Aromatic Compounds and Huckel's Rule

[JoeSuperSakic]

This man is a god

[ayumi149]

Thank you. It's very easy to understand. But I think you forgot to emphasize the fact that "n" must be integers according to huckel's rule for it to be aromatic.

[shatta4ever]

شكرا

[creamsoda20090]

@sohc287 Any natural number (any integer zero or greater).

[sohc287]

WTF is "n"?

[bosniaandsarajevo]

Where is the correction video?

[ilianadeedee]

never mind i guess you set the variable n=1,2 etc. and your pi e' have to equal on eof those numbers...

[ilianadeedee]

omg what is N ??? i get everything else but what is "n" where do you get the 'n' number

[herpderpmonkey]

Can someone answer: why can't you call this cyclohex-1,3,5-ene? Which video do I watch for resonance nomenclature?

[ShotandBotched]

@herpderpmonkey I'm going to assume you meant to say cyclohexa-1,3,5-triene. You COULD call it that, but not only is benzene much easier to convey to fellow chemists but it's IUPAC accepted as well.

[herpderpmonkey]

@ShotandBotched thanks mate :D

[jessyjessy4]

great video thanks

[staranjela]

good work here

[TheKcsmithy]

brilliant video

[kourosh89]

I thought of a good way of remembering Huckel's rule.

4n+2=2(2n+1)

2n+1 is just any odd number, so 2(2n+1) is just an odd number doubled.

For example: 6 is an odd number doubled, 10 is an odd number doubled, 14 is an odd number doubled, etc. I find it easier to remember it like this than to memorize 4n+2.

[moka22051]

@kourosh89 suweet!!

[Liitttaaaa]

i still don't get the huckel's rule calculation !!?!!!!

[fanchemii]

@Liitttaaaa so the Huckel's rule is 4n + 2 pi electrons; now, if you have a conjugated system, such as benzene, you have 3 double bonds and so a total of 6 pi electrons; all you need to do now is as follows: 4n + 2 = 6; when you solve it, you get 4n=4 and n=1; so benzene is aromatic; the point is that the n has to be an integer (e.g. 1, 2, 3, 4, 5 etc.); if it is not a full integer, then the system is not aromatic. An example is heptalene (gives n=2.5).

[TyTimeIsAwesome]

@fanchemii awesome explaination for clearing it up.

[IVdaaze]

does anyone know what kind of writing software he is using. i want to start doing notes like this on my laptop

[pballdale]

like if your doing A2 chem

[vmelkon]

What is hybradization? The pi orbitals of each carbon coming together? Is it sigma bonds joining with pi orbitals?

[marochakka]

where is the correction video??

[strikertp]

This video is mistaken at the end. In order for an cyclical conjugated compound to be aromatic they must also be planar. The example he gave at the end cyclodecene is never planar, thus never aromatic.

[strikertp]

@strikertp

I meant Cyclodecapentaene

[nomilkforsanta]

@strikertp no, a planar structure is assumed, if you look at the ACS organic chemistry study guide on page 17 it explains this.

[indigestable1]

@strikertp

thanks for pointing this out chum! my text book did say something about that... but it was one of those one liners buried under a stack of other facts. I would have missed it entirely if you hadn't pointed it out!

[baburo101]

Didn'nt know Organic Chemistry was this easy.

[Sulamer]

@baburo101 The hard part are not the concepts but applying these concepts in problem-solving situations. You have to be able to think of the different concepts you may have learned and important information about reagents/reactants, and see how it will lead a reaction. Most of these are basic examples that show the concepts, but if one were to give ask you to synthesize something and explain how it happens, you can have many intensive ways to do it. Source: Biochem Major at Wash. U. at StL...

[himiker]

I have to say, I'm a physics major, and you have definitely inspired me to learn as many different subjects as I can. Since the world's problems can be solved exponentially faster with interdisciplinary approaches, people like you truly make a difference. Keep it up!

[xpstkxps]

Thank you!