@dinto1 The mathematics show that the output of the multiplier at the receiver has frequency components centered around twice the carrier frequency. The low pass filter is needed to get rid of these high frequency components and capture the message signal. Note multiplying at the receiver with the same carrier yields m(t)cos(wt)*cos(wt)=m(t)/2+m(t)*cos(2wt)/2. Need LPF to get rid of m(t)*cos(wt), where w is the carrier frequency in rads/sec and m(t) is the message. Hope this helps! Dr J
plz upload FM demodulation video
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MoniRokse 1 year ago
y did u add 5hz filter...i mean how.....i am confused plz help
dinto1 1 year ago
@dinto1 The mathematics show that the output of the multiplier at the receiver has frequency components centered around twice the carrier frequency. The low pass filter is needed to get rid of these high frequency components and capture the message signal. Note multiplying at the receiver with the same carrier yields m(t)cos(wt)*cos(wt)=m(t)/2+m(t)*cos(2wt)/2. Need LPF to get rid of m(t)*cos(wt), where w is the carrier frequency in rads/sec and m(t) is the message. Hope this helps! Dr J
freedomuniversitytv 1 year ago
@freedomuniversitytv Thanks this helped me
dinto1 1 year ago
oh wow ! nice work.
ineedaname004 2 years ago
great video!!! thank you
johnykoukou 2 years ago 3
good job please keep it up
shazaduh 2 years ago
cool stuff
yehiaashour 2 years ago