OMG THANK YOU SO MUCH. My teacher did not explain it well for my junior class at all but, now i clearly understand it. It is much easier after you split the horizontal and vertical terms. Thank You good sir!
I am very happy to see the vidoe This is our series of physics lesson videos made for our students at Earl Haig SS in North York, Ontario, Canada. Let us know if you found them helpful. M after you give this
Steady I Really Like This Video This is our series of physics lesson videos made for our students at Earl Haig SS in North York, Ontario, Canada. Let us know if you found them helpful. Mr
Yeah no. This guy is wrong at 0:30. When an object is THROWN UP it's acceleration is -9.81m/s squared. When the object is coming back DOWN, the acceleration is 9.81m/s squared. Same for projectile motion. There is no vertical acceleration when thrown off a raised surface, but when the object, be it a cannonball or a twig, goes down towards the surface the earth, the acceleration is - 9.81 m/s squared.
@LiliRayofSun when drawing a diagram, you define up or down as negative/positive, and left or right on the diagram as negative/positive. It doesnt matter which one you choose, you will get the same result, but you have to define it on your diagram like he did with the arrow pointing upwards and the + sign. The initial acceleration for an infinitesimal amount of time when dropped from a height above ground will be exactly 9.81ms^2
hey my school does not offer physics as a coarse but would like to persue a degree in advanced physics and nuclear engineering any tips on how i could be prepared for my first day in college will i be behind the crowed or should i persue outside help to get me pre pared
it's a good illustration. you could also watch a demonstration video on my channel. it shows a program that does projectile motion automatically. if you're interested on how the program works, you can visit the web site that's also on my channel.
Hey, I have an question and maybe you could answer it.
Don't we need to consider the earth's orbit to determine where a projectile lands. Because in every projectile motion question, they just use the magnitude of the displacement as where it lands from the starting point.
I like how organized this is. I am a student that needs to know why about everything. I can see what I need and how it is used this way. Very helpful.
@abelardofloresd10 With d=V1t +1/2at^2 you can't rearrange it if V1 is not zero because it becomes a quadratic equation and you have to use the quadratic formula to solve for t. If V1 is zero as in this example you get d= V1t + 1/2 at^2 and so -40 = 0 + 1/2(-9.8)t^2. Multiply the 1/2 and the -9.8 you get -40 = -4.9t^2 now divide boht sides by 4.9 like this -40/4.9 = -4.9/4.9 *t^2 and the result is -8.16 = - t^2 so now cancel the (-) from both sides and take the square root and you get about 2.9
if i had teachers like you i wouldn't feel stupid in life or like i have some ADD since i cant get it...half paying attention to this made more sense and was easy to remember than struggling to pay attention in class wondering what way i can organize the scattered notes he puts up on the board.
@eaglesgogirl Hi. It depends on what you are asked for. If you are asked for the final velocity when it hits the gound, then you need both Vh and V2v to find this. We have a video that shows this called "Physics Lesson: Projectile Motion Part 3" Otherwise you don't need it to solve the problem in this video. I hope this helps.
you guys are th e best!!! so much better than my prof. mine doesn't makes sense at all and goes too fast without asking us if we understand what the hell she's talking about!
Thanks a lot! I missed 3 days of school before the beginning of our Spring Break (got sick), and missed quite a bit of notes. I then returned to school, to find out that our exam was the next day.
@MusicTewns The horizontal direction it is uniform motion so there is only one v=d/t For the vertical theres 5 acceleration equations. You must be given at least 3 of the 5 variables in these equations and you decide which of the other ones you need to solve for. You look at the 5 equations and find the equation that has the 3 variables you have and the one you are looking for. That's the equation you use. Check our video Physics Lesson: Acceleration Equations Part 1 Kinematics for High School
Hey, calculated your working and i dont think tt answer for time is 2.9, i'm not sure and pls correct me if i'm wrong, cause from my calculations it isn't 2.9. Thank you, great vid!
woah. i am a bit confused. I wasn't told of the formula v=d/t
i was given formulas like Vx^2 = Ux^2
and Vy^2= Uy2 + 2ay(delta)y
Am i confusing things :s
iDJMIXTRESS 1 day ago
thanks man your soo goin to heaven cz of saving people's lives
WhyIsMyNameSoLong1 3 days ago
I've got just one question: at 4:10 you say "you probably know: d_v= V_1*t + a*1/2*t^2". Where does that equation comes from?
OokamiKyoodai 1 week ago
great teacher...my physics teacher is also great but i m just refershing!!!! thanx for helping, sir!!!
someone20ify 2 weeks ago
oh i thought -9.80m/s^2 is the gravity not the acceleration
ruthxcore10 2 weeks ago
@ruthxcore10 That's the acceleration OF gravity =)
andismokedatguitar 2 weeks ago
@andismokedatguitar oh thanks.. I'm kind of confused there! =)
ruthxcore10 2 weeks ago
370*
greenran5 3 weeks ago
@royourboat23 bullets travel even faster. Up to about 470 m/s!
greenran5 3 weeks ago
wow, setting the two components into two separate columns makes it so much easier to solve.
SkateKanata 4 weeks ago
i love you
schnouttz 4 weeks ago
this is so helpful! thanks!
mrtsunny 4 weeks ago
is 200m/s really practical?
royourboat23 1 month ago
Thank you very much =)
FantasyOfLegends 1 month ago
It's amazing what a simple concept of organizing the givens into vertical and horizontal is! BUT THIS MADE ALL THE DIFFERENCE! Thanks :)
Zelby95 1 month ago
Oh man, this is so much better than how my teacher explained it. Time to pass that exam!
Tabongadoo 1 month ago
@Tabongadoo Same here. Canada and its teachers. Bah, some of them are just bad at teaching.
XOSiren18XO 1 month ago
I thank God that people like you exist.
GREATGAIWAIN 1 month ago
I dont underestand how you get 2.9
yyyy2999 1 month ago
This is aweeeeeesome
yyyy2999 1 month ago
OMG THANK YOU SO MUCH. My teacher did not explain it well for my junior class at all but, now i clearly understand it. It is much easier after you split the horizontal and vertical terms. Thank You good sir!
snowboarder1ify 1 month ago
I am very happy to see the vidoe This is our series of physics lesson videos made for our students at Earl Haig SS in North York, Ontario, Canada. Let us know if you found them helpful. M after you give this
Kricardose 1 month ago
I Love The Video We have a number of videos so we have organized them on our school website It Can Increase My Knowledge
bebeheuy 1 month ago
Steady I Really Like This Video This is our series of physics lesson videos made for our students at Earl Haig SS in North York, Ontario, Canada. Let us know if you found them helpful. Mr
Mjhond 1 month ago
Thank you for all the help!
iceecream6 1 month ago
Mostly confused but will get there. In our school we refer to the SUVAT formula.
S=displacement
U=starting velocity v=Ending velocity and A for acceleration...oh god is the Dh in this video horizontal distance?
Dragonxsolo 1 month ago in playlist More videos from PhysicsEH
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for USE Mr Newton we must be sure own speed vector direcion More detail
wwww.maroszVSnewton.cba.pl please see my experiments and Patents
Maciekkmarosz 2 months ago
ok now i'm more genius than before tanksalotXD
oniro91 2 months ago
Thank you! This has helped me soooo much!!!
melheartspink17 2 months ago
Physics test tomorrow. I will probably have the biggest headache in the 15 years of my existence. But hopefully this would of help
xxhanaxxbluexx 2 months ago
Comment removed
gluemanred 3 months ago
Yeah no. This guy is wrong at 0:30. When an object is THROWN UP it's acceleration is -9.81m/s squared. When the object is coming back DOWN, the acceleration is 9.81m/s squared. Same for projectile motion. There is no vertical acceleration when thrown off a raised surface, but when the object, be it a cannonball or a twig, goes down towards the surface the earth, the acceleration is - 9.81 m/s squared.
LiliRayofSun 3 months ago
@LiliRayofSun when drawing a diagram, you define up or down as negative/positive, and left or right on the diagram as negative/positive. It doesnt matter which one you choose, you will get the same result, but you have to define it on your diagram like he did with the arrow pointing upwards and the + sign. The initial acceleration for an infinitesimal amount of time when dropped from a height above ground will be exactly 9.81ms^2
SALENTRAT 2 months ago
@LiliRayofSun agreed, i was kinda confused abit when he said that, since objects going up slows down due to gravity, the acceleration is negative.
MrLYTRIX 2 months ago
Comment removed
LiliRayofSun 3 months ago
I want you to be my teacher!!! You are unspeakable helpful!!!!!
cool12threeman 3 months ago
how did u figure the timeon the vertical column?
OfficialBassMonkey 3 months ago
(Y)
MsCraze94 3 months ago
you just saved me from failing my physics midterm tomorrow, thank you so much
SkiesTheLimit62 3 months ago
hey my school does not offer physics as a coarse but would like to persue a degree in advanced physics and nuclear engineering any tips on how i could be prepared for my first day in college will i be behind the crowed or should i persue outside help to get me pre pared
goodcake507 3 months ago
it's a good illustration. you could also watch a demonstration video on my channel. it shows a program that does projectile motion automatically. if you're interested on how the program works, you can visit the web site that's also on my channel.
jensons88 3 months ago
Thanks a lot. Really really helpful.
rapstreetz 3 months ago
ih y goodness i thnk i may pass my pass my test <3
Diegonators 3 months ago
very helpful thx
soulxofxgirl 3 months ago
Thanks alot . it really helped me alot
SUMEET2459 4 months ago
My teacher told me to multiply by 2 to get the time for the horizontal...
CookieSpring 4 months ago in playlist More videos from PhysicsEH
Hey, I have an question and maybe you could answer it.
Don't we need to consider the earth's orbit to determine where a projectile lands. Because in every projectile motion question, they just use the magnitude of the displacement as where it lands from the starting point.
804YankeeFan 4 months ago
My goodness... What I'd do for an instructor who can teach as well as this man in my daily life. Thank you sir, SO much.
Johnnyman67 4 months ago
Comment removed
georgiegirl5542684 4 months ago
thanks, u a wonderful teacher for home
georgiegirl5542684 4 months ago
I like how organized this is. I am a student that needs to know why about everything. I can see what I need and how it is used this way. Very helpful.
qsierra1 4 months ago
You saved me from failing a huge test
Thaank you <3 FROM THE PEOPLE OF DUBAI !
Reem2013 4 months ago
Thanks for taking time to make these videos, i hope you realize how much it helps!
jkhotrod360 4 months ago 17
@jkhotrod360 Thanks for letting us know. Glad we could help.
PhysicsEH 4 months ago
Thank's for your help. Very helpful video.
benhendrick1 4 months ago
@benhendrick1 Glad we could help.
PhysicsEH 4 months ago
what about a full parabola?
mousetail90 4 months ago
@mousetail90 Try the same title video but part 2 I think this is what you are asking about. Hope it helps.
PhysicsEH 4 months ago
@PhysicsEH Is the parabolic motion applied to a missle?
Bakugantsuvai1 3 months ago
how do you solve for t?!!!
thats what always confuses me, i cant figure out the algebra
rearranging is complex for me
abelardofloresd10 4 months ago
@abelardofloresd10 -40/-4.9 = 8.16 then you get the t squared ,you must find t so you square root 8.16 and TA DA =2.9<<ROUNDED
Zolfigarr 4 months ago
@abelardofloresd10 With d=V1t +1/2at^2 you can't rearrange it if V1 is not zero because it becomes a quadratic equation and you have to use the quadratic formula to solve for t. If V1 is zero as in this example you get d= V1t + 1/2 at^2 and so -40 = 0 + 1/2(-9.8)t^2. Multiply the 1/2 and the -9.8 you get -40 = -4.9t^2 now divide boht sides by 4.9 like this -40/4.9 = -4.9/4.9 *t^2 and the result is -8.16 = - t^2 so now cancel the (-) from both sides and take the square root and you get about 2.9
PhysicsEH 4 months ago
Thanks a lot :)
i really benefited a lot
PLZ keep on doing this :)
and thanks again
((Subscribed))
shehab1414 4 months ago 12
@shehab1414 Thanks for the kind comment. Glad we could help.
PhysicsEH 4 months ago
thank you for this video. It helped a lot :D
idiotlover03 5 months ago
@idiotlover03 Glad we could help
PhysicsEH 4 months ago
if i had teachers like you i wouldn't feel stupid in life or like i have some ADD since i cant get it...half paying attention to this made more sense and was easy to remember than struggling to pay attention in class wondering what way i can organize the scattered notes he puts up on the board.
alextheromanian 5 months ago
@alextheromanian Thanks for the very nice comment. Glad to help.
PhysicsEH 5 months ago
@alextheromanian Thanks for the very nice comment. Glad to help.
PhysicsEH 5 months ago
You guys are F- ing Awesome!!!!!!
SiikP90 5 months ago
@SiikP90 Thanks. We're glad to help.
PhysicsEH 5 months ago
wait so is the V2v neccessary info or do we just not solve for it?
eaglesgogirl 5 months ago
@eaglesgogirl Hi. It depends on what you are asked for. If you are asked for the final velocity when it hits the gound, then you need both Vh and V2v to find this. We have a video that shows this called "Physics Lesson: Projectile Motion Part 3" Otherwise you don't need it to solve the problem in this video. I hope this helps.
PhysicsEH 5 months ago
@PhysicsEH Thank you, I understand. :D
eaglesgogirl 3 months ago
ur d coolest of d cool man thanks
kabilan83 5 months ago
@kabilan83 Thanks for taking the time to let us know we helped. Best of luck with your course.
PhysicsEH 5 months ago
@PhysicsEH You are the Best Physics Teacher ever! Thanks alot! you made me Pass my Test Perfectly!
hardyx91252614 5 months ago
@hardyx91252614 Best comment we have had in a while. Thanks!
PhysicsEH 5 months ago
@PhysicsEH Thanks to you. :)
hardyx91252614 4 months ago
you guys make physics very easy to understand. Great job!
trammi10000 6 months ago
@trammi10000 Thanks. We love to hear positive comments.
PhysicsEH 6 months ago
@Bond071000 Thanks for the kind comments. We are glad to help.
PhysicsEH 6 months ago
@Bond071000 Glad we could help.
PhysicsEH 6 months ago
you guys are th e best!!! so much better than my prof. mine doesn't makes sense at all and goes too fast without asking us if we understand what the hell she's talking about!
Please do more videos!!! :D
mozahemi 6 months ago
@mozahemi Thanks for the compliments. Glad we could help.
PhysicsEH 6 months ago
YOU ARE THE BEST TEACHER EVER!! :D
I wish you were my physics teacher. Even though english is not my normal medium for communication I understood your explanation very well. :D
gatecrusher02 6 months ago
thxs man
csegul1 6 months ago
@csegul1 You're welcome.
mcaruana1 6 months ago
Comment removed
Sp3llCrack3r 7 months ago
Wow!! i was so down about not understanding my physics homework... and because of you i understand it. thanks a lot. great teacher/professor.
rgarciajr4 8 months ago
@rgarciajr4 Hi. Thanks for taking the time to let us know it helped. We love to hear that.
PhysicsEH 8 months ago
Comment removed
RefinedCode 8 months ago
@RefinedCode Glad to help. Best of luck with your exam.
PhysicsEH 8 months ago
This is taught in 12th grade at Earl Haig? At Mackenzie, this is gr.11 material :(
ItHappens117 8 months ago
@ItHappens117 Hi. Yes, we moved a few things around to make both courses flow better. Good luck on your exams.
PhysicsEH 8 months ago
I LIKE IT ... thanks :)
vb4des 9 months ago
@vb4des Glad to hear you liked it. Thanks for the comment.
PhysicsEH 9 months ago
Sir, you make learning physics look easy. You are, from what I can see, an AMAZING teacher!
MastaAlexo 10 months ago
@MastaAlexo Thanks for taking the time to leave such a nice comment. Glad we could help.
PhysicsEH 10 months ago
What if what is asked is the final velocity??
AinahMAx 10 months ago
@AinahMAx Hi. We have a video on that topic. Look for "Physics Lesson: Projectile Motion Part 3 for High School"
You can search it on YouTube or if you go to our website listed in the description you can find the link with all our videos. I hope this helps.
PhysicsEH 10 months ago
@PhysicsEH Thanks you! :D i have a big test tomorrow and this video really helped!
AinahMAx 10 months ago
@AinahMAx Glad to help. Good luck on your test.
PhysicsEH 10 months ago
@lolmunkyboi Thanks for the compliment. We appreciate you taking the time to let us know you liked our videos.
PhysicsEH 10 months ago
Thanks a lot! I missed 3 days of school before the beginning of our Spring Break (got sick), and missed quite a bit of notes. I then returned to school, to find out that our exam was the next day.
TintedRedFilms 11 months ago
@TintedRedFilms I hope yout exam went well. Glad we could help.
PhysicsEH 10 months ago
I don't understand how you know which formulas to use, there are so many...
MusicTewns 11 months ago
@MusicTewns The horizontal direction it is uniform motion so there is only one v=d/t For the vertical theres 5 acceleration equations. You must be given at least 3 of the 5 variables in these equations and you decide which of the other ones you need to solve for. You look at the 5 equations and find the equation that has the 3 variables you have and the one you are looking for. That's the equation you use. Check our video Physics Lesson: Acceleration Equations Part 1 Kinematics for High School
PhysicsEH 11 months ago
thanks so much, that was really helpful!
averychristina 11 months ago
@averychristina Thanks for letting us know. It's nice to hear we've helped.
PhysicsEH 11 months ago
I'm confused u shoulda done the math for the 2.9 seconds for slow people like me but still great
Powerdude29 1 year ago
Really vivid explaining and well set out, thank you that was really helpful! keep them coming! :)
wabisk3 1 year ago
@wabisk3 Great to hear they helped. Let your friends know about us.
PhysicsEH 1 year ago
@brooklynhearts Thanks for the kind words. We are so glad we could help you. Let others know about us.
PhysicsEH 1 year ago
YES!
LightReincarnation 1 year ago
@LightReincarnation Thanks, glad to help. Tell your friends about us.
PhysicsEH 1 year ago
@PhysicsEH Thanks to you sir I covered a semester in 1 day and passed the test with a 94
LightReincarnation 1 year ago
@LightReincarnation Thanks for letting us know. You made my day.
PhysicsEH 1 year ago
Hey, calculated your working and i dont think tt answer for time is 2.9, i'm not sure and pls correct me if i'm wrong, cause from my calculations it isn't 2.9. Thank you, great vid!
64647936 1 year ago
@64647936 OH wait, i just got 2.9, sorry, my mistake, thx for the vid!
64647936 1 year ago
@64647936 Glad you got it. Good luck in your course.
PhysicsEH 1 year ago
Man.... i had you last year, and i wish Mr. Motica could teach it like you. Wish you were my teacher
nickey7402005 1 year ago
Thx u very much u really helped me a lot about this
ahlawy1993 1 year ago
@ahlawy1993 Great. Glad to help.
PhysicsEH 1 year ago
dudeee, you have no idea how much you cleared things up for me
HrdCore1337 1 year ago
@HrdCore1337 Hi. Great! Thanks for letting us know we helped.
PhysicsEH 1 year ago
@PhysicsEH the only thing is that could you explain how to calculate y-max?
HrdCore1337 1 year ago
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@PhysicsEH the only thing is that could you explain how to calculate y-max?
HrdCore1337 1 year ago
This has been flagged as spam show
@PhysicsEH the only thing is that could you explain how to calculate y-max?
HrdCore1337 1 year ago