Added: 3 years ago
From: redrockscc
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  • Can you help me with this please: xy-z=yz for y

  • OHMYGOD. Thank you sooo much, i was having a really hard time on my math h.w & this really helped! (:

  • why are all the good teachers on youtube and the complicated ones in my school

  • Thanks SO much

  • what about a variable that dosent have any numbers Ex.

    y = mx + b solving for m is this even possible???

  • These videos have helped me SO much!

    Thank you again!!!!!!!!!!!

  • thanks man i have a math exam tomorrow and i was goin through review u saved the day

  • 2 questions:

    F = T - Mg

    Why is the "T" eradicated first instead of M?

    How/ why does M become a negative?

  • What if you have the same variable to solve for on both sides of the =? How do you know which side to solve for the variable?

  • could you help me with this please? -3x + b = 6x solve for x i dont understand it completley

  • Thanks man :)

  • THANK YOU so much.!

    Your video helped me ALOT when it came to the elementary algebra on the accuplacer test..!

  • Hey, I'm havinbg problems with my math homework. What is (2b)^-5?

  • can you show how to do a problem like this can you show like 3 or so I am really having a hard time with this and I really appreciate it I love the way you teach my teacher is ugh!

    2[-(x-1)+4]=5+[-(6x-7)+9x]

  • nice, thanks again

  • Can you help me with this equation:

    u=F(P/T-E)

  • Sure! What variable do you need to solve for?

  • Here:

    u=F(P/T-E)

  • Do you need to solve for E, T, P of F?

  • Solve for P

  • Cool so if we distribute F, we get

    u = F*P/T - E*F

    Now, there's only one term with P in it - get that term by itself by adding E*F.

    u + E*F = F*P/T

    Now, we just have to multiply by T and divide by F to solve for P:

    T/F(u + EF) = P

    You can distribute the T/F if you want to, but we solved for P, so the problem is finished!

    Just a note: This problem is very different if it's

    u = F(P/(T-E))

  • Thanks alot.

  • So let's say the equation was

    2xy + xz = 4

    and we're solving for x. Since we have all of the x's on the same side of the equation, we can factor out an x.

    x(2y + z) = 4

    Now to solve for x, we can divide by the factor in parentheses:

    x = 4 / (2y + z)

  • What if there are two terms with the same variable?

    PS: Reply BEFORE the 23 of September, thanks!

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