Boolean algebra #3: Basic problems (continued)

[HIHAYTAH]

@Viktormajstor Now if you would on and not been in a rush to go shit you would see the rules at the very end of the video.

[Viktormajstor]

can you put a list of all the rules somewhere please

[micropope]

6:48 you mentioned that A+AB = A so would that mean, for example, B+BA = B?

[croman2000]

@micropope yes!

[gian2g]

Thanks

[Flamez4000]

wot if its A + B' wots the simplified version of this???

plez respond!!

[superdpawar]

@Flamez4000 A + B' cannot be simplified as far as i know! because A and B are independent of each other.

[djhealey]

Best Boolean Algebra tutorial around! Very easy to follow! Thanks alot buddy!

[kamaleshthegreat]

Wow!! Cool dude! It helped me a lot!! Keep up the good work!

[McGowanChris]

Very well done again, thanks.

[LaToya2581]

This really helped me !

[eartrail]

the second one is not clear because this answer is zero(0)

[keleshevCOM]

@eartrail sorry, what do you mean? by second one you mean (A+B)(A+C) ?

[eartrail]

@keleshevCOM

 -A+B-A=

(-) this symbol represent negation

[keleshevCOM]

@eartrail

A' + BA' =

A'(1+B) =

A'

[eartrail]

@keleshevCOM oh thank you very much

[gurngurn00]

@keleshevCOM Can you please explain the second one clearer? D: from what I understand, A'(1+B) = 0 since (1+B) is going to be equal to 1. So does it mean A' multiplied by 1 is 0? :)

[steelepowell]

@gurngurn00 yeah i cant understand that either

[freestylerstyler]

You make it sound like a game :) thx

[tayntroy]

ohhh so that is the Absorption theorem. i get it :)