Question...What happens to the 2s orbital for F? Isn't that still in the valence shell? And why don't the electrons from the other p orbitals get put into the MO diagram? I thought that's how you make the diagram-by just putting the valence electrons into MO's
You should define your axis system and point group. HF belongs to point group C∞v. Where by convention the z axis goes down the H-F bond and the H 1s and F the 2s and 2pz have the appropriate symmetry (A1=Σ+) to form a sigma bond but the F 2s is low in energy due to the high electronegativity (effective nuclear charge) of F so it does not overlap well with the H 1s and so is nonbonding. The 2px and py have E1=Π symmetry and are also nonbonding.
what about the electrons from the Fluorine that are in the 2s orbital, should they not be shown because technically wouldn't they be involved in the nonbonding electrons since there are 3 lone pairs of electrons around the F and the MO you drew only shows two lone pairs of nonbonding electrons.
@blegrand5 You can show the 2s orbitals but there isn't overlap with the other orbitals. In that case, draw what is most helpful for the problem you are doing.
The material you are presenting might be basic, but your presentation is so clear and organized, your camera work so professional, that I was impressed in moments.
The atomic orbitals of F should be lower in energy than that of H because it has more protons that will attract the valence electrons toward it, decreasing the energy of the valence electrons. So the 2p orbital should be shown as lower on the diagram!
Question...What happens to the 2s orbital for F? Isn't that still in the valence shell? And why don't the electrons from the other p orbitals get put into the MO diagram? I thought that's how you make the diagram-by just putting the valence electrons into MO's
Thanks!
MrZrh 2 weeks ago in playlist Adv. Molecular Orbital Diagrams
@MrZrh Energetically, they are low in energy and it doesn't overlap. You would need to have or be given that knowledge to draw the diagram.
EnderlePhD 2 weeks ago
You should define your axis system and point group. HF belongs to point group C∞v. Where by convention the z axis goes down the H-F bond and the H 1s and F the 2s and 2pz have the appropriate symmetry (A1=Σ+) to form a sigma bond but the F 2s is low in energy due to the high electronegativity (effective nuclear charge) of F so it does not overlap well with the H 1s and so is nonbonding. The 2px and py have E1=Π symmetry and are also nonbonding.
olsemeik 1 month ago
@olsemeik Thanks for the additional information. I didn't have the intention to include that information in this video. Cheers.
EnderlePhD 1 month ago
what about the electrons from the Fluorine that are in the 2s orbital, should they not be shown because technically wouldn't they be involved in the nonbonding electrons since there are 3 lone pairs of electrons around the F and the MO you drew only shows two lone pairs of nonbonding electrons.
blegrand5 2 months ago
@blegrand5 You can show the 2s orbitals but there isn't overlap with the other orbitals. In that case, draw what is most helpful for the problem you are doing.
EnderlePhD 2 months ago
The material you are presenting might be basic, but your presentation is so clear and organized, your camera work so professional, that I was impressed in moments.
steser23 3 months ago
The atomic orbitals of F should be lower in energy than that of H because it has more protons that will attract the valence electrons toward it, decreasing the energy of the valence electrons. So the 2p orbital should be shown as lower on the diagram!
1nkay 3 months ago
hes cute :)
MonaRocks09 11 months ago
thanx alooooooot,God bless u
alyausa 1 year ago