Added: 2 years ago
From: cgcclive
Views: 11,675
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  • awesome work

    

  • thank you good sir,

  • this really help better than my professor

  • hey for rule 11, where did the A.notA come from on the forth line?? pls explain

  • rule no. 11 is the only one i didnt understand """

  • your method of knowing the rules is so fu$ing awesome prof!!! I don't have to memorize this nor adding a stupid paper on the wall to force me not to forget them.

  • How about a'a'?

  • junge junge du hast mir in 3 part das beigebracht was mein lehrer nicht mal in einem halben jahr bei bringen konnte ^^ hut ab

    jetzt kann ich entspannt in den test gehen thank you very much man i like you

  • Thanks from Freeport, IL./Madison, WI. I've been having a hard time wrapping my head around Boolean Algebra, and I have a test on it next week. Your video of the lesson is helping. The book I'm using is "Digital Fundamentals" (10th edition) by Floyd, and I've been re-reading it over, and over again. I'm not sure which book you teach from, but it's easy to follow along in the book from your videos. Thanks.

  • I didn't really get number 11. but that's ok, thanks SO much man!

  • you lost me a little with the second not A at 8:20 where did that come from?

  • DUDE!!! Thx from the Netherlands :D

  • @kamran14march

    It's: A+A'B

    NOT: B(A'+A)

    Those are not the same thing. The parenthesis makes the problem completely different.

  • @joeldoyle I think what he was trying to say is that the line of the 11 proof with A+A*B+A*'B, it could be simplified to A+B*(A+A')=A+B*(1)=A+B, and got confused somewhere along the way. Doing it that way would have been better, I would think.

  • Why are you making the rule 11 proof so long just take B as common term from

    BA' + AB => B(A'+A) => BA = > AB

  • @kamran14march you cant do that. B(A'+A) = B(1) since (A+A')=1

  • Thanks for this!:)

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