good job
Trev727272 4 months ago
Thank you so much i would fail my test without this! THANKU
B335430104 10 months ago
Current is through, not across.
pdt8ball 11 months ago
This has been flagged as spam show
Free Energy is real and it's here but the coverup is strong, if u r interested in a REAL free energy magnet motor
just go to LT-MAGNET-MOTORdotCOM and download the blueprints ,it's probably the ONLY working magnet
motor out there. Join the free energy revolution!!
breeannaqktjbl 1 year ago
Free Energy is real and it's here! The Big Oil companies r doing everything they can to stop this
information. If you want a Free energy magnet motor , get the blueprints at LT-MAGNET-MOTORdotCOM , Join the
revolution!
glennjgd 1 year ago
Free Energy is real and its here but the coverup is strong, if u r interested in a REAL free energy magnet motor then
motor out there. Join the free energy revolution!!
fittingciobb 1 year ago
Free Energy is real and its here but the coverup is strong, if u r interested in a REAL free energy magnet motor then
urgencyharviefcem 1 year ago
Free Energy is real and its here but the coverup is strong, if u r interested in a REAL free energy magnet motor then
just go to LT-MAGNET-MOTORdotCOM and download the blueprints ,it is probably the ONLY working magnet
ivylsp 1 year ago
ohm my god, I'm shocked.
Is resistance futile?
Now do power factor correction for a 440v, 3ph motor at 80% efficiency and 80% PF, how much capacitance is needed to make the motor operate at 95% PF?
Easier way to solve your problem: 1 over 1/2+1/3+1/4 = total R.
Resistance will always be lower than the lowest value in parallel (less than 2 ohms in your circuit.
1 divided by 0.5+0.33+0.25 = 0.923 ohms. E=I*R
12v=I*0.923
I=12.999
Your circuit will have 12.999 amps total.
CalicoatMaker 2 years ago
@CalicoatMaker you are incorrect did you think someone would not notice?
theblackguy6haaa 1 year ago
nice man :D
jackyboy233 2 years ago
Thank you very much...
Shusuke3 3 years ago
good job
Trev727272 4 months ago
Thank you so much i would fail my test without this! THANKU
B335430104 10 months ago
Current is through, not across.
pdt8ball 11 months ago
This has been flagged as spam show
Free Energy is real and it's here but the coverup is strong, if u r interested in a REAL free energy magnet motor
just go to LT-MAGNET-MOTORdotCOM and download the blueprints ,it's probably the ONLY working magnet
motor out there. Join the free energy revolution!!
breeannaqktjbl 1 year ago
This has been flagged as spam show
Free Energy is real and it's here! The Big Oil companies r doing everything they can to stop this
information. If you want a Free energy magnet motor , get the blueprints at LT-MAGNET-MOTORdotCOM , Join the
revolution!
glennjgd 1 year ago
This has been flagged as spam show
Free Energy is real and its here but the coverup is strong, if u r interested in a REAL free energy magnet motor then
just go to LT-MAGNET-MOTORdotCOM and download the blueprints ,it's probably the ONLY working magnet
motor out there. Join the free energy revolution!!
fittingciobb 1 year ago
This has been flagged as spam show
Free Energy is real and its here but the coverup is strong, if u r interested in a REAL free energy magnet motor then
just go to LT-MAGNET-MOTORdotCOM and download the blueprints ,it's probably the ONLY working magnet
motor out there. Join the free energy revolution!!
urgencyharviefcem 1 year ago
This has been flagged as spam show
Free Energy is real and its here but the coverup is strong, if u r interested in a REAL free energy magnet motor then
just go to LT-MAGNET-MOTORdotCOM and download the blueprints ,it is probably the ONLY working magnet
motor out there. Join the free energy revolution!!
ivylsp 1 year ago
ohm my god, I'm shocked.
Is resistance futile?
Now do power factor correction for a 440v, 3ph motor at 80% efficiency and 80% PF, how much capacitance is needed to make the motor operate at 95% PF?
Easier way to solve your problem: 1 over 1/2+1/3+1/4 = total R.
Resistance will always be lower than the lowest value in parallel (less than 2 ohms in your circuit.
1 divided by 0.5+0.33+0.25 = 0.923 ohms. E=I*R
12v=I*0.923
I=12.999
Your circuit will have 12.999 amps total.
CalicoatMaker 2 years ago
@CalicoatMaker you are incorrect did you think someone would not notice?
theblackguy6haaa 1 year ago
nice man :D
jackyboy233 2 years ago
Thank you very much...
Shusuke3 3 years ago