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From: MIT
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  • Good, I like that you share this video Orthogonal Vectors and Subspaces., I wish success always

  • Nice Video Orthogonal Vectors and Subspaces That You Share , So Very Nice Thanks You

  • I Really Like The Video From Your Orthogonal Vectors and Subspaces

  • Your Video Orthogonal Vectors and Subspaces Is Very Useful Sharing

  • Wouldn't the z-axis be orthogonal to the entire x-y plane? It kind of goes against one of his remarks in the 20-21 minute part of the video.

  • mmh ich bin blond

  • I am learning many lessons from this videos.

  • thanks professor

  • tanks sir...

  • thanks professor gilbert

  • I also love this series of lectures, but in this lecture I find that he does not explain perpendicular subspaces enough. The example with the blackboard and the floor is just confusing (to me and my colleagues at least), because obviously they form a right angle and thus are perpendicular. And obviously they are both subspaces. Which leads me to believe that the definition is wrong, which I'm sure it isn't.

  • @pelemanov Not all the vectors in these two subspaces are perpendicular. Say vectors in the line of their intersection. So it violates the definition. (In fact there could not be two orthogonal plane in R^3.) I think this is exactly his purpose of picking the wall and the floor to remind us this subtlety: What we think is perpendicular is not orthogonal by definition.

  • @j4ckjs Thanks for the reply. It's just a confusing definition and if you google a bit on orthogonality, you find many other definitions contradicting this one. I think he should have pointed it out more clearly, but at least now I will be cautious when it comes to this topic. I guess that's good enough...

  • r like Gama(Γ)

  • Look at the students, now back to Strang, now back at the students, now back to Strang.

    Sadly, he's teaching an empty class.

    But if he records this video and puts it online, he could still teach.

  • Gilbert Strang is my hero.

  • when finding an orthogonal vector, are there specific steps to find it, or do we have to find a vector (through inspection) which when multiplied by another vector through dot product is zero?

  • Like every lecture of Mr. Strang this was not the exception

  • I swear, these lectures with the Schaum's Outline of Linear Algebra can really help anyone learn the subject.

  • Really good videos!! This series are helping me pretty much!! I'm from Brazil and I'm loving this videos!!

  • Like it.

    AX=b for the over determined system starts from this video.

  • wow in 49 minutes he's layed out the big picture and gotten down to all the information! he is such a coherent lecturer omg! i love u prof strang!!!!!!!!!!!

  • This series is phenomenal. Every lecture a gem. Thank you Mr Strang!

  • did you hear someone in the class burp loudly about two minutes before the end? How gross!

  • About 48:48 exactly. Bloody MIT students don't appreciate Mathematics!

  • what are you talking about a cough?

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