Hey Midnight tutor, not to rain on your parade, but I did not find this that challenging. With a little inspection of all of the exponential terms, you can re-write the exp(2x) as [ exp(x) ]^2. Now making a change of variable letting v=exp(x) we arrive at the integral of 5v^(2)+4v / (v^2+v-2). Looking back at what exp(x) equals, which is v, you can substitute that in for your dv. Now giving, integral of (5v^(2)+4v) / (v^2+v-2)v. Using partial fractions gives: A/(v-1) + B/(v+2) + C/(v).
Your approach works, but I think it's far easier to use partial fractions right off the bat. Letting u = e^x, you get : (5u + 4)/[(u+2)(u-1)]. Which is then 2/(u+2) + 3/(u-1).after doing partial fractions. Just my opinion. Also, as people have said, this way you avoid that pesky negative.
easy to say "in enough time you will get the answer" but what about on an AP test you dont have that luxury of time to be spending 10mins to a problem, just pointing that out
@Shweet7248 well actually, that is because the problem is not done yet, mr. Midnighttutor might have overlooked the "4ln(u)+C" @3:10. at the final part @11:18 he mentions that. you should have listened.
This guy looks like he could kill 30 terrorists with a butterknife and he's solving partial fraction integrals. That basically makes him the batman of math.
@eatadick1 What the hell is wrong with your name. I bet you wish you didnt make that your name, cause now your stuck with it, and as you grow older, you mature and you relize how stupid you are.
the problem was great BUT........A AND B HAVE to be negative...your result gives us a POSITIVE 3w...and we all know adding two positive integers yield a positive answer for all real numbers...but that serves no relevance to this problem, because the numerator is negative.
He pulled the negative out to solve the partial fraction. It is a legal move to do that. He didn't show the final answer so I'd assume he would cloister the negative back in. He was just making the problem simpler.
yeah Ok...everyone has a different way of doing it....I honestly don't care...I hate when folks sit there and bother to reply to me....I've already made my As in Calc 1, 2, 3, and 4....here at Georgia Tech....I really don't care anymore = )
If you didn't care, why did you "sit there and bother to reply" Your writing misinformation, thats why we replied. kids are watching this video trying to get help in math and your feeding bunk info, so don't get butt hurt when someone corrects you.
God, this is so confusing. Boy came to the teacher and wrote a math problem in the board saying teacherr, I got a problem. Teacher said what is your problem. He said pointing the board that. Then teacher said problem is always a problem of another problem, which is how math works. Therefore he erased the whole problem on the board and asked that solved a your problem? It was problem because it is in the board. :)
I don't think too many truckers bother themselves with calculus. As for the equation, I would have reversed integrated the partially derived field log(n) with an R set of Lorentz bananas, and then took up a different hobby.
this NERD stuff is what makes your car run...or allows you to drive your car over a bridge...or even allow you to get on the internet so you stfu now = )
jajaja he talks funny xP I like the video
mariaisgorgeous16 2 months ago
blood sweat and tears!!!!ARGGHHH this guy will snap at you lol
psychoticstreetpoets 4 months ago
This has been flagged as spam show
Hey Midnight tutor, not to rain on your parade, but I did not find this that challenging. With a little inspection of all of the exponential terms, you can re-write the exp(2x) as [ exp(x) ]^2. Now making a change of variable letting v=exp(x) we arrive at the integral of 5v^(2)+4v / (v^2+v-2). Looking back at what exp(x) equals, which is v, you can substitute that in for your dv. Now giving, integral of (5v^(2)+4v) / (v^2+v-2)v. Using partial fractions gives: A/(v-1) + B/(v+2) + C/(v).
trese0000 8 months ago
Comment removed
trese0000 8 months ago
thanks Mr. Muscle man it helps me on my indefinite integral problem
charicepempengco26 1 year ago
3 log(exp(x) - 1) + 2 log(exp(x) + 2)
moveaxebx 1 year ago
Your approach works, but I think it's far easier to use partial fractions right off the bat. Letting u = e^x, you get : (5u + 4)/[(u+2)(u-1)]. Which is then 2/(u+2) + 3/(u-1).after doing partial fractions. Just my opinion. Also, as people have said, this way you avoid that pesky negative.
dethwing 1 year ago
at around 9 minutes, when you break up the integral into partial fractions, i think you forgot the negative on the 3wdw.
itsmancini 2 years ago
very creative solution. I just need to ask, do you have a dip in? If so, thats baller.
itsmancini 2 years ago
easy to say "in enough time you will get the answer" but what about on an AP test you dont have that luxury of time to be spending 10mins to a problem, just pointing that out
Brain704 2 years ago
I typed this integral problem into WolframAlpha and it gave a different answer
Shweet7248 2 years ago
i suggest you watch the videos on wolfram alpha in that case too. thank you for not subscribing
midnighttutor 2 years ago
@midnighttutor LMAO
trese0000 8 months ago
I wasn't looking to offend you midnight, I was just concerned that the answer might be wrong
Shweet7248 2 years ago
@Shweet7248 well actually, that is because the problem is not done yet, mr. Midnighttutor might have overlooked the "4ln(u)+C" @3:10. at the final part @11:18 he mentions that. you should have listened.
hvhfyjtdhf 8 months ago
@hvhfyjtdhf ya sure i didnt, i was in the wrong. but 'thank you for not subscribing' i was honestly just trying to help..
Shweet7248 7 months ago
oh! calculas!my gad
khalid97899789 2 years ago
truly a batman of math hahaha, thanks alot , i encountered a problem nearly similar to this, and my skull cracks for about 20 mins.
pathfinder0009 3 years ago
This guy looks like he could kill 30 terrorists with a butterknife and he's solving partial fraction integrals. That basically makes him the batman of math.
eatadick1 3 years ago 27
rofl i thought the same thing...just not as creatively.
MPV839 3 years ago
so true...
whoombat 3 years ago
LMAO!
ShadowKila39 2 years ago
@eatadick1 What the hell is wrong with your name. I bet you wish you didnt make that your name, cause now your stuck with it, and as you grow older, you mature and you relize how stupid you are.
michael102387 1 year ago 2
its drblueeyes and trying to touch base. call me
drblueeyes3003 3 years ago
the problem was great BUT........A AND B HAVE to be negative...your result gives us a POSITIVE 3w...and we all know adding two positive integers yield a positive answer for all real numbers...but that serves no relevance to this problem, because the numerator is negative.
haril007 4 years ago
He pulled the negative out to solve the partial fraction. It is a legal move to do that. He didn't show the final answer so I'd assume he would cloister the negative back in. He was just making the problem simpler.
Entertainmentwf 3 years ago
you cannot assume in mathetmatics...I made my comment strictly from what is shown...you are going off of assumptions ; )
haril007 3 years ago
No he pulled the negative out. Theres no assumption, its in the video
dukemallan 3 years ago
yeah Ok...everyone has a different way of doing it....I honestly don't care...I hate when folks sit there and bother to reply to me....I've already made my As in Calc 1, 2, 3, and 4....here at Georgia Tech....I really don't care anymore = )
haril007 3 years ago
If you didn't care, why did you "sit there and bother to reply" Your writing misinformation, thats why we replied. kids are watching this video trying to get help in math and your feeding bunk info, so don't get butt hurt when someone corrects you.
dukemallan 3 years ago
CORRECT me!? LOOOOOOOOL this guy takes a short cut out of no where, and I point out a flaw in it....big whoop by do you give a shit!?
haril007 3 years ago
theres no flaw. Its a pretty basic step
dukemallan 3 years ago
ok...and exactly what do YOU do? go around correcting folks on youtube? get a life...I found a flaw...my opinion
haril007 3 years ago
God, this is so confusing. Boy came to the teacher and wrote a math problem in the board saying teacherr, I got a problem. Teacher said what is your problem. He said pointing the board that. Then teacher said problem is always a problem of another problem, which is how math works. Therefore he erased the whole problem on the board and asked that solved a your problem? It was problem because it is in the board. :)
TinTin7777777 4 years ago
Shouldn't du/dx = 2e^(2x-1) + e^x ???
CPBach 4 years ago
derivative of e^x is e^x. It's essentially the chain rule. e^(2x) times the derivative of the exponent which is 2.
du/dx = 2e^(2x) + e^x
e^x doesn't behave like the power rule. It behaves like the chain rule.
Entertainmentwf 3 years ago
You're an awesome teacher
andrewwarmen 4 years ago
I don't think too many truckers bother themselves with calculus. As for the equation, I would have reversed integrated the partially derived field log(n) with an R set of Lorentz bananas, and then took up a different hobby.
noeatingallowed 4 years ago
better to do partial fractions from the beginning
miviamx 4 years ago
you're hot. call me now dude!
bkjoelover 4 years ago
freaking nerd stuff
fabvon 4 years ago
there was a pretty long assssssss pause at 3:55, LAWL>
bkjoelover 4 years ago
this NERD stuff is what makes your car run...or allows you to drive your car over a bridge...or even allow you to get on the internet so you stfu now = )
haril007 3 years ago
Nice work!! the - sign detail is not important. He es teaching the solving method.
nahuelito2007 4 years ago
isnt the power of the numerator the same as the denomintor? can't you rewrite the integral by long division.
Aloosh12 4 years ago
indeed.. its sad he made a mistake this is a really difficult one nice job anyways and thanks for the colors and everything :P
hecatonchiress 4 years ago 2
-2ln|e^x+2|-ln|e^x-1|+4ln|e^2x +e^x-2|+C.....is the answer yall
julyfogfrog 4 years ago
u can always complete a square of d denominator instead of partial fraction
zaith88 4 years ago
very nice work, i liked the use of all the colors, that made it really easy to see what was going on.
theid 5 years ago
Double check your work on your partial fractions @ time 10 minutes -- you lost a negative sign on the 3 in the integral (upper left).
This should be the correct answer:
3ln(|(e^x)-1|) + 2ln(|(e^x)+2|) + C
(Check by differentiation.)
pyrosarco 5 years ago 7
Excellent job! You people are fantastic!!!
guest12344 5 years ago
Thank you soo much for making that very understandable, it really helped me solve problems just like that so thx again :)
Giridorn 5 years ago
I wish I had this professor when I was studying calculus.
DiegoHCantor 5 years ago
you rock!!!
zanza17 5 years ago
He's wrong!
pyrosarco 5 years ago