Here's what I don't get. It's always explained that for the function e^x the y value is equal to the slope, but this only matters if your base is e, so you can mainly forget about that. The more useful property, as I see it is that if f'(x) = kf(x), e^k = your base. This is what the natural logarith does, but inverted but no one mentions the relationship between e, k, and b. This would seem more relavent and I don't really no why e^k = b, because no one brings this up.
Excellent presentation. Always more than one way to skin a cat. If I remember correctly, I think my calc I proff. started with the intergral of 1/x to arrive at e. But that was a long time ago. Thanks again.
thanks for the help its good to get two perspectives on this
SDCrow 4 months ago
I meant Einstein
MrCarsandstuff 5 months ago
Wow poor leohnard if he didn't have eye problems he would have been as famous as entein
MrCarsandstuff 5 months ago
Here's what I don't get. It's always explained that for the function e^x the y value is equal to the slope, but this only matters if your base is e, so you can mainly forget about that. The more useful property, as I see it is that if f'(x) = kf(x), e^k = your base. This is what the natural logarith does, but inverted but no one mentions the relationship between e, k, and b. This would seem more relavent and I don't really no why e^k = b, because no one brings this up.
DarthHater100 9 months ago
Excellent presentation. Always more than one way to skin a cat. If I remember correctly, I think my calc I proff. started with the intergral of 1/x to arrive at e. But that was a long time ago. Thanks again.
Haizeron 1 year ago