Laplace Transform: First Shifting Theorem

[fakhrealam1]

Thank u so much :)

[iamcanadian1919]

every university professor could learn a thing or two from you. keep up the informative videos, they are awesome! one suggestion, leave the video on the final solution for a bit so we can pause it and look over the solution. great stuff, thanks!

[iamcanadian1919]

and this is why i don't need to go to classes. +1 thanks for helping me through engineering! xD

[MFKing007]

thanks

[Raptured71]

It's a sad world when I learn more from Youtube than attending a 60 minute lecture at my university.

[TheFlam3head]

Wow I learned more in 8 Minutes than my entire 3 hour lecture at school. I should send this to my professor. Maybe he'll learn a thing or 2. 

[legolaswei0317]

thank u for ur helpful videos

[persianastic]

Chris your the man!

[Fazare91]

great!

[shiven10]

Certain lecturers in Melbourne could learn from you in how to explain such functions.

[sudaratniam]

Thank you, I want to understand about laplace function now.



[ypz615]

awesome!!

[yumchalife1]

Very useful!..Thanks so much!...

[Ken900625]

yayyy thx!

[lanodom]

You sound like the boss on Flight of the Concords

[zebizaza]

you really helped me out!!! thank you very much! waiting for watch more of your videos!

[isam1335]

THAAANKKKK YYYOOOUUU SIR ! = )

[JurassicPlank]

Chris rocks!

[lamblamblike]

very useful!!!!!

[zeeshannomali]

thankx sir nice lecture

watching in pakistan

[ronalddlelariarte]

why did you use 3 in the a in the s/(s^2 + a^2)? i thought you will use 2 as the substitute in the a?

[AA10Megaviv]

@ronalddlelariarte The reason he used 3 in the expression you've mentioned is it's the coefficient of t in the transformed expression cos(3*t), and the parameter a as defined in the expression you've mentioned absolutely shouldn't and doesn't refer to the parameter a defined in the video, so the use of 3 as the parameter a in that expression doesn't contradict with the use (shown in the video) of 2 as the parameter a in the Laplace Transform shifting power, e^(a*t).

[minhajk21]

Suscribed! Thank you so much!

[HumanTargetAus]

Thanks for the Video! good to see Aussies making great videos.

I am currently studying at UQ and this helps alot!

[RoguePlank]

very helpful- just about to do a little test on Laplace that counts for a massive 2% of my degree, this helped straighten things out alot (my maths professor is Russian, very thick accent) thanks again.

[0861246038]

You actually are a HERO!!! spent forever looking for examples but nothing compares to your explanation...also i feel like an idiot for not being to figure that out myself!

[shadowC10ne]

Like always, a great video. You really explain things good, dr. Tisdell!

[jsm666]

Dear Dr Tisdell; can you please give me the titles of a couple of texts I could get hold of in order to follow this up in my own time? (I am not a UNSW student)

[skang89]

thanks sir for such a detail explanation.......i wish my all lecture able to teach like you for my Engineering Mathematics 1 until 4........double thumb up sir......

[Tyskviking76]

sehr gut erklärt!

danke sehr :)

[Balzacrose]

your a saviour from across the world!!!! could you maybe do inverse laplace problems for the same topics? could be useful, cause thats where i get lost!!thanks otherwise tho..much love!

[ademir7]

thank you very much

[eflanny]

thank you! you're a great teacher :)

[refugee786]

But apparently cannot spell humiliate.. ironic haha!!

[refugee786]

Your explanations and general enthusiasm completely humuliate any lecturer I have come across so far in England; and I attend a top University (Imperial College London). Thankyou so much

[icf9530]

Dr. CHRIS ... YOU ARE A BAMF !

[jcmackey72]

Thank You for posting this video. It was very helpful.

[bittertrooth]

THANK YOU SOOO MUCH... i'm having a presentation tomorrow and now im confident enough to present myself infront of class thanks to u

[mina19o]

Thank you, that was veryyyyyyyyyyy useful!!!

[DrChrisTisdell]

You're welcome!

[busterwolf123]

hi chris, i was having a bit of problem with this question:

F(s)=(4S+1)/(S^2+6s+5),use 1st shift theorem to do it. i can solve it by using partial fraction, but can't seem to apply 1st shift theorem to it, can u pls point me in the right direction. the best i can get for the bottom line is:(S+3)^2+3^2-3, so "a" can be equal to 3, but after that...i dunno where to go...this is actually 1 of my assignment's question :)

[CODclimber]

@mina19o true that!

[MacGruberFan]

God bless you for posting these videos! You're helping people all over the world. I'm watching these in Minneapolis, Minnesota. Thanks again for your generosity. I hope I can also share knowledge with others in this way someday.

[DrChrisTisdell]

I encourage you to do so - it's very rewarding!

[1carlento]

thank you very much for posting this clip

[DrChrisTisdell]

You're welcome!

[RezanOth]

A big thank to you Dr. Chris!! this helped me much!

[DrChrisTisdell]

Good luck with your studies.

[boydekus]

Thankyou

[DrChrisTisdell]

You're welcome.

[electriciansmate]

I hope I haven't upset any of your students. I wish them the best of luck.

[DrChrisTisdell]

Hey - no worries - as us Aussies say!

[electriciansmate]

You made that look more complicated than it should of.

[DrChrisTisdell]

Hi Neil! If I understand you correctly, then I think you're saying that a better solution method would be to substitute $e^{2x} \cos 3x$ straight into the integral and then do some algebra on the exponents to show that $F(s-2)$ is required? If so, then that would suffice! Thanks for commenting.