Added: 3 years ago
From: patrickJMT
Views: 27,638
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  • Hey man, how can you easily tell whether the function you are working with must be integrated with respect to y axis or x axis?

  • @dragonmasta91 in general, it depends on if the equations are of the form y = ... or x = ...

  • Holy mother of god....thank you! I thought YouTube would be useless for all my science courses but I am getting it thanks to videos like this!

  • @dudemburg come back any time, lots of good stuff on youtube!

  • IB diploma SL mock exam tomorrow(senior year)- this is a part of the syllabus and explained but not in detail such as your 2 videos; thanks!

  • THANKS A LOT! I HAVE MY FINAL TEST COMING TOMORROW, YOUR VIDS REALLY HELP A LOT!!!

  • Big exam on Monday . . .this helped loads. Thanks :)

  • sir patrick , we can apply the ( right minus left ) only when we are integrating with respect to y ! or we can do that also with respect to x ! cuz i tried to apply this rule on one of the problem with respect to x which involve (two curves that Cross)but i couldn't get the right answer !

  • Comment removed

  • you have no idea how much this helped me, I really appreciate it.

  • @sam1209 the reasoning behind the subtracting right and left or top minus bottom is because we are finding area and area is always positive. I hope I am right by saying that.

  • Thank you man! Thank you! your a savior!

  • I go to calc 2 to hear what the subject is and than I come on here and learn the material. Thanks so much for your time and effort you put into these videos, it really does help so much.

  • What do you do if the two curves don't intercept at one point? Like..one of the two interceptions intercepts at different points on the x-axis.

  • Man, I "learned" this stuff years ago, but I'm reviewing it now, and of course there are holes... so here's a dumb question...

    Is 8/5 the area between the two curves, or is it the "signed" area? I see that the shape formed by the curves is partly to the left of the y-axis, and partly to the right. So when we integrate and get 8/5, is that the area of the whole shape, or is it the area of the right side minus the area of the left side?

  • @minusjason

    It's the area between the two curves if I can recall.

  • hi patrick I have a question, how do you know which function to subtract from another ?

  • @sam1209 top minus bottom or right minus left

  • i have a question: we make the anti derivative for the given function F(x) of the curve (C), or for the equations as you did???

    i`m confused.....help me if u plz

  • You are my hero! This is exactly what I need to know for my quiz tomorrow. Thank you so much!

  • with your help i got a B+ in my calc 1 class in my summer course thank, still followin up in calc 2

  • @moeaoude03 this time: A+!! : )

  • thank you very much i understand it so much better now :D

  • I meant at time 1:18 sorry

  • @patrickJMT Your a time saver man thanks i took calculus one 2 years ago but know i found out i have to take calculus 2 now so i forgot a lot of things im just remembering integrations. I forgot why or how we do the step that starts with at :18 where you added an extra y to all of the variables like from y^4 to y^5.

  • i like watching stuff like this, i just wish i understood whyy it works.

  • You explain concepts in a few minutes, that take my calc professor an entire hour, and you do it better. Bravo

  • thanx dude, why can't all teachers explain these material thoroughly

  • Thanks, this helped a lot!

  • Your videos are super helpful! They really make a huge difference to my understanding of calculus, which btw, I'm extremely weak at.

    Thanks!

  • Your videos are so good!!

    thank you!!

  • your videos are the best!

  • thank you thank you

    thank you teacher

  • happy to help : )

  • thanks for Explain

  • What if I have a function with absolute value?

  • awsome job...where did you go to school?

  • how did you get y to the fifth and y to the second :D

  • he found the indefinite integrals (antiderivatives) of -y^4 and +y^2

    and using the reverse of power rule, they should equal (-y^5)/5 and (y^2)/2 respectively

  • They are definite integrals.

  • you make calculus look easy...thnx

  • Keep up the great videos! :)

  • why are so many people watching this part but not the first? : )

  • Comment removed

  • @patrickJMT that is a good question

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