Added: 2 years ago
From: freelanceteach
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  • thank you so much :D

  • In the last reaction with the Sn1 and the E1, which product is the major one? Is it SN1?

  • @ditzychinchilla yes, Sn1 is the major almost always under normal conditions

  • You are doing an enormous service to society. I don't believe in god, but I will use the expression "God bless you" anyways. Thank you SO much. Been watching your lectures for two semesters now.

  • lifesaver

  • LOL @ background noise. YA YA YA YA YA YA YA 0:41

  • suprise!!!! HAHAHAHAHA this guy is the greatest.

  • How freakin cool are you? Thanks, you help so much because our Professor is so hard to understand.

  • You seriously just saved my life!

  • Comment removed

  • Masterful!

  • I just want to say again that you are the man and I am goin to send some money your way when Im back on the up. You're vids saved me hours of studying on my own.

  • Your videos and worksheets are so helpful! Thank you.

    We have H-Br as a product for the Sn1 rxn. Why is it that the Br- doesn't take a hydrogen from H3O+ in the E1 rxn to balance the charges?

  • IF you show both of the ions then the charges are balanced, it doesn't really matter.

  • @jenandroid

    Because the hydrogen will attach to the original nucleophile. Also, he said that HBr is a strong acid and it would want to be deprotonated anyway :)

  • @HsureWhyNot I was wondering about that, thanks!

  • @jenandroid I'm not positive, but if I remember correctly H30 and Br- is the same thing as HBr and H2O since they are in equilibrium

  • @jenandroid It's because HBr is a strong acid so it wants to LOOSE it's hydrogen (proton). So in nature it is more common for HBr to form Br- rather then Br- to form HBr by gaining a hydrogen, the latter just won't occur in nature. Just remember a strong acid always wants to loose it's hydrogen.

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