Added: 3 years ago
From: kwokthechemteacher
Views: 14,278
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  • thank you so much :) couldn't have made it much clearer - feeling much more confident for my exams tomorrow!

  • its owsommmmmmmmmmmmmmmmmmmmmm

  • SWEEEET!! I finally understand! 2 hours until my final chemistry exam you just saved my butt great vid :-D

  • isn't there a free radical on the Cl in the 2nd propagation step?

  • Thanks alot that was very clear and well done :D:D:D

  • @moorbre: Your welcome. I am glad that it helped. :)

  • fantastic.....exams next week. feel v confident now. 

  • @ah4fecksake Glad that it helped! :)

  • thank youuuu i revised it my self and still couldnt understand it myself until now thank youuu it pretty simple now

  • That really clear, brilliant to see it in simple steps. Thanks very much, helped a lot!

  • @fintaneh I am glad that it helped. :)

  • thanks man my exams r comming near and it helped me a lot ,, cheers buddy

  • @bindaasmahesh I am glad that it helped! :)

  • Can i guess that you're from sinagpore?

  • @gamerohan Well.. it is in my introduction. :P

  • @kwokthechemteacher Ah right, didn't see that, but i guessed from your accent! But this really helped with my chem exam yesterday! Oh and one question, how does Fe3+ bond with CN-? 

  • @gamerohan Well, that is okay. What is the context of the question? If it is a compound with the formula Fe(CN)2 = ionic, if it is a compound with a formula [Fe(CN)6]4-, covalent (dative bond).

  • @kwokthechemteacher Well the question was something like...what is the name of the complex ion when with Fe3+ and the Ligand CN-, and predict its shape

  • @gamerohan then it is a dative bond. Are you J1 or J2? Which sch?

  • @gamerohan. haha yup.. it is in my introduction.

  • AMAZING! finally understood it! thank god for your video!

  • @ohyahers I am glad that it was helpful to you. :)

  • amazing explanation, this is all i need !!

  • Nice Video.........Very Helpful

  • this was really helpful THANKS ALOT!!

    the mechanisim u explained really helped me understanding the "Chain Reaction" as we'r taking it.

  • For the chain propagation 2nd sub step: Where does the Cl2 come from?

  • a great explanation..helped a lot thanks

  • Ronery, so ronery, ronery and sad and awone...

  • Too sluggish dude, not bad though!

  • where did the carbon come from?

  • Excellent - The AQA Specification textbook used in the UK doesn't describe the exact mechanism of reaction and merely states it!

  • Thanks.. I hoe it was useful.

  • @JoeGaynerMusic Yeah same! AQA book sucks, its doesnt have answers for exam style questions, doesnt explain things clearly and just generally bad!

  • How does the fact that the relatively large size of the bromine atom allow the formation of a 3 membered ring structure in the carbonion ion?

  • See the propagattion step, step 2.

    There the chlorine radical missis an electron.

    The arrows in your explanation are not very clear.

  • Comment removed

  • thanx really helpfull video :)

  • You sounds like you are from Singapore

  • thanks , but i gueess you really need to buy a new microphone

  • thanks it was really helpfull

  • @hasan111111111111111

    Thanks for the comment. I am glad it was helpful. Hope that the others will be useful too. :)

  • Thanx for explaining..it has been of much help:)

  • your welcome. Glad that it was helpful. :)

  • thank you for this video, studying for a test on friday and this really helped clear this up

  • I am glad that it was of some help. Thanks! :)

  • I am taking Advanced Organic chemistry right now and I a ma senior in college. I must say, going over the basics again can be a little crazy after you haven't had organic in a while. But your video was great for free radical substitution. Hopefully you have a lot more from where that came from Thanks for this man and keep up the good work.

  • Hi, thanks! Glad that it was helpful. Yes, organic can become rusty when we haven't looked into its reactions.

  • yup! you are right that 2,3 dimethylbutane will be the bypdt. that is because the removal of the 2nd H of propane produces a radical that is more stable. Hence, this results in 2-bromopropane to be formed.

  • Thanks for the video, it supplemented my readings well. Keep it up.

  • @denzelnolet

    Hi there! Glad that this helps! :)

  • Thanks a lot, I am doing an assignment for chem where we have to learn our reaction. I was given propane + Br2, would I still follow these steps and could the last step for it be C3H7C3H7?

  • yes the last step cld be C6H14, the formation of hexane. :) but that usually wld be the byproduct.

  • Thanks a lot, so one of the questions i have to answer is what are the uses of the product and the reaction itself. Would i use the product of C3H7Br and the reaction: C3H7 + Br --> C3H7Br?

  • @LOL2345432

    if you are trying to produce C3H7Br, then it will be reacting C3H8 with Br2. During the propagation C3H7 radical reacts with a Br2 molecule to give the C3H7Br. In addition, yes the termination step will also have C3H7 radical reacting with a Br radical to give C3H7Br.

  • Ohhh i understand, thanks a lot for your great help!

  • were does the CH3 molecule come from?

  • It comes from the reaction between the halogen radical and the alkyl molecule.

  • Excellent video.

    Very usefull

  • thanks.. glad that found it useful. :)

  • great video

  • thanks!

  • thanks for the vid! very helpful indeed

  • @xhappyberryx

    glad you found it useful. :)

  • Thank you so much. You can not make it any better. Very helpful. :)

  • Your welcome. Glad that it was helpful. :)

  • Very clear and very good!

    btw if you want to make the video widescreen add the tag yt:stretch=16:9

  • i really appreciate the way you hav choosen to make ur students understand thanks alt

  • what does homolytic fashion and fission means sorry to say but your words are tooo complicated to understand them and my chem teacher taught us in a bit differnt style there are many steps you dint show its ok but u hav done a good job!!! thanks alt

  • When one electron goes to each chlorine atom, it's evenly shared so it's 1 electron each not 2 electrons for 1 atom and the other get's non.

  • very good and very clear working :) exams tomorrow and this has helped me to cement my knowledge of the mechanism, thanks

  • Thank you! =) I am glad you find it useful.

  • pretty clear`n useful

  • Thank you! =)

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