I spend some time tryin' to find the series in -pi, pi, and I think I found it, but because I'm belgian, I couldn't quite understand if you say it is impossible, or that we simply can not know if it is correct. According to me, the series for -pi, pi equals:
pi²/3-4cos x+cos 2x -4/9 cos 3x + 1/4 cos 4x -4/25 cos 5x + 1/9 cos 6x -4/49 cos 7x+ ...
Assuming convergence, this seems to allow a really quick proof of the Basel problem. Letting x = 3, f(x)=x^2 -> f(3) = 9,
9=3+36/Pi^2*Sum[n=1->Infinity](-1)^(2n)/n^2 so after some basic algebra
6Pi^2/36=Pi^2/6=Sum[n=1->Infinity]1/n^2. I think Donny was sort of hinting at that, but I think that's interesting. Hopefully the next couple of videos will help establish convergence =)
I would get crazy if I had to listen to him more.....talking so fast that it is almost imposible to follow....very bad teacher...
DasGewitter83 2 months ago
Good energy and skill, thanks for sharing.
JonnyHackerRed 8 months ago
I spend some time tryin' to find the series in -pi, pi, and I think I found it, but because I'm belgian, I couldn't quite understand if you say it is impossible, or that we simply can not know if it is correct. According to me, the series for -pi, pi equals:
pi²/3-4cos x+cos 2x -4/9 cos 3x + 1/4 cos 4x -4/25 cos 5x + 1/9 cos 6x -4/49 cos 7x+ ...
Thanks for your help.
pietersmulders 9 months ago
@pietersmulders
Yes this series is correct.
wadud88 5 months ago
Comment removed
bdboyplaysguitar 10 months ago
Its funny cuz hes asian
NeRvExNaTiOn 11 months ago
what if the limit was 1<x<3???
obrebel4ever02 1 year ago
What is it that you've done at 2:00? i don't understand how you've computed that integral.
spectrex1 1 year ago
Thanks... :)
theYusrie 1 year ago
what the hell am i watchin man
crazy shit
matBTF 1 year ago
Ugh, thanks for the help. I just hate having to integrate by parts over and over on exams.
tharock220 1 year ago
Assuming convergence, this seems to allow a really quick proof of the Basel problem. Letting x = 3, f(x)=x^2 -> f(3) = 9,
9=3+36/Pi^2*Sum[n=1->Infinity](-1)^(2n)/n^2 so after some basic algebra
6Pi^2/36=Pi^2/6=Sum[n=1->Infinity]1/n^2. I think Donny was sort of hinting at that, but I think that's interesting. Hopefully the next couple of videos will help establish convergence =)
2BobSaget3 3 years ago
It's exciting for it's elegance not it's complexity.
bluesrunthegame 3 years ago 5
This has been flagged as spam show
What are you so excited about? This is all very trivial and simple stuff
rutturu 4 years ago
Shut up and go fuck yourself. Some people are trying to learn.
LiangRome 3 years ago 22
okay,,,this one is quite clear and theoridically!!!!GOOD
dannylee86 4 years ago 3