LOL! so many people don't get it. It was obvious from the first video that something had to be a trick. It is impossible to arrange the pieces in ANY way and make them occupy a different total surface. The shape may change but never the area. Thanks for posting!
Good job. You saved me the time of getting a printout and doing the maths myself. I was hoping there was maths behind this rather than it be some cheat/illusion.
The answer lies in the fact that the bottom slope of your top top triangle does not and will never fit perfectly on top of the 2 combined top slopes of the 2 big pieces beneath it in the rearranged combination.
@thatubeman2008 sigh. The bottom part sticks out because of the slope you are trying to fit. Go google "The Triangle Problem or What's Wrong with the Obvious Truth" or get a maths degree.
@pjn2001 Did you even watch the video that this one is replying to? Did you read my description? I found your "The Triangle problem" before I ever posted this video. In the triangle problem the pieces aren't restricted to a set border or frame like in "impossible puzzle", So your eyes trick you into thinking they are straight (does not apply to this puzzle). In this puzzle the pieces ARE STRAIGHT ( I cut them). Therefore the ONLY solution to my puzzle is what I have shown and described.
Simple. Area wen't from 2x4=8 to 3x3=9 so a 1in^2 area remains. The perimeter remained constant from 2x2+4x2=12 to 3x4=12. that means the area taken up by the bottom right did not affect the surrounding pieces consumed area. Neat trick though....:-)
great job.....I'm amazed at how many people make this harder than it is. The actual pieces make up a certain surface area. In the first polygon (made up of all the pieces) the total surface area is less than the second polygon(made up of all the pieces plus the empty space). Therefore the perimeters of both polygons cannot be equal. In other words, the outside shape can't be the same in both instances.
In calculus, you can integrate your functions to get the area (rate of change/position). But if you have no initial condition, you have infinite number of solutions. This puzzle has 4 solutions where all the pieces fit (including upside down).
In calculus, you can integrate your functions to get the area (rate of change/position). But if you have no initial condition, you have infinite number of solutions. This puzzle has 4 solutions where all the pieces fit (including upside down).
This comment has received too many negative votesshow
WRONG. This is simple to explain it's all about the rate of change and postition (calculus). The right edge of the largest piece is short. The left edge of the largest piece is longer (including the slant). When the object moves right, you are covering up less space and creating more space. So your rate of change is positive..so you create more empty space. When you move the piece left, you are covering more space and create less, so your rate of change is negative.
@jwh424 Sorry, but I don't think you understand the point to this video. Basically it is IMPOSSIBLE to change the surface area of a puzzle just by moving the pieces around. If you haven't yet, read the video description.
@thatubeman2008 I think you are correct in your explanation of the puzzle. I just watched the original video for a second time, and when he puts the last 2 pieces in the second time, he has to "force" them pretty hard, and it looks like they are made of some type of spongy material which allow them to "give" slightly. This makes it appear as some type of camera trick which allows the creation of the "free space".
@jwh424 are you trying to say that when you move the largest peice in a direction it takes up less space ;-)
or Are you just pointing out the obviuos that the bottom edge of the largest peice is longer then the other and the left side of the second bigest piece not including the slant is shorter then the left edge not including the slant of the biggest peice.
That said the area the peices cover does not change calculus new math or whatever.
@jwh424 are you trying to say that when you move the largest peice in a direction it takes up less space ;-)
or Are you just pointing out the obviuos that the bottom edge of the largest peice is longer then the other and the left side of the second bigest piece not including the slant is shorter then the left edge not including the slant of the biggest peice.
That said the area the peices cover does not change calculus new math or whatever.
@jwh424 are you trying to say that when you move the largest peice in a direction it takes up less space ;-)
or Are you just pointing out the obviuos that the bottom edge of the largest peice is longer then the other and the left side of the second bigest piece not including the slant is shorter then the left edge not including the slant of the biggest peice.
That said the area the peices cover does not change calculus new math or whatever.
@jwh424: Uhhh V = a + b + c + d + e where a-e represent the volumes of each piece. If a, b, c, d, and e all remain constant, which they do, V remains constant. Don't try to pretend you understand something you don't.
@windwitch1 - I think the height of each piece is kept constant, so we can treat the system as Area, not Volume. In that case, I agree with you. Area is kept constant throughout the whole process.
you've got the right idea, no space magically "appears", but the puzzle works by the angle of the slope on the two triangular-square pieces. A very small change in the angle equates to a very different surface area.
I did the same thing, only that the extra space was to the left rather than below, still the same thing. I'm still trying to get exact measurements so I can mathematically prove this but using the ruler tool in PS is not very accurate.
Although this puzzle and its 'impossible solution' are now exposed, the same principle does not apply to this puzzle.
Extremely fitting music bro.
GrtrThnClnD 3 days ago
Do you actually have two hands, or you 're missing your left one?
vassdel 2 weeks ago
if anyone's still reading this...the L's were against each other l=l not l_ -l i don't think it's a mystery
thumper409 3 weeks ago
BRAVO!
raymondduncan01 1 month ago
NAME OF SONG!!!!!!!!!!!
CrashDrumz 2 months ago
SSOOONGGG!! FUCK!! SONG!!!!
CrashDrumz 2 months ago
very easy
Raajao2 2 months ago
Song?!?!?!
TheLolilol321 3 months ago
LOL! so many people don't get it. It was obvious from the first video that something had to be a trick. It is impossible to arrange the pieces in ANY way and make them occupy a different total surface. The shape may change but never the area. Thanks for posting!
Grafight23 3 months ago
Song please?
RocknLee 5 months ago
I noticed in the origonal video that he put extra force into getting that last piece to fit, so I agree that this explains how that hole appeared.
aether222 6 months ago
Good job. You saved me the time of getting a printout and doing the maths myself. I was hoping there was maths behind this rather than it be some cheat/illusion.
hassanvoyeau 9 months ago
YOU CHANGED THE LENGTH OF THE TWO BOTTOM PIECES ITS FAKE!!!
2coastercrazy 10 months ago
@2coastercrazy
idiot he didn't change anything. And it's supposed to be fake, that's the whole point. He's showing it is impossible.
LAOJoe09 9 months ago
@LAOJoe09 sorry! calm down. i didnt know, im ten
2coastercrazy 9 months ago
The answer lies in the fact that the bottom slope of your top top triangle does not and will never fit perfectly on top of the 2 combined top slopes of the 2 big pieces beneath it in the rearranged combination.
pjn2001 1 year ago
@pjn2001 Sorry but my example has nothing to do with the slope on top. These pieces could be cut PERFECT and you would get the same result.
thatubeman2008 1 year ago 6
@thatubeman2008 sigh. The bottom part sticks out because of the slope you are trying to fit. Go google "The Triangle Problem or What's Wrong with the Obvious Truth" or get a maths degree.
pjn2001 1 year ago
@pjn2001 Did you even watch the video that this one is replying to? Did you read my description? I found your "The Triangle problem" before I ever posted this video. In the triangle problem the pieces aren't restricted to a set border or frame like in "impossible puzzle", So your eyes trick you into thinking they are straight (does not apply to this puzzle). In this puzzle the pieces ARE STRAIGHT ( I cut them). Therefore the ONLY solution to my puzzle is what I have shown and described.
thatubeman2008 1 year ago
yes, but if you look at the bottom right corner, you'll notice it isn't exactly lined up with the rest of the paper.
nerfgunuser 1 year ago
@nerfgunuser witch is where the empty space comes from!!!!
thatubeman2008 1 year ago 5
@thatubeman2008 i feel your pain.
juliusdamonkey 7 months ago
@thatubeman2008 you should make a video and cut that second into 3s and fit it in the hole to shut people up.
freakin1random 6 months ago
Simple. Area wen't from 2x4=8 to 3x3=9 so a 1in^2 area remains. The perimeter remained constant from 2x2+4x2=12 to 3x4=12. that means the area taken up by the bottom right did not affect the surrounding pieces consumed area. Neat trick though....:-)
Mjaeger72 1 year ago
Yea this is definitely wrong. You missed the mark with this puzzle.
SeraphsWitness 1 year ago
great job.....I'm amazed at how many people make this harder than it is. The actual pieces make up a certain surface area. In the first polygon (made up of all the pieces) the total surface area is less than the second polygon(made up of all the pieces plus the empty space). Therefore the perimeters of both polygons cannot be equal. In other words, the outside shape can't be the same in both instances.
JUMPINGJIMBRUNZEL 1 year ago
so, in simple language, in the original the pieces are not metal or wodden so they compact, easy as that.
GnlMachoman 1 year ago
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In calculus, you can integrate your functions to get the area (rate of change/position). But if you have no initial condition, you have infinite number of solutions. This puzzle has 4 solutions where all the pieces fit (including upside down).
jwh424 1 year ago
This has been flagged as spam show
In calculus, you can integrate your functions to get the area (rate of change/position). But if you have no initial condition, you have infinite number of solutions. This puzzle has 4 solutions where all the pieces fit (including upside down).
jwh424 1 year ago
This comment has received too many negative votes show
WRONG. This is simple to explain it's all about the rate of change and postition (calculus). The right edge of the largest piece is short. The left edge of the largest piece is longer (including the slant). When the object moves right, you are covering up less space and creating more space. So your rate of change is positive..so you create more empty space. When you move the piece left, you are covering more space and create less, so your rate of change is negative.
jwh424 1 year ago
@jwh424 Sorry, but I don't think you understand the point to this video. Basically it is IMPOSSIBLE to change the surface area of a puzzle just by moving the pieces around. If you haven't yet, read the video description.
thatubeman2008 1 year ago 12
@thatubeman2008 I think you are correct in your explanation of the puzzle. I just watched the original video for a second time, and when he puts the last 2 pieces in the second time, he has to "force" them pretty hard, and it looks like they are made of some type of spongy material which allow them to "give" slightly. This makes it appear as some type of camera trick which allows the creation of the "free space".
clintonearlwalker 1 year ago
@jwh424 are you trying to say that when you move the largest peice in a direction it takes up less space ;-)
or Are you just pointing out the obviuos that the bottom edge of the largest peice is longer then the other and the left side of the second bigest piece not including the slant is shorter then the left edge not including the slant of the biggest peice.
That said the area the peices cover does not change calculus new math or whatever.
reigh7 1 year ago
@jwh424 are you trying to say that when you move the largest peice in a direction it takes up less space ;-)
or Are you just pointing out the obviuos that the bottom edge of the largest peice is longer then the other and the left side of the second bigest piece not including the slant is shorter then the left edge not including the slant of the biggest peice.
That said the area the peices cover does not change calculus new math or whatever.
reigh7 1 year ago
This has been flagged as spam show
@jwh424 are you trying to say that when you move the largest peice in a direction it takes up less space ;-)
or Are you just pointing out the obviuos that the bottom edge of the largest peice is longer then the other and the left side of the second bigest piece not including the slant is shorter then the left edge not including the slant of the biggest peice.
That said the area the peices cover does not change calculus new math or whatever.
reigh7 1 year ago
@jwh424: Uhhh V = a + b + c + d + e where a-e represent the volumes of each piece. If a, b, c, d, and e all remain constant, which they do, V remains constant. Don't try to pretend you understand something you don't.
windwitch1 1 year ago
@windwitch1 - I think the height of each piece is kept constant, so we can treat the system as Area, not Volume. In that case, I agree with you. Area is kept constant throughout the whole process.
SwiftCuber 1 year ago
@jwh424 - Shouldn't the total area be constant no matter the change in the length and width?
SwiftCuber 1 year ago
this is a perfect and clear demonstration. Great! I believe that this is actually how it works
advance467 1 year ago
retarded song
ruisir1 1 year ago
ahha,so,they squeezed it into the external shape in the other video when they moved the shape pieces around.........ty
dawggonecrazee 1 year ago
not that interesting... but i do understand it
Den1sVengeance 1 year ago
THANK YOU
Starrz88 1 year ago
you've got the right idea, no space magically "appears", but the puzzle works by the angle of the slope on the two triangular-square pieces. A very small change in the angle equates to a very different surface area.
imajackastro 1 year ago
@imajackastro yea right
imgordonfreeman 1 year ago
I did the same thing, only that the extra space was to the left rather than below, still the same thing. I'm still trying to get exact measurements so I can mathematically prove this but using the ruler tool in PS is not very accurate.
Although this puzzle and its 'impossible solution' are now exposed, the same principle does not apply to this puzzle.
img185.imageshack.us/img185/3108/magicpuzzle.gif
Let me know if you come up with a solution.
Good luck!
Ro2006Ro 1 year ago
@Ro2006Ro I'm not so sure if I solved it or not but
if u add the area of every block
12 + 5 + 7 + 8 ( you can calculate it for yourself )
it's equal to 32
now if you get the area of the triangle
(13 x 5)/2 = 32.5
o_O that 0.5 extra space is hidden in the first one on the hypo but in the second one, it is expanded to 1 and hidden.
perm1992 1 year ago
@Ro2006Ro
your link says 404 NF
advance467 1 year ago
Sad
MrBlobby360 1 year ago