at 5:00 why cant the iodide anion act as a base and attack the beta hydrogen, why does water have to take the hydrogen, cant the iodide act as a base??
In the first problems shouldnt the products be h2o and hi because i has a negative charge and h30 and a positive charge and you cant leave it like that
@risingroad1 No, it should be H3O+ and I-. The iodide ion leaves the substrate for the creation of the carbocation. The O atom of the water solvent bonds to the carbocation. This makes O positive because of the electron configuration. To make it a neutral compound, you need to get rid of a H+, and the way to do that is to use another water molecule by means of solvolysis, making an alcohol and the hydronium ion (H3O+), which is found in acidic solutions.
@chung05 was just going to say that. in his guide it shows Br is not a base and therefore cannot pull the H+ away, that would the be the O in the H2O that does the pulling off
These videos are great thank you so much!!!! My only suggestion is that you might have some really difficult ones at the end because although these are really helpful when first learning, most O-chem tests have way harder questions with multiple products and confirmations/configurations involved
Dehar, since it's a Sn1 rxn the nucleophile doesn't mater; it's not part of the reaction rate. Just focus that it's a tertiary alkyl halide and therefore Sn1 occurs.
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herojha 4 months ago in playlist Organic chemistry: SN2, SN1, E2, and E1 reactions
at 5:00 why cant the iodide anion act as a base and attack the beta hydrogen, why does water have to take the hydrogen, cant the iodide act as a base??
lk98765 1 year ago
@lk98765 i think they both can bu maybe the water is a better base?
bungerman1000 9 months ago
In the first problems shouldnt the products be h2o and hi because i has a negative charge and h30 and a positive charge and you cant leave it like that
risingroad1 1 year ago
@risingroad1 No, it should be H3O+ and I-. The iodide ion leaves the substrate for the creation of the carbocation. The O atom of the water solvent bonds to the carbocation. This makes O positive because of the electron configuration. To make it a neutral compound, you need to get rid of a H+, and the way to do that is to use another water molecule by means of solvolysis, making an alcohol and the hydronium ion (H3O+), which is found in acidic solutions.
TetsuRoku 1 year ago
the br shouldn't bond with the proton since it will make a strong acid it should be the solvent (water)
chung05 1 year ago 2
@chung05 was just going to say that. in his guide it shows Br is not a base and therefore cannot pull the H+ away, that would the be the O in the H2O that does the pulling off
h2okaz 1 month ago
These videos are great thank you so much!!!! My only suggestion is that you might have some really difficult ones at the end because although these are really helpful when first learning, most O-chem tests have way harder questions with multiple products and confirmations/configurations involved
theshtgoose 2 years ago 24
Dehar, since it's a Sn1 rxn the nucleophile doesn't mater; it's not part of the reaction rate. Just focus that it's a tertiary alkyl halide and therefore Sn1 occurs.
chinosister 2 years ago
water is a poor nucleophile, how did elimination happen?
Dehar 2 years ago