Added: 3 years ago
From: khanacademy
Views: 39,068
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  • @islamChika [B1 B2 B3 M4 M5, B1 B2 M4 B3 M5, B1 M4 B2 B3 M5, M4 B1 B2 B3 M5, B1 B2 M4 M5 B3, B1 M4 B2 M5 B3, M4 B1 B2 M5 B3, B1 M4 M5 B2 B3, M4 B1 M5 B2 B3, M4 M5 B1 B2 B3] are the 10 unique combinations; consider, why [B2 B1 B3 M4 M5] isn't part of the above set... because it's just a repeat of [B1 B2 B3 M4 M5]. It's just tough to *see* the uniqueness because B and M are used more than once. Hopefully this will help anyone else who got a little confused. -- Keep it real!

  • im guessing your wife unplugged it?

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  • This very good and provided me help to understand the concept of Probability this is the first time having watched the video i couldn't help passing my comments

  • "high end calculator" LOLX

  • why do you multiple by the number of outcomes instead of dividing like prior example on probability and combinations part 1?

  • Do you have a video on sum of sequences?

  • thanks :D

  • thank you, your video helped a lot.

    i'm learning this as binomial random variables and for some reason you didn't mention that. i feel that had you said that i would have made the connection a little sooner with the formula

    ( n choose x ) p^x (1-p)^n-x where p is a success.

    thanks again.

  • Thank you very much, Sal! I'm a returning student who's just discovered your videos, and they have been a huge help as a supplement tor my Discrete Math and Pre-Calculus classes already! Your lessons are very clear and easy to understand (and pause and takes notes on when necessary), and like the other user, I must give kudos to your wife as well.

  • Hi Khan (I'm sorry this other commenter calls u Sal; is that your name?), anyway, can u plz answer a Q for me? in ur last vid, prob. & combs, u said "prob of anything happening is the # of equally probable events/trials which are 'true' OVER the total # of equally possible outcomes," but in this vid I don't think u do that, but only seem to multiply. Why is that? I know it's b/c I don't understand something & with correspondence I don't get much help so thank you tons!!!

  • @valeagrl1 I'm having the same problem

  • Sal,

    for a change, let's give credit to your wife for letting you have enough time to post all these videos and your microphone will stay plugged!!

  • Hello,

    Thank you so much for your videos!! I'm terrible at Math and I find your explanations to be clear and easy to understand. There is one thing I don't understand however: you said in your previous videos that the difference between a Permutation and a combination is that order is important in the former. But in your free throw example, you said that BBBMM and BMBMB are 2 different combination. All I'm seeing is a different order of the same number of baskets and misses. Could you explain?

  • In a permutation, you would differentiate between the misses (or the baskets) while you wouldn't in the combinations. If I wanted to know all of the permutations of 3 people that could sit in 3 seats, there would be 6. There is however only 1 combination.

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  • I think you got confused here. BBBMM means you got basket for first time 2nd time and 3rd time. BMBMB means you got basket for first time 3rd time and fifth time. These are different combination. If you consider permutation for BBBMM, that will sound weird, meaning you got basket for 2nd time and got basket for first time and got basket for 3rd time...

  • { (B1 B2 B3 M4 M5), (B1 B2 M4 B3 M5), (B1 M4 B2 B3 M5), (M4 B1 B2 B3 M5), (B1 B2 M4 M5 B3), (B1 M4 B2 M5 B3), (M4 B1 B2 M5 B3), (B1 M4 M5 B2 B3), (M4 B1 M5 B2 B3), (M4 M5 B1 B2 B3) } are the 10 unique combinations; consider, why [B2 B1 B3 M4 M5] isn't part of the above set... because it's just a repeat of [B1 B2 B3 M4 M5]. It's just tough to *see* the uniqueness because B and M are used more than once. I hopefully this will help anyone else who got a little confused. -- Keep it real!

  • just go view.. click sciencetific... nice vid but

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