Interesting Effect (Possible OverUnity?)

[Max75572]

If you want to get the plans for Overunity Generator?

Go to Google and search for "Top Magnetic Generator" ...

Choose the First Result (Ignore the Advertisements)

[georgeutterpower]

Imagine you had time to make this video, but didn't have time to learn ohms law :-)

you should run for political office in California, they'll love you!

[gconol]

I had this video on my play list for many years. It's only now that I realized the significance of your little experiment. I learned much about radiant spikes since then. Thanks singerz.

[leigh7801]

NOW what you want is to make it give 1000v + at 20+ amp from one 9v. This is what im working on and so far so good, just having trouble collecting the raw power

[leigh7801]

I've been working on the same concept. howevr you have it hooked up wrong, first of all you have 2x9v, each 9volt has about 75watts of power...2x75=150watts..

you had 300milliamp at 500volt, so 500x.300 = 150 To me you are getting out the same amount of power you are putting in (possability that the timer circuit isn't using any power as you're re making it again, so basicly all you have at the end process is the same amou of power you started with.

[PhyUL09]

If you think about what you made a little, can you believe that you will be able to create energy out of nowhere? Overunity is impossible, just like it was 50 or 200 or 500 years ago ... A concerned physicist

[JoelHarvey1]

@PhyUL09 you have been brain washed

[PhyUL09]

@JoelHarvey1 LOL, I'm not brainwashed... If you can come up with a good theoretical basis and run this thing on itself for more than an hour... I will believe you. I only want to say that overunity in electrical circuits have been tried since the 1800's and no one came up with something usable. There is something people usually forget: Their circuit's impedance. Oh and yeah get some education before saying to some1 that he is brainwashed.

[JoelHarvey1]

@PhyUL09 YOU SAID IT IS IMPOSABLE IT IS NOT YOU DO YOUR RESERCH AND OPEN YOUR NARROW MIND

[PhyUL09]

@JoelHarvey1 There are 2 things that bother me in this video in fact: 1. When the guy gets the current intensity he only switches the wire in his multimeter but not on his circuit... A voltmeter and an ammeter do not work the same way and must be plugged differently. That's why he gets such high intensity... an ammeter has a low resistance and he plugs it in parallel like his voltmeter... I = V/R

[PhyUL09]

@JoelHarvey1 2. If this thing can work for a while it must certainly not work forever as it will break the 2nd law of thermodynamics. Since our universe is a closed system (It does work like one as of today...), It's energy tends to equalize everywhere, like hot water in a cold room, it means that creating energy from nothing is impossible and this has been experimented a lot of times since it's discovery in the 1800's. Oh and I certainly do my researches since I study physics...

[JoelHarvey1]

@PhyUL09 THE UNIVERSE IS AN OPEN SYSTEM DO YOUR RESEARCH

L.C TOM BEARDEN

[PhyUL09]

@JoelHarvey1 Yeah the universe is flat I agree, but what I meant is that it's entropy always increase... there is no input of energy possible, except in some yet to be proven weird string theory effect(Which would be very great if true), which would also have created the universe, but in any ways the energy input in a flat universe is kinda very brutal and would not happen through the electromagnetic force that's for sure (It's too weak at high energies, think about plasmas).

[JoelHarvey1]

@PhyUL09 im not saying it works i'm saying that you are thinking inside the box and that education system is brain washing the masses to control them. do some research on JOHN bedini. DONT TAKE OTHER FILIP ON IT.

NIKOLA TESLA IS ANOTHER ON. OH AND EINSTEIN IS ANOTHER TOO ALL SUPPORT THE FREE FLOW OF ENERGY. EINSTEIN CONCLUDED THER IS AN EITHER

[PhyUL09]

@JoelHarvey1 I'm sorry but about Einstein and the ether you are wrong. Einstein's relativity is based on the fact that the speed of light is the same in every frame of reference, which would not be true if there was an ether since objects could actually break the speed of light just like airplanes break the speed of sound. I'm also sorry to inform you that all that I learned have been presented to me with rigorous mathematical demonstrations based on experimental facts...

[stefb2005]

Hi singerxyz , I have also been experamenting with transformers, and from what i understand ,it seems to be very high voltage needed and then stepped down again to get a gain in output , it may be that it also needs to resonate at a given frequency .

I feel frequency plays a major part , but what frequency and voltage i do not no.

Did you try stepping down the voltage with a transformer at the other end ? (probebly a silly question !) Good luck.stefb2005

[IST814]

: )  I WILL DUPLICATE IT

just saw it today

IST

[vpo20]

You got a high voltage first with almost no current: => power is small. Then you got a high current with almost no voltage => power is again small. They should act at the same very moment of time. Definition of power is integral of product of momentary voltage by momentary current taken over interval of time of one second. It is common to see high current and high voltage at separate moment of time but power is small at any given moment of time. Transistor switches in modern pow. supp do this.

[Aerosteon]

You're not using you're multimeter properly. A voltmeter needs to be in parallel with the circuits load, otherwise all you're doing is measuring the voltage drop across the internal resistance of the voltmeter.

[smilisav]

When you turn to voltmeter you don't have amperage. When you turn to ampermeter, you don't have voltage. For real measurement put strong resistor with no reactanse and measure voltage on it, then calculate power by dividing sqared voltage by resistance. You will get a completely different rezult, which is in fact real rezult.

[215858452845]

Seems like you could replace the batteries with capacitors and run the output to the capacitors. If that works then you definitely have over unity.

[tjamassey]

You need a scope to look at the waveforms but I suspect that you are measuring power wrong. When voltage is pulsed it can fool multimeters. You need a wide-bandwidth system (expensive) where you sample voltage and current. You cannot get out more power than you put in. Don't even try! if you were right then collect your Nobel prize!

[challenger159]

Use 5 lightbulbs in seriesas the load , so each one has 100 or so volts. If it works, let it run as long as it gets. If the 2 batteries can charge it for more than a moment then it's overunity.

[ZincFold]

See "Self Running 35 Watt Delay Line Generator!" video.

[ZincFold]

Thanks for sharing. This approach shows a lot of potential. Keep up the good work.

Cheers.

[ZincFold]

The collapsing EMF spike in the powering coil has a reverse charge which can be extracted via a diode. I found though that tapping into this collapsing EMF spike drops output of second pick up coil which otherwise provides a higher spike. I think this is related to Bedini and Bearden research. Hold an LED pin and other pin to transformer metal casing to see induction. Instead of rotating magnets to create MF pulsing, this setup seems more efficient with no moving parts if pulsing circuit used.

[ZincFold]

High voltage output alternating spike is used to pulse charge two 12v motor bike batteries still need to try charging a 6 volt battery from 12v batteries to feed back into input. Square pulsing frequency needs fine tuning to different coil size. I'm still using a physical switch mechanism for my pulsing. On the lookout for a good simple square pulsing circuit. Be very careful the higher the pulsing voltage the higher output. VERY HIGH VOLTAGE!!! I put 12v in and got spiking over 1000v

[ZincFold]

I have a similar setup. I got low voltage 5v pulsing through the low voltage coil of the transformer. I get an average of 410v off the second coil. The charge coming out second coil is electrostatic in nature. bring the wires close enough creates a jumping spark which alternates to EMF creation and collapse.

digital voltmeter can pick up electrostatic discharge in air. Square wave pulsing works better then sine type wave. Sharp on & off very important.

[Redogful]

Your measures data result like this:

Open voltage =500V, but current =0A, resultant=500V x 0A=0W and

Short circuit current=220mA but the loaded voltage almost=0V, resultant 0.22A x 0V=0W

Can you make the data with loaded current and voltage?

[electra]

Yep, that's overunity allright. Alien technology actually, I got one in my car, it runs on water.

[stephenawolfe]

I have a 50,000 volt taser that takes a 9 volt battery. Re-wire your setup to run itself indefinately, after disconnecting the batteries, and I'll call it overunity.

[morpher44]

Yes .. I agree with those who say that you need to measure this sucker when there is a load present. So put a load on their like a 40watt bulb or something ... then measure current/voltage. Waveform duty cycle is key.

[canadiancarfashion]

it looks like you are not using the primary side of transformer but u mentioned it was the secondary side u were not using please check it again and let us know thanks great job on the circuit

[twitchd8]

it's the primary side that he is not using... I've used one of those exact center-tapped transformers to make a +/- 12 volt DC power supply in Electronics at my college...

[prototype9000]

ive fried multimeters with similar circuits they dont like high frequency or high voltage inductive kick backs epecially both at the same time

[Rotitomato]

You're definetly getting a voltage spike with the collapsing magnetic field, the current collapses a lot faster than the voltage. If the current hits a very high resistance upon collapsing(I believe it's your bridge rectifyer) you also produce a high power output. So for a split nanosecond your getting a power spike at least that's the theory. I'd like to reproduce your experiment if you would send me a schematic, please!

[pknaack1]

you are using your multimeter incorrectly. when measuring voltage, you have no load, so the voltage is high. when measuring current, your meter IS the load (you're effectively shorting the power supply thru the meter), so the voltage drops. instead use two meters and a separate resistive load. measure voltage across the load, the other in series to measure current from supply to load. do this to both the load and battery. discover more watts of power going in than coming out. not over-unity.

[kjpdqpb]

Yup. You definitely need to change where the leads sit for an accurate current reading. Voltage readings are taken across a component, current is taken by forcing the current through the multimeter by making the multimeter act as a wire in series with the circuit.

[fu2ah]

mammamca (seven months ago) has some great points on parameters!!!!!

you also need to look at duty cycles and waveforms, probably not power factors.

Basic electronics can be very tricky, especially if you have been mislead by free energy youtubers.

I got half an associate diploma in electronics, 20 years ago, and dont quite understand what you have done.

RE: 4:40 "Good luck, peace"

Good luck and peace to you too buddy.

[livelounge106]

This appears a similar system to how a car ignition coil works, by stopping the flow of current, a hige back spike is produced by the coil in the transformer. have you tried putting the (unrectified) output from this into another transformer to reduce the voltage and step up the current, then put the rectifier on the low voltage output, to get dc

[Nonetub]

Of course... Finally this experiment is claimed as Overunity or not?

[massoonmann]

yer not even close dude...

[dallasgoldbug]

You might want to use something other than the alkaline 9v batteries. They tend to resist giving up their current from time to time. Anyone out there experience this?

[Paz4254]

As other posters have pointed out, the volt/ammeter is absolutely the wrong instrument. In every video claiming overunity you see someone using a VOM as proof. You are not measuring rectified DC, but a waveform. It probably looks a lot like some sort of saw tooth waveform. You need an oscilloscope. You need the amplitude and period of the voltage and current to calculate the actual power. I'm guessing it's less than the input.

[alextrem24]

That's right the digital ampmeter measure the maximum of the amp, not the average because of the wave form.

The proof is that you need about 160 watts just to powered a tiny neon light which is ridiculous.

Don't trus the digital ampmeter when you measured strange waveform.

THIS IS NOT OVERUNITY this is just a measurement mistake

[living4game]

Maybe Touch the wires or lick the cable contacts how is shocking :) this is best measurement i can say :)

[pknaack1]

his biggest mistake was assuming that the voltage stays the same when he switches the meter over to measure amps. because the meter itself is shorting out the output, the voltage will drop to near 0. so yes, he can get 300v, or he can get 300mA, but not both at the same time, so definitely NOT over-unity.

[jerktrucker]

If you put a maximum load directly to the batteries or just short out the batteries with an ammeter and measure the current then calculate the power and you will see more power than your getting with all that other junk connected. Now were talking free energy and you can easily show that there is nothing plugged into the wall!!!!!

[mammamca]

eugneo1111 is half right. From the information (if correct) you can find the Thevenin parameters...

test1 (open circuit) v = 500V and I = 0A

test2 (short circuit) v = 0 and I = 0.250A

there for internal resistance is:

250V/0.125A = 2kohm

and maximum power is:

250V*0.125A = 31,25W

and of course the presented system never do any work. If you add a load of 2Kohm (that can support 31.25W) it will be at peak efficiency, and your battery will be drained in no time

[eugeneo1111]

You are almost shorting the output so P=IV

where I=250ma and V=almost 0

So P= almost 0

[overunitydotcom]

Please try to hook up an 8 Watts fluorescent tube directly to your output ( In parallel with your blue cap) and you could probably light it up

pretty nicely...

Good luck.

Regards, Stefan.

[billwcali]

unfortunately open circuit voltage doesnt equal useable power - as others say you need to measure under load use any load like may be a large (high wattage) resistor, maybe 200 ohms - then measure the voltage across the resistor and the current through it - you can buy a coupel of resitors for low cost at radio shack

[jordyx]

Let say you obtained about 500V x 0.25A = 125W

You should use 5 x 30W/110vac incandescent light bulbs connected in series as a load. If the bulbs does not light up you don't have 0.25A. Try to measure the output voltage with the light bulbs connected. Add the ampermeter in series with the bulbs to measure the current and update us with your findings. Good Luck.

[WisdomVendor]

In any circuit that contains any signal other than pure dc, you can't get an accurate volt or amp reading with a multimeter. You have to have an oscilloscope to see the actual signal to be able to find the duty cycle of that signal. Then you can calculate the power involved.

[primaer]

It looks like you are hooking up an ammeter without a load? That's a good way to blow an ammeter fuse.

[klexn]

That's not overunity.. You're not going to have 500+ volts with a 250ma load.. You're Power figures are all fucked up.. Throw a resistor across it, measure your voltage across the R, figure I, then mult I x V = P (Watts).. Measure input power and calculate P (Watts) and you'll come up short on the other side of the transformer by quite a bit.. 1N4001 diodes steal a bit of power ya know.. =) Study slew rates of semiconductors.

[singerxyz]

You're right- I now know more about measuring current than I did when I made this video. I keep it posted for the sake of the circuit. I'll update when I get the chance.

[Drevtoobe]

Nothing unusual is going on here. So many free energy thinkers know next to nothing about electronics. Take a few courses!

[Dragonfire7666]

Thank you. The cap doesn't addd a "kick" in that configuration. It acts as a filter.

[hyperkinetic]

Could you please post the manufacturer and model of the timer you're using? I tried googling, but came up dry.

[Blennophobic]

cont'd

PF is cosine(angle between voltage and current wave). Reactive power (VAR) is voltage x current x sine(angle between the voltage and current). Apparent power is the vector sum of real power and reactive power.

Cheers,

SI (P.Eng.)

[Blennophobic]

In engineering terms what you're measuring is apparent power or volt-amps (VA). In simple DC circuits, power is equal to voltage times current. Since you've introduced switching, now you're dealing with alternating current (AC) circuit rules. Real Power (watts) is equal to voltage times current times power factor.

[heruursciences]

What you did is build a vibrator HV induction power supply. These used to power a model t's spark plugs. The transformer stores energy in a magnetic field, when current is interrupted it spikes current and voltage limited by the time for the core to demagnetize and the resistance of the coil, however time component is compressed. The over unity effect is an artifact from the way the digatal meter samples current. It's actually far less than unity.

[athews1976]

Hey, look up RMS(root mean square) do some reseach. To prove overunity you have to prove that your power output under a work load is consistent.

[wildhart7]

lol i suggested that to camster6 waaaaay before this experiment! NOOB ripping off my ideas!!!

[gabydewilde]

I think you are measuring the voltage on a charged cap. The amperage you see is from a short circuit. You are however on the right track. :) Should try to make the pulse with empty batteries. That way you know you are not drawing any amps. Empty batteries stay empty for a very long time. Very reliable. lol

[singerxyz]

Thanks for the response- Not sure what you mean by "make the pulse with batteries"?

[Dragonfire7666]

That's good work. You have to take in account the volt meter your useing, find an old simpson and measure your voltage with that. You'll see the results will be different. The increase in voltage you are receiving is caused by the spike in your dc wave and the anti-current from the transformer. To up the current you should use a secondary winding to decrease the voltage.

[SoulAnimated]

if you decide to follow up, please get ready to see smoke and sparks.

so you show 500v 1/4 amp. if that's true, you have 125w. five 30w/110vac light bulbs in series should be lit with that power.

[athews1976]

You need an ocilascope. Because of RMS(root mean square) you need to see how consitent your output is under heavy loads. But you're on the right track. That kick you talkin' bout is back EMF(Back electromotive force). that's what we think the crude way of taping the so called zero point field.

[LONECOW1210]

Not to be a total downer but you measured either voltage or current wrong. Voltage is measured in parallel to the load and current is measured in series with the load so without changing the configuration of your circuit you cant measure both voltage and current.

[singerxyz]

The probably the current is wrong- I'm new at this stuff.

But please try it yourself, too! It'll cost about $30 US. You can even just get a transformer for @ $10 wire it as shown and tap it on a battery to test it

[youtuubbguy66]

If i'm correct, to mesure correctly both you should....Leave the lamp on the circuit.

To read the voltage simply use your multi-meter on both end of the lamp.

To read you amps, unplug one of the end of the lamp and make the current pass through your meter and then in the lamp or in the lamp then in your meter.

[hyperkinetic]

The lamp he's using is a bad choice. Gas discharge lamps don't provide a constant load and change characteristics while warming up and vary with frequency of the driving voltage as well. Better to use carbon resistor or other non-inductive load.

[TinselTownRebel]

Hi, there!

First of all, if you ever come across something which looks like over unity, you can start from the assumption that something is wrong in your setup.

Since you are producing pulses and not DC or sinewave AC the multimeter will definately show incorrect readings! Do not be surprised if the error is several 100%.

The instrument is build from some basic assumptions on the input signal, and the generated pulses does not fit into those assumptions.

[TinselTownRebel]

Preferably, you should use an oscilloscope to find out what the signal really looks like.

The math for calculating the power now becomes much more complex, since you have to integrate the voltage and current over a period of time.

You could also try to see if the setup is able to power one or several suitable lightbulbs. (The voltage tester does not use a fraction of the power that you claim to produce.) This is by far the fastest way to see that you are wrong in your over unity assumption.

[singerxyz]

I don't know what's going on, honestly. Effect only happens using short "tap" on power- with continuous power, no volts at all on meter. Also noticed slight stinging on skin standing near the unit. But when tested with resistors (10 ohm, 100 ohm, 1000 ohm) meter reads hardly any current, yet sparks jump when the leads are to close together, or change the meter lead to amps (as in video) Might be radiant energy unusable by most equipment, or just a bad meter reading- who knows

[TinselTownRebel]

The coil (transformer) basically is "reluctant" to changes in the current flowing through it.

During the active state of the pulse, the circuit forces the coil to a certain current.

During the "off" phase of the pulse, the impedance of the circuit appears as high for the coil. This leads to a very high voltage across the coil, since it tries to feed the same current as it did previously during the active phase of the pulse.

This explains the sparks and the high voltage.

[gconol]

it's pretty odd that a transformer can produce more energy than it's given. It would probably best to test the output while it's under a load. Measure both the voltage and the current at the same time too when your device is running something like that tester(bulb).

Just in case you are right with your assumption, the best way I know to reduce the voltage to a useable amount and increase the current is to use a Step-down transformer.

Good luck.

[valveman12]

A transformer does not produce more energy than it's given. This absolutely incorrect! In fact a transformer is less than 100% efficient. The voltage may be high but the current is very low. There is always a tradeoff.

[manriquea]

I think you measured your ouput wrong. You measured voltage and amperage seperately, you need to measure them at the same time. It is a comon mistake many make, I have done it myself.

[singerxyz]

How?

[hyperkinetic]

You need to attach a constant load, like a resistor. The neon lamp in you tester will not work because it's load changes at startup, and with temperature as the lamp warms. Plus the gas inside excites easier the higher the frequency AC or pulsed DC hitting it. Use a resistor instead. Measure across it for voltage, and in series with it to measure current.

[gabydewilde]

nice one, I've seen one guy do this with dead batteries. Will send you the link when I find it. :-)

go-here. nl

[seshkanuri]

Fantastic. Great video.