calculus fundamental theorem part ii proof (1 of 2)

[xheather492]

Why does this guy remind me of Donkey Kong?

[byte1988]

you are awesome! you dont look like a math teacher, dont dress like a math teacher, but you know exactly what you are talking about.. I give me respect! :)

[bangalirussian]

for real this guy doesnt look like a math teacher. he looks more like a physical ed teacher!!!

[naix319]

this guy scares me he is really built

[nawidayima]

Really nice proof!

[nawidayima]

It should just be little f(x) in the mean value theorem, not f prime f'(x), because he already defined f(x) to be the derivative of F(x).

MISTAKE!!!! DUMBASS!!!!

[Jazzwoman1985]

hi,

where is fundamental theorem part i discussed

[onlynumbersas]

jeez calculus its so easy its for infants. the real stuff comes with stochastic calculus up to ito calculus.

[johnbrz]

Yeah, he means F'(c), which would mean f(c).

[Calculusman08]

No, F'(c) is the derivative notation. f(c) means a function defined by c.

[mildcheddarcheese]

"Let f(x) = d/dx(F(x))"

As far as I can tell that's the same thing as "Let f(x) = F'(x)" where x could be any number, including c. If I'm wrong, I'd like to know, it will help me in the future.

[Calculusman08]

Oh, ok. Well, yes then. I'm sure it could be equal to c, it's just a 'dummy variable'. No matter what the function is defined as, the variable shouldn't matter, as long as the funcion notation is correct. If you need anything just let me know mildcheddarcheese.

[novatodeguitarra]

you're right it can be c actually f(c)=F'(c) but the thing is that the c you're lookin for is the one where f(c)=F'(c) but also = [F(a)-F(b)]/[b-a]

[kossmikham]

At 3:19, I believe f'(c) should be F'(c). Otherwise it would be the second derivative of F(c). Maybe you did mean F'(c), but it looks like f'(c).

[dkitov]

It is wonderful knowing people do explain things like that!