Very good demo. Take that from an old Navy radar tech. I too have had an interest in the 160-190 Khz band for a long time.Glad to see that the old hands-on techniques are not getting lost.
If the ic suddenly draws more current, the voltage over the internal resistance in your voltage source rises, and less voltage is delivered at the terminals.
Very good demo. Take that from an old Navy radar tech. I too have had an interest in the 160-190 Khz band for a long time.Glad to see that the old hands-on techniques are not getting lost.
lochinvar00465 1 month ago
I posted a video response which explains where the noise comes from and why bypass capacitors help.
yoududeuser 2 months ago
If the ic suddenly draws more current, the voltage over the internal resistance in your voltage source rises, and less voltage is delivered at the terminals.
flopski 4 months ago
I argue with that :
1- your chip is generating signal with some frequency
2- that signal can find its way back to the rest of the design via the power line VCC
3- you use decouple cap to DECOUPLE the noisy circuit from the rest of the design
4- choose decouple cap with value that adopt to the noise signal you expect
viewgsm 6 months ago
Nice demonstration! It's good to see an example of what voltage sag looks like in practice.
whisk0r 11 months ago