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  • Isn't this just fooling the meter into showing a reading that doesn't reflect the true energy utilization.

  • When there is a flow of electricity, there is a spinning vortex of "Zero-Point" energy around it which condenses into magnetic flux. When there is a flow of magnetic flux, there is a spinning vortex of Zero-Point energy around it which condenses into electricity. If you allow that electricity to flow you allow Zero-Point energy to oppose the energy you are putting into the flow by flowing in the opposite direction, against the flow.. unless you reverse it, in which case you tap Zero Point energy

  • where do the 4 leads from the secondary coils go? are they both combined and connected to diodes for power out?

  • What would be some potential applications, considering the manufacturing costs and potential max output? Bottom line is always cost efficiency. If it cost x to produce, I must be able to sell it at y and the consumer must be able to ultilize it to improve their costs z.

  • Where does the "excess power" go? If it stays in the system and continues to build, it would burn out pretty quickly, no?

    BTW, if there's really 100+ volts in the system, I'd never touch varnish coated wire with my bare (sweaty) hands.

  • Just curious if this in any way relates to Leedskalin's device?

  • also loading changes reluctance path from the low to hi conduit ....

  • very interesting .... commercial potential .... not medical

  • Even though, the outer path do probably have less resistance or opposition for the sec coils than the primary's path, as the inducing field from the primary has to be powerful. This should mean free energy aka "overunity", but with a restriction as you go into higher currents output.

  • being put into the device. Can a device, if configured correctly, have a greater measurable output than the measurable input? Yes, by pulling more energy from another source. That is how devices like this truly do not violate any laws of physics. It receives it's extra energy from the atmosphere around it, therefor it still has a greater input that output by physics laws, but it doesn't require you personally to provide all of the input energy.

  • If this does what you claim, it will allow you to run a motor using its own output with a surplus.

    If it cannot, it is worthless gobbledygook words.

  • stop measuring - just let it run itself, if you could do that at least some people would listen (other people would call it perpetum mobile not understanding the energy is not produced, it of course comes from somewhere, but that's hard to explain) very simply these things are just an 'antenna' that has to vibrate and resonate with a special frequency to work

  • a ?-UNIVERSITY-? involved with this ?

    this is a closed system - it *cannot* generate additional power !!!!!

  • This is simply an error in the method of measurement.

    IF this transformer had a 377% effency then he would simply have to take the output from the resistor, feed it into the input, then disconnect the outside power.

    At that point the transformer would make energy on its own & also have excess energy output which could be tapped.

    If he tried this experiment his theory would go up in a puff of logic.

    May I ask what input frequency this is operating at?

  • @Texmurphy51: please see my comments below or others, there is no need to even imagine self-running. This demo is just plain underunity, no excess energy. Nevertheless, the magnetic geometry and coil could be tuned to generate excess energy but obviously, the author does not know basics of real power metering in order to properly measure COP factor !

  • The distance between the over-unity transformer and the measuring equipment is to short. The over-unity transformer creates a strong magnetical field which fools around with the results. The distance between the transformer and the equipment must at least 1 meter. Then start over the experiment.

  • why you did not respond any question here?

  • Can you SHOW us the Input current/voltage of the first coil

    then the output current/voltage of BOTH coils. If it is free energy the Power in the output should be higher than the power in the input. Hmm.....

  • @f5inter I totally agree with this request, let's see if Thane accept to do it !

    One question for you: the primary V & I will show reactive power fed into the system and similarly, the secondary V & I will show reactive power produced by the system output. Since we're dealing with nonlinear or polyphasic reactive power (non pure sinusoidal), what reactive power definition do you suggest in order to compute if there is an anomalous reactive power self-amplification ?

  • If this is OU, can use one secondary as feedback and the other for load? Proving that the aparatus can be used as a perpetual batery!!

  • The explanation is good, but... are you serious. This really works as overunity device?

  • Outstanding. Very well explained. Even I understand it lol

  • I realy like your invetion mate... lets we develop it..

  • Can you do that with a purely inductive load?

  • So lets see a scope picture of the secondary current and secondary voltage at the same time with the primary voltage and primary current. Just because the load is purely resistive doesn't mean the secondary current is in phase. This experiment is not very scientific.

  • @kufman01 obviously you know nothing of electricity. NEXT !

  • @fgleich On the contrary, kufman01 is spot on. It's an inductive load with the power factor of 0.7, thus you'll have to use calculations accordingly. Read a bit about power factor on wikipedia before you cluelessly flame people.

  • @selfonlypath Did U replicate exectly like he did? if not, u should not make a comment basis on what u know, u just don't know the trick get involved

    Cost a years, lot time, money to make one show exectly what to do,

    whay is ur contribution???

    ur comment waste my time and others, keep for urself..

  • This is sooooo cool! Why does he not have a patent for this?

  • Great explanation and diagrams! I understood everything with the first viewing! Awesome transformer!

  • As you might know from my channel, i've a Ph.D. & electronics engineer explaining my previous analysis that you do not get overunity for the moment with your setup.

    I'm also a yogi, healer explaining why I experience pyschokinesis effect near ZPE devices so I also confirm that upon telepathically scanning your video, it does not produce scalar waves required to shift overunity.

    About the 4 holes topology which is correct, I suggest your for transverter approach of my friend Hector Torres.

  • @selfonlypath Did U replicate exectly like he did? if not, u should not make a comment basis on what u know, u just don't know the trick get involved

    Cost a years, lot time, money to make one show exectly what to do,

    whay is ur contribution???

    ur comment waste my time and others, keep for urself..

  • @selfonlypath i did not detect, telepathically, as well, any scalar waves in the overunity process here.

  • To measure COP of any ZPE devices is really tricky and can never be done with standard multimeter but requires special devices or digital signal processing techniques.

    The physical topology of your ferro-resonant ZPE reactor is correct but as shown in your video, it is not producing overunity. You need to tune via special PWM frequency pulsing and voltage saturation in order to bring ferro-resonance.

  • I think you have a problem measuring input power with enough accuracy. Measuring 3mA AC current with a 3-3/4 meter on 4A range is ridiculous - tolerance for most meters falls in rango of +/- 3-5 counts, meaning it could be 0 to 7mA of current.

    More on the topic - no matter how you fold the flux, it'll find a way to balance itself out. No overunity here, or ever.

  • What a messy experiment

  • So you claim overunity but where? How do you know the BEMF is flowing down the path away from the primary? So if it is overunity then things will continue to run as a closed circuit whey you remove the source.  Not possible!

  • OK Cool but what is the gauge wire and how many windings

  • Thanks Thane..we're getting there!

    (OK, you're getting there, but you know what i mean)

    You have the patent, are you now planning manufacturing and marketing?

  • You say that the output power equals 403.3mW and that the voltage across the secondary windings equals 3.3V but nowhere in the video do you measure the current through the secondary windings. If You Are truly producing 403.3mW output power compared to 106.9mW input power then you should be able to measure 112.21mA through the secondary windings.

    Please demonstrate this measurement of 112.21mA through the secondary windings.

  • Your load resistor is wire wound and it has inductance replaced it with carbon resistors or metal film resistors and repeat your test.

  • super genius! want one of those

  • Brilliant!

  • He said that it acts as a magnetic diode... I want if that in itself could be apply to making a purely magnetic motor?

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