do we have an answer yet?
jimu57 2 years ago
Okay here's a hint. Draw out every path and how many ways you can get to each point approaching the final spot.
It should start to look like Pascal's Triangle.
mathprobs 2 years ago
well, I posted a comment again but it disappeared.
1 + (10^1) + (10^2) + (10^3) = 1111 possible paths
That's not the answer we've been getting... I don't think that's the correct way to calculate it..
I'll look again but it seems like it follows that, or close to it.
at least 80
True.. can you provide a more specific answer? :-)
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do we have an answer yet?
jimu57 2 years ago
Okay here's a hint. Draw out every path and how many ways you can get to each point approaching the final spot.
It should start to look like Pascal's Triangle.
mathprobs 2 years ago
well, I posted a comment again but it disappeared.
1 + (10^1) + (10^2) + (10^3) = 1111 possible paths
jimu57 2 years ago
That's not the answer we've been getting... I don't think that's the correct way to calculate it..
mathprobs 2 years ago
I'll look again but it seems like it follows that, or close to it.
jimu57 2 years ago
at least 80
jimu57 2 years ago
True.. can you provide a more specific answer? :-)
mathprobs 2 years ago