Fourier Series - Parsevals theorem

[roflcoptergoswoosh]

The coefficients for the fourier series of an should be 4(-1)^n/n^2 not n+1 (5:28), set be back an hour trying to figure out was I was doing wrong.

[mebinsebastaian]

as t^2 is even bn is zero,

[mebinsebastaian]

as t^2 is even bn is zero,

[yasthatsme]

Why didn't you calculate bn? I must have missed something...

[burny1]

@yasthatsme its about 5 minutes in. Because fourier is estimate for line t^2 is a graph like \./ (.=origin) and since cos is like \/\./\/\ and sin is like \/\/.\/\/ it makes sense that bn is not needed. I also think its something to do with odd and even functions but i cant remember that much.

[LadislauFernandes]

@yasthatsme , the Fourier series of an even function contains only cosines, i.e., f(x) = a_0/2 + \suma_ncos(nx) and the Fourier Series of an odd function contains only sines. t^2 is even.

[tranqilopapa]

thanks from chile, i have a test at 7pm! :)

[sanaz25600]

thanks

[VliegtuigFan]

Excellent.. thanks mate

[IslamUSA1]

Good job!