Pi-Squared Over 6 and the Algebraic Genius of Euler - Part I

[MathNotationsVids]

dmarain For any function f, the y-int is f(0). For a polynomial, this will be the constant term since all other terms will have a variable. Thus for y=ax^2+bx+c, c is the y-int. Completing the sqr produces y=a(x-h)^2+k. (h,k) locates the vertex of the parabola.

[gayglue]

at 3:48, don't you have to complete the square for the last term to be the y-intercept?

[johnnynapalmiv]

Wadworth's constant applies

[MathNotationsVids]

Everyone's comments are most appreciated. Thanks for correcting the errors. I'm sure I made others! As far as wasting time, point well taken. I need to tighten up my presentation. I'm not following a tight script.

[TOMTOM171717]

seriously, 2 minutes and no maths

[TOMTOM171717]

i think you should dive straight in to the math, people who don't like maths can work that out for themselves

[StefanoCiampichetti]

Also in the second video a little mistak..it should be:

Also in this video a little mistake: 1 - (x^2)/6 + (x^4)/120 - ..... (So, not x^5)

[StefanoCiampichetti]

Hey my friend! Good vid! But you made a mistake: It is: 1 - 1/6x + 5/6x^2

[TLMCiSkyzz]

first post. woot