@ImJacksAmygdala Dielectric breakdown isn't the key. Meyer's patent shows that the electrical charge is literally ripping apart the water molecules when the VIC ( I stress VIC) is at resonance. Specifically the section of the circuit between the charging choke behind the blocking diode and water capacitor. The frequency must be exactly at resonance for the effect to work, not higher, not lower. Meyers had a scanner circuit to scan the water cap to lock his PWM into the resonant frequency.
@Paul7mac The resonant frequency of water is not relevant when you consider that the water cell is just a capacitor. Please watch my upcoming video series starting with "What A Capacitor Is".
I'm interested in determining the minimum wattage required to produce a Meker flame. I understand feed back from the PLL is the key to keep the cell at resonance to restrict the amp flow through the dielectric break down as the cell saturates from a gated stepped pulse. I also think precise coil and core geometries are critical. Knowing the minimum input wattage to sustain a Meker Burner flame would be helpful to refine efficiencies for practical use. I've yet to see anyone attempt this at all.
@ImJacksAmygdala I'm inclined to agree. However, my time and experience is limited on the PLL at present. However, it is something that I have been regularly considering and am working on the direction of. Thanks for pointing it out.
@ImJacksAmygdala In all honesty, I don't have a very accurate measurement for this particular video. The ammeter I used suggested a current of between 100 and 200 mA, but I believe it's meant to be used for larger applications. I didn't start using my power monitor until later videos. However, I am waiting a new Pyramid power source that monitors voltage and current and will be able to give much better readings for future experiments.
Note that at time index 1:23 in watch?v=StV4jkJPnDY that the resonance is being applied to the CIRCUIT, not the water itself. Referring to the dielectric of the water demonstrates a capacitive attribute in a circuit, not specifically an attribute of the water itself. The resonating effect of ANY circuit is dependent on the capacitive effect of the capacitor (in the this case water cell) in the circuit in question. This important to understand in order to properly apply Meyer's technique.
@4891chris4891 Oh, and incidentally, I have on previous occasions tuned this circuit to the "known" resonant frequency of water. It did not change the effect. Demonstrating directly that the resonant frequency of the electronic tank circuit is more important than the resonant frequency of the dielectric of the capacitor in the tank circuit (in our case water). Please do some research in the LRC or electronic tank circuits to get a better understand of resonance in electronics.
@4891chris4891 One thing that most people miss is that the resonant frequency of water DOES NOT MATTER. This is an electronic tank circuit. Replace the water cell with ANY capacitor and the CIRCUIT will resonate based on that capacitors properties (while destroying the capacitor because that is essentially what this circuit is supposed to do, overload to catastrophic dielectric breakdown). The water cell is simply a capacitor. The resonant frequency of the dielectric is irrelevant.
You people are all morons! Whats the resonant frequency of water? look it up. And also the resistance of water changes a lot between temp and pressure. Did you check that?? In the mean time I am going to go bang my skull against the wall..... thanks p.s. you may be the least moronic of them all.
Overall, my conclusion to date is that gas out is relative to power in. The quantity of oxygen attracted to positive charge is dependant on size of the charge. Likewise for hydrogen for negative charge. The only way to make use of this would be if combustion results in a higher energy output than the equivalent power required to separate the atoms. If anyone knows how to measure the output of combustion with ambient gases by specific quantity, we'd have our answer.
Use vertical disks that are allowed to spin to slough off the bubbles quicker. (one disk positive the next negative etc. and 13.56 Mhz introduced for the harmonic of sodium)
The space gap between the pipes is apparently very important. I haven't measured the distance between them, but I believe mine are further apart than they should be. I will be trying at some point either plates or tubes that have less of a gap in them.
@quickshell Interesting result. Have you tried other frequencies? Like: 18k, 23k or 43k (plus or minus a few hundred Hz) are supposed to be other related resonance frequencies to shatter water. I'd be interested in your results.
I can't remember if those frequencies are accurate as it's been a while since I read them. They are noted in patents, to do with water fracturing/shattering.
@Itsmeeman1 Electrical frequencies do not cause the same effect of sound frequencies. The circuit is a self amplifying LRC (or tank) circuit. The water cell is the capacitor in the LRC circuit which resonates at the circuits resonant frequency, not the water's resonant frequency. To create hydrogen in this fashion, the water cell capacitor must achieve dielectric breakdown. The self amplifying circuit is what accomplishes this. See v=Ru8YQ6HUwbU&NR=1
@quickshell Just to note, I am in error in this comment as I no longer believe that dielectric breakdown is the force at work here.
quickshell 3 days ago
@ImJacksAmygdala Dielectric breakdown isn't the key. Meyer's patent shows that the electrical charge is literally ripping apart the water molecules when the VIC ( I stress VIC) is at resonance. Specifically the section of the circuit between the charging choke behind the blocking diode and water capacitor. The frequency must be exactly at resonance for the effect to work, not higher, not lower. Meyers had a scanner circuit to scan the water cap to lock his PWM into the resonant frequency.
quickshell 3 days ago
Have you gotten this to produce a lot of HHO gas yet?
Somewhere I read that just frequency, low current, high voltage alone does not just do the job, something else has to be done with the circuit...
RzBusterCB87 2 weeks ago
try 24.7khz resonant frequency of distilled water.
Paul7mac 4 weeks ago
@Paul7mac The resonant frequency of water is not relevant when you consider that the water cell is just a capacitor. Please watch my upcoming video series starting with "What A Capacitor Is".
quickshell 4 weeks ago
I'm interested in determining the minimum wattage required to produce a Meker flame. I understand feed back from the PLL is the key to keep the cell at resonance to restrict the amp flow through the dielectric break down as the cell saturates from a gated stepped pulse. I also think precise coil and core geometries are critical. Knowing the minimum input wattage to sustain a Meker Burner flame would be helpful to refine efficiencies for practical use. I've yet to see anyone attempt this at all.
ImJacksAmygdala 1 month ago in playlist More videos from quickshell
@ImJacksAmygdala I'm inclined to agree. However, my time and experience is limited on the PLL at present. However, it is something that I have been regularly considering and am working on the direction of. Thanks for pointing it out.
quickshell 4 weeks ago
@quickshell This is one of the best videos I know of that explain practical use of the PLL (Phase Lock Loops).
/watch?v=VP1XwIJHkyE
ImJacksAmygdala 4 weeks ago
Please correct me if I am wrong but is the gas production shown in this video a result of 1.2 watts of input power?
ImJacksAmygdala 1 month ago
@ImJacksAmygdala In all honesty, I don't have a very accurate measurement for this particular video. The ammeter I used suggested a current of between 100 and 200 mA, but I believe it's meant to be used for larger applications. I didn't start using my power monitor until later videos. However, I am waiting a new Pyramid power source that monitors voltage and current and will be able to give much better readings for future experiments.
quickshell 1 month ago
Note that at time index 1:23 in watch?v=StV4jkJPnDY that the resonance is being applied to the CIRCUIT, not the water itself. Referring to the dielectric of the water demonstrates a capacitive attribute in a circuit, not specifically an attribute of the water itself. The resonating effect of ANY circuit is dependent on the capacitive effect of the capacitor (in the this case water cell) in the circuit in question. This important to understand in order to properly apply Meyer's technique.
quickshell 1 month ago
@4891chris4891 Oh, and incidentally, I have on previous occasions tuned this circuit to the "known" resonant frequency of water. It did not change the effect. Demonstrating directly that the resonant frequency of the electronic tank circuit is more important than the resonant frequency of the dielectric of the capacitor in the tank circuit (in our case water). Please do some research in the LRC or electronic tank circuits to get a better understand of resonance in electronics.
quickshell 1 month ago
@4891chris4891 One thing that most people miss is that the resonant frequency of water DOES NOT MATTER. This is an electronic tank circuit. Replace the water cell with ANY capacitor and the CIRCUIT will resonate based on that capacitors properties (while destroying the capacitor because that is essentially what this circuit is supposed to do, overload to catastrophic dielectric breakdown). The water cell is simply a capacitor. The resonant frequency of the dielectric is irrelevant.
quickshell 1 month ago
You people are all morons! Whats the resonant frequency of water? look it up. And also the resistance of water changes a lot between temp and pressure. Did you check that?? In the mean time I am going to go bang my skull against the wall..... thanks p.s. you may be the least moronic of them all.
4891chris4891 1 month ago
Have tried distilled.
Overall, my conclusion to date is that gas out is relative to power in. The quantity of oxygen attracted to positive charge is dependant on size of the charge. Likewise for hydrogen for negative charge. The only way to make use of this would be if combustion results in a higher energy output than the equivalent power required to separate the atoms. If anyone knows how to measure the output of combustion with ambient gases by specific quantity, we'd have our answer.
quickshell 1 month ago
Dude use distilled water and see if that works also you will need to update the frequency to giga possibly terahertz range
ohsdrummer1 2 months ago
Use vertical disks that are allowed to spin to slough off the bubbles quicker. (one disk positive the next negative etc. and 13.56 Mhz introduced for the harmonic of sodium)
willienaz333 3 months ago
The space gap between the pipes is apparently very important. I haven't measured the distance between them, but I believe mine are further apart than they should be. I will be trying at some point either plates or tubes that have less of a gap in them.
quickshell 9 months ago
@quickshell Interesting result. Have you tried other frequencies? Like: 18k, 23k or 43k (plus or minus a few hundred Hz) are supposed to be other related resonance frequencies to shatter water. I'd be interested in your results.
I can't remember if those frequencies are accurate as it's been a while since I read them. They are noted in patents, to do with water fracturing/shattering.
Itsmeeman1 9 months ago
@Itsmeeman1 Electrical frequencies do not cause the same effect of sound frequencies. The circuit is a self amplifying LRC (or tank) circuit. The water cell is the capacitor in the LRC circuit which resonates at the circuits resonant frequency, not the water's resonant frequency. To create hydrogen in this fashion, the water cell capacitor must achieve dielectric breakdown. The self amplifying circuit is what accomplishes this. See v=Ru8YQ6HUwbU&NR=1
quickshell 9 months ago
ever try underwater speakers with sound waves?
adam3176 10 months ago
nice ! a very expensive 316 ss .... i love tubes for HHO ....
vox1philippines 1 year ago