Can someone explain this? I thought that if that positive-charged carbon anion is getting more negative charge from the surrounding carbons, wouldn't that make it less positively charged? So if it's less positively charged, wouldn't the Bromide not attach itself to it as much?
@chillerman625@thatguy126 You're right, a barbed curved arrow ("half arrow") should be used when only one electron is moving (e.g. homolytic bond cleavage or radical reactions). Sal talks about moving only one electron here, but the common convention in this mechanism is to depict the movement of pairs of electrons, which would be indicated using a full arrow. So the full arrow is correct for this mechanism, but it should be two, not one, electrons moving in each of the steps.
this stability video has no significance but justy confuses.......
just break the double bond so we get two posibilies ie the presence of partially positive on one or the other and we know the order of the stability of carbocation ie positive charge which is resonance>3deg>2deg>1deg>0deg
Quick question Sal (or anyone else): should Sal not draw a single arrowhead instead of ----> because ---> implies that there are two electrons being lost from an atom but in this mechanism we are seeing only one electron at a time being moved from one atom to anotehr. Anyone want to clarify this? thanks.
Wait, what if the second carbon (in the left) was bonded to a electron hogging group like chlorine? I don't see a reason for the left mechanism to work at all (without peroxides), but I know I'm wrong. Help?
a carbocation is more electronegative than a chlorine ---think about it, a positive atom is much more likely to attract electrons. The dispersed electrons in the will shift towards the positive charge. To really understand this, you have to think about electronegativity and why it is that certain atoms have a higher affinity for electrons. Hopefully that helped.
a carbocation is more electronegative than a chlorine ---think about it, a positive atom is much more likely to attract electrons. The dispersed electrons in the will shift towards the positive charge. To really understand this, you have to think about electronegativity and why it is that certain atoms have a higher affinity for electrons. Hopefully that helped.
@n1a1s1i1m I believe the left one works because it has two carbon groups to stabilize the positively charged transition state whereas the one on the right doesn't work as well because it only has one carbon group. This means that the one on the left has a lower energy hurdle to jump over so it is more likely to occur.
I'm not sure if that is what you mean? Either way, your post is a year old so you probably don't even care anymore.
Its not bonded to a Cl, the point is that the H goes to the place where MOST of the H are bonded. The C-HH to make C-HHH.
Or you can look at the carbons and see which one has the higher carbocation (In this case, it was secondary). We know carbon can have tertiary, secondary, and primary. In this example there is no tertiary so look at the secondary one.
Can someone explain this? I thought that if that positive-charged carbon anion is getting more negative charge from the surrounding carbons, wouldn't that make it less positively charged? So if it's less positively charged, wouldn't the Bromide not attach itself to it as much?
herpderpmonkey 4 days ago in playlist Organic Chemistry
Markovnikov Rules
Ponnyboy555 1 month ago
Gracias.
s0m0c 1 month ago
I am the first person to dislike this video
goldensilverstar 2 months ago in playlist Khan Academy Organic Chemistry
@goldensilverstar And why is that? O_o
AnnosY 1 week ago
Shouldn't the arrow be only a half arrow since you are only transferring one electron rather than electron pair?
chillerman625 3 months ago in playlist Organic Chemistry
@chillerman625 haha i actually asked this question too on a different vid......i just went with the flow and ignored it
thatguy126 3 months ago
@chillerman625 @thatguy126 You're right, a barbed curved arrow ("half arrow") should be used when only one electron is moving (e.g. homolytic bond cleavage or radical reactions). Sal talks about moving only one electron here, but the common convention in this mechanism is to depict the movement of pairs of electrons, which would be indicated using a full arrow. So the full arrow is correct for this mechanism, but it should be two, not one, electrons moving in each of the steps.
kayliyt 1 week ago
Genial señor, thanks
airdas 3 months ago
where have you been all my life?! this was so helpful! you are awesome!!! yay! :D
chickvball012 3 months ago
So, what I can see here is that the more stable the carbocation, the more it tendency to be bonded with H+, am I right? :\
potynaughty 5 months ago
Thank you so much! I'm planning to take ochem this coming semester, and I hope I can watch all your videos before school starts! :D
JarOfNotes 7 months ago
Thanks Salman.
stexan88 8 months ago
I love you even more. I'm Indian too btw xD
bfmvshinigami 9 months ago
I love you
ItsNeuroscience 9 months ago
I love you
doflegend291 10 months ago
This is a dumb question but when you said stable did you mean that the valence electrons were filled?
O0oSorousho0O 10 months ago
@O0oSorousho0O Yes.
Rictoo 10 months ago
@O0oSorousho0O Yes, when the valence shell is filled.
Rictoo 10 months ago
This summer, I will try to watch every single Khanacademy video! I hope! :D
O0oSorousho0O 10 months ago
great visuals! wish you could have been my ochem prof back in college.
ariesstardiamond 10 months ago
this stability video has no significance but justy confuses.......
just break the double bond so we get two posibilies ie the presence of partially positive on one or the other and we know the order of the stability of carbocation ie positive charge which is resonance>3deg>2deg>1deg>0deg
zombiedead19 11 months ago
Great pedagogics, voice and visual assets! Very helpful, thank you and keep up the good work!
iSahand 11 months ago
Markovnikov sounds like a capitalist. Rich get richer, poor get poorer.
SSJLIGHT 11 months ago
Are you single?
just kidding. Thank you so much for your help.
nahilhamam 11 months ago
Quick question Sal (or anyone else): should Sal not draw a single arrowhead instead of ----> because ---> implies that there are two electrons being lost from an atom but in this mechanism we are seeing only one electron at a time being moved from one atom to anotehr. Anyone want to clarify this? thanks.
Rizmaestro 1 year ago
"Borrow electrons from some of its friends" HAHAHAHA
timechange01 1 year ago
lovely! :D....and all of this occurs at room temperature...right o_O? ....please dooo a video on oxidation of alcoholssssssss!!!!!!!!!!!! thanks :)
missbopeepsqueak 1 year ago
I wonder .. the right carbon in left compound was attached to 3 carbons ..
does that right carbon call tertiary carbon ?
Anthonyay2008 1 year ago
You make all this stuff very simple to understand! Thank you!
Charmed20077 1 year ago
Wait, what if the second carbon (in the left) was bonded to a electron hogging group like chlorine? I don't see a reason for the left mechanism to work at all (without peroxides), but I know I'm wrong. Help?
n1a1s1i1m 1 year ago 3
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autumnissweetcuz 1 year ago
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autumnissweetcuz 1 year ago
This has been flagged as spam show
@n1a1s1i1m
@n1a1s1i1m
a carbocation is more electronegative than a chlorine ---think about it, a positive atom is much more likely to attract electrons. The dispersed electrons in the will shift towards the positive charge. To really understand this, you have to think about electronegativity and why it is that certain atoms have a higher affinity for electrons. Hopefully that helped.
autumnissweetcuz 1 year ago
This has been flagged as spam show
a carbocation is more electronegative than a chlorine ---think about it, a positive atom is much more likely to attract electrons. The dispersed electrons in the will shift towards the positive charge. To really understand this, you have to think about electronegativity and why it is that certain atoms have a higher affinity for electrons. Hopefully that helped.
autumnissweetcuz 1 year ago
@n1a1s1i1m I believe the left one works because it has two carbon groups to stabilize the positively charged transition state whereas the one on the right doesn't work as well because it only has one carbon group. This means that the one on the left has a lower energy hurdle to jump over so it is more likely to occur.
I'm not sure if that is what you mean? Either way, your post is a year old so you probably don't even care anymore.
sidewinder4489 4 months ago
@n1a1s1i1m A year later..
Its not bonded to a Cl, the point is that the H goes to the place where MOST of the H are bonded. The C-HH to make C-HHH.
Or you can look at the carbons and see which one has the higher carbocation (In this case, it was secondary). We know carbon can have tertiary, secondary, and primary. In this example there is no tertiary so look at the secondary one.
tra12345iscool 4 months ago
Swiper no swiping?
n1a1s1i1m 1 year ago
Sal, I am addicted to these videos.
boeing747200lr 1 year ago
This one actuality has great quality video, thanks SAL for the hard work !
I'm from Algeria and u just helped me alot to understand Math and Chemistry ... Thx again :)
aiisshsaak 1 year ago 18
Twice the same video, Sal?
norwayte 1 year ago