That may very well be true, but could you explain that in cartoon form? :) Just kidding. I didn't make the video, I just posted it with permission from the author. :)
That is true in algebra but in calculus the "C" should always be treated as a separate term because the antiderivative of any function will always be indefinite unless a definite interval is defined. That is why when you perform e^(2x^2+C), it will always be e^(2x^2) + e^C. since e^C is a constant, you can just simply call it C. simply put, y = e^(2x^2) + C.
This video was absolutely ridiculous, but it helped. Thank you, haha
ianrousso 1 year ago
great video
unknown2all2k5 2 years ago
yesss
infraorbitalforamen 2 years ago
Woah! That freaked me out when y started talking. I didn't see his mouth at first.
EverASurprise 3 years ago
No, that's cool. The video was fun. I support anything that makes math more appealing to a wider audience.
aj646464 4 years ago
The solution should not be the sum of two exponential functions. When you solve for y, you get: y = exp(2x^2 + c), which reduces to
y = exp(2x^2)*exp(c) instead of
y = exp(2x^2)+exp(c). Since exp(c) is just some constant, you can rewrite the solution as
y = C*exp(2x^2).
aj646464 4 years ago 3
That may very well be true, but could you explain that in cartoon form? :) Just kidding. I didn't make the video, I just posted it with permission from the author. :)
AllAboutMormons 4 years ago
That is true in algebra but in calculus the "C" should always be treated as a separate term because the antiderivative of any function will always be indefinite unless a definite interval is defined. That is why when you perform e^(2x^2+C), it will always be e^(2x^2) + e^C. since e^C is a constant, you can just simply call it C. simply put, y = e^(2x^2) + C.
terrencemcg 3 years ago