Added: 2 years ago
From: khanacademy
Views: 39,017
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  • what the fudge?

  • OH MY GOD, THE WATER!

    ITS EVERYWHERE!!!!!

  • everything will be perfect if he changes all the "carbon dioxide" to "carbon monoxide"... I do not get confused by this small case and I could understand the thing he says...

  • I have this test tomorrow so I learned it in lecture three weeks ago and just learned more than my phd in nuclear chemistry teacher taught us!

  • I understand how the probability of finding water in a solution where water is the solvent has a probability of 1 given a volume of small arbitrary size because its essentially everywhere but how is a solid also viewed the same way? if we take a volume of small arbitrary size on the surface of the solid, then the probability is 1, otherwise it is ZERO!...unless we assume equilibrium will be achieved once all the H20 EVENTUALLY will interact with all of the carbon. Is this correct???

  • CO? you are wrong! you said carbondioxide.this is all the chemical elements I know.

    hydrogen,helium,lithium,beryll­ium,boron,carbon,nitrogen,oxyg­en,fluorine,neon,sodium,magnes­ium,aluminum,silcon,phosporsru­s,sulfur,chlorine and argon.

  • A minor mistake: You say "Carbon Dioxide" when you write "CO".

    Insignificant to the examples, but it drove me crazy!

  • carbon dioxide = CO2 not CO

    CO would be carbon monoxide

  • These "equillibrium" confuses me. I don't get the point of the contstant you're calculating, nor how you can find it with just the concentration numbers. I mean, aren't there many more factors?

  • @R2SweetTooth i believe the constant represents how many sets of BF3 3H20 there are per set of 3HF H3BO3

  • I thought you don't need to include equilibrium concentrations for water bacause its concentration doesn't change(it has a constant molarity).

  • Sal, I love you so much that you may want to be careful of me stalking you

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