Hey dude, if you think this is overunity put your meter over a florescent lamp socket and then try to figure out why it doesn't give you the proper voltage reading.
Whatever you are doing there it is oscillating at about 800 Hz.
Your measurements have to be wrong. Look at it from an energy perspective. 9 amps times 12 volts is 108 watts. Something has to be getting really hot damn fast to dissipate 108 watts of power. I don't get a sense in the clip that there are 108 watts of continuous power cooking up a storm of heat. I don't even see a load.
I will correct my mistake, you say that 9 amps are going into the secondary battery which is at 12 volts. Well, then R = V/I, which gives you 12/9 = 1.33 ohms.
Replace the second battery with a 1.33 ohm resistor and measure the voltage. You will see that it is very very low. That will prove that your preliminary conclusion is incorrect.
As you know your output power is the volts times the amps. Is it AC or DC? I will guess that it is AC at around 800 Hz.
Your multimeter cannot read AC current at 800 Hz and is giving you the wrong measurement. Multimeters have limits on what they can measure. They are not designed to work with pulse circuits at all and give wildly inaccurate readings.
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hungarylnnjsd 1 year ago
it's just an inductive spike from the relay coil - it's a good way to fry a multimeter.
camhax 2 years ago
Hey dude, if you think this is overunity put your meter over a florescent lamp socket and then try to figure out why it doesn't give you the proper voltage reading.
electra 2 years ago
Use a 50 Watts 12 Volts bulb instead of the ampmeter to see, if you really have 9 Amps flowing there.
Many thanks.
Regards, Stefan.
overunitydotcom 2 years ago
Grea video,
You might on something wonderful.
Keeping up the work, clear show this is a OU device, 5 stars !
fdoca 2 years ago
ever fry a multimeter like that relays ar enot friendly to multimeters they end up expensive coasters found out the hard way
prototype9000 2 years ago
Whatever you are doing there it is oscillating at about 800 Hz.
Your measurements have to be wrong. Look at it from an energy perspective. 9 amps times 12 volts is 108 watts. Something has to be getting really hot damn fast to dissipate 108 watts of power. I don't get a sense in the clip that there are 108 watts of continuous power cooking up a storm of heat. I don't even see a load.
Drevtoobe 3 years ago
I will correct my mistake, you say that 9 amps are going into the secondary battery which is at 12 volts. Well, then R = V/I, which gives you 12/9 = 1.33 ohms.
Replace the second battery with a 1.33 ohm resistor and measure the voltage. You will see that it is very very low. That will prove that your preliminary conclusion is incorrect.
Drevtoobe 3 years ago
I said meter shows 9 Amps, with bulb load its not glowing much.
capacitor70 3 years ago
As you know your output power is the volts times the amps. Is it AC or DC? I will guess that it is AC at around 800 Hz.
Your multimeter cannot read AC current at 800 Hz and is giving you the wrong measurement. Multimeters have limits on what they can measure. They are not designed to work with pulse circuits at all and give wildly inaccurate readings.
Drevtoobe 3 years ago
It must be AC becouse Relay coil is oscillating.
capacitor70 3 years ago
5. Some times meter hangs.
6. Put magnets near oscilating contact.
7. It gives huge electrical shock at battery terminal.
8. I dont have Scope please check it on scope.
capacitor70 3 years ago
what was your load to get the 9.0 amps.
crob227 3 years ago
It same as bedini motor, Primary Battery discharging at 0.02Amps and Secondery battery charging at 9.0Amps both batteries have same rating 12V.
After interchaning meters it gives me same result. but when i have connected bulb it does not glow bright.
Connection details:
1. Relay Common terminal goes to first coil terminal.
2. Second coil terminal to GND.
3. Relay NC(normally connected to +ve).
This way relay strats oscillations.
4. take back emf from coil to second battery through diode
capacitor70 3 years ago