Added: 2 years ago
From: freelanceteach
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  • His favorite song: "My ARROWS don't lie".

  • at 5:00 why cant the iodide anion act as a base and attack the beta hydrogen, why does water have to take the hydrogen, cant the iodide act as a base??

  • @lk98765 i think they both can bu maybe the water is a better base?

  • In the first problems shouldnt the products be h2o and hi because i has a negative charge and h30 and a positive charge and you cant leave it like that

  • @risingroad1 No, it should be H3O+ and I-. The iodide ion leaves the substrate for the creation of the carbocation. The O atom of the water solvent bonds to the carbocation. This makes O positive because of the electron configuration. To make it a neutral compound, you need to get rid of a H+, and the way to do that is to use another water molecule by means of solvolysis, making an alcohol and the hydronium ion (H3O+), which is found in acidic solutions.

  • the br shouldn't bond with the proton since it will make a strong acid it should be the solvent (water)

  • @chung05 was just going to say that. in his guide it shows Br is not a base and therefore cannot pull the H+ away, that would the be the O in the H2O that does the pulling off

  • These videos are great thank you so much!!!! My only suggestion is that you might have some really difficult ones at the end because although these are really helpful when first learning, most O-chem tests have way harder questions with multiple products and confirmations/configurations involved

  • Dehar, since it's a Sn1 rxn the nucleophile doesn't mater; it's not part of the reaction rate. Just focus that it's a tertiary alkyl halide and therefore Sn1 occurs.

  • water is a poor nucleophile, how did elimination happen?

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