Oh, by the way I am enjoying these videos, I wish I had the ability to crunch the numbers like everyone else, been a mechanic all of my life, I'm 53 can build most anything I put my mind too. I am real curious on how the average joe like myself will ever be able to power this unit outside of the house hold to be useful. I wondered what type amps could a 24 volt setup produce?
New viewer, I have a question, I continually hear you talking about power consumption have you ever considered using some form of a rheostat and power off of a 24 volt power source? Its just a matter of wiring up your 12 volt batteries to achieve this, just curious!
finding your videos has resparked my interest in HHO technology. have you ever hooked up a timing circuit fed into a relay to produce a square wave DC out put , or a DC pulse. I had better numbers off of a wet cell that way. Thanks......
If you are converting water to gas in a 1:1 mole ratio, if you can measure gas production, or calculate by considering the Watt-seconds, you can replace the exact volume of water necessary to maintain a perfect KOH percent solution.
@d3adp001 D3, I buy water in 2.5 Gallon jugs. I didn't measure the exact amount but it was about a gallon to refill it that time and every time I get the reservoirs that low.
@d3adp001 Yes, D3 published data presently beeing taken as fact are in fact not fact. I am proving that every day. It is just getting better and better. Now how to find just 4 tenths of an MMW more. I think we both know how to do that. BUBBLES!
@Boyntonstu Stu, I am in no way now or have I ever represented that the energy in the HHO I am producing is greater or even equal to the energy put in this device. Once again, That is not what these tests are about.
@Boyntonstu 1860L of hho = 1L of water, the cell ran for 11 hours 11 x 60 x 10 = 6600 liters of hho = 3.54 L of water. It looks to be exactly where it should be to me. These figures are widely known all you need to do is ask.
@Boyntonstu If memory serves he was just under a gallon to refill the device. But I didnt reqatch the video. I asked Larry maybe he will remember. But the 1866 conversion come from molar math to ideal gas law, so its pretty much a proven fact of science.
i was jjust wondering, if you where to have the water refreshing slowly like , to feed fresh water in one end trickling in, and let the old water come from far end over flowing, would it keep the water fresh.
bassically trickle feeding it, and let it trickle out over flow.
What plate gap are you using ?
moffett8 9 months ago
@moffett8 1/8th inch.
HHOPWR 9 months ago
Oh, by the way I am enjoying these videos, I wish I had the ability to crunch the numbers like everyone else, been a mechanic all of my life, I'm 53 can build most anything I put my mind too. I am real curious on how the average joe like myself will ever be able to power this unit outside of the house hold to be useful. I wondered what type amps could a 24 volt setup produce?
MrEricuhl 1 year ago
New viewer, I have a question, I continually hear you talking about power consumption have you ever considered using some form of a rheostat and power off of a 24 volt power source? Its just a matter of wiring up your 12 volt batteries to achieve this, just curious!
MrEricuhl 1 year ago
finding your videos has resparked my interest in HHO technology. have you ever hooked up a timing circuit fed into a relay to produce a square wave DC out put , or a DC pulse. I had better numbers off of a wet cell that way. Thanks......
dcswen 1 year ago
@dcswen Yes many times, So far I have found no difference in effeciency but the jury is still out.
Larry
HHOPWR 1 year ago
Looking great Larry. 115amps at 13v huh? 15 solar panels on the roof ought to cover that, huh? :) Then you'll be cookin with gas! hehe
KyleCarrington 1 year ago
If you are converting water to gas in a 1:1 mole ratio, if you can measure gas production, or calculate by considering the Watt-seconds, you can replace the exact volume of water necessary to maintain a perfect KOH percent solution.
My $0.02
Boyntonstu 1 year ago
@Boyntonstu it a system that was intended to run for long durations I am sure a ph metered water system would be in order.
d3adp001 1 year ago
Larry how much water did you need to add to top those resi's off?
d3adp001 1 year ago
@d3adp001 D3, I buy water in 2.5 Gallon jugs. I didn't measure the exact amount but it was about a gallon to refill it that time and every time I get the reservoirs that low.
Larry
HHOPWR 1 year ago
well done bro
jdmforyou 1 year ago
Hello Larry, you are very, very, close... well done
going through all your latest vid's - for some reason only known to youtube - I'm not being informed when my subscribed fav's upload new vid's???
Anyway, I'm messing with tungsten + S/S & magnets at the minute - we'll see if it is any good.
Jim
reeseht 1 year ago
I am Happy, very very very happy.
Kinda blows the doors off some theories doesnt it?
d3adp001 1 year ago
@d3adp001 Yes, D3 published data presently beeing taken as fact are in fact not fact. I am proving that every day. It is just getting better and better. Now how to find just 4 tenths of an MMW more. I think we both know how to do that. BUBBLES!
Larry
HHOPWR 1 year ago
@d3adp001
What theory has been blown?
Boyntonstu 1 year ago
Did you burn off the "catalytic" layer? loved the close up shot of the dried koh on the hoses
sylvanenergy 1 year ago
@sylvanenergy Yes,I got a little sloppy filling it couple times.
Larry
HHOPWR 1 year ago
The amount of lost water seems too much for 10 LPM of gas.
How much water is missing?
100 ML of water contains X liters of HHO gas?
IOW Is the water being converted entirely to HHO gas or is it lost another way?
Boyntonstu 1 year ago
@Boyntonstu Stu, I am not sure how much is missing there is 11 hours run time so lots of water has been split. No there are no leaks.
Larry
HHOPWR 1 year ago
@HHOPWR
I suggest that you determine how many ML of water are missing/second//MW/Liter of HHO.
Let's say that it is 500 ml missing every 5 hours with 115 Amps, 13.14 Volts and in the 5 hours you produced 3,000 liters of HHO.
For example: 10 LPM x 60 min x 5 = 3,000 Liters of HHO.
We can calculate the mole weight of 500 ML and see if it makes any sense.
What energy is in 3,000 Liters of HHO at/near atmospheric pressure?
Boyntonstu 1 year ago
@Boyntonstu Stu, I am in no way now or have I ever represented that the energy in the HHO I am producing is greater or even equal to the energy put in this device. Once again, That is not what these tests are about.
Larry
HHOPWR 1 year ago
@HHOPWR
Larry,
You missed my point.
My question was NOT about efficiency.
My question concerns the issue of whether there was enough HHO generated to account for the loss of water.
Boyntonstu 1 year ago
@Boyntonstu I think it is really close Stu. The whole device holds about 2 gallons. Watching it run is deceiving.
Larry
HHOPWR 1 year ago
@Boyntonstu 1860L of hho = 1L of water, the cell ran for 11 hours 11 x 60 x 10 = 6600 liters of hho = 3.54 L of water. It looks to be exactly where it should be to me. These figures are widely known all you need to do is ask.
d3adp001 1 year ago
@d3adp001
It looks to be exactly where it should be to me. ??
How much water was missing?
Boyntonstu 1 year ago
@d3adp001 and Larry,
Was 3.54 L of water missing?
Boyntonstu 1 year ago
@Boyntonstu If memory serves he was just under a gallon to refill the device. But I didnt reqatch the video. I asked Larry maybe he will remember. But the 1866 conversion come from molar math to ideal gas law, so its pretty much a proven fact of science.
d3adp001 1 year ago
i was jjust wondering, if you where to have the water refreshing slowly like , to feed fresh water in one end trickling in, and let the old water come from far end over flowing, would it keep the water fresh.
bassically trickle feeding it, and let it trickle out over flow.
TedFnBuckle 1 year ago
@TedFnBuckle The point of this test was to let the water get a stronger mix.
Larry
HHOPWR 1 year ago