Good question. Due to the total resistance increasing if R2 opens, R1 and R3 will not shine brighter. Try this. Work through the circuit with the three resistors equaling 100 ohms each and a total voltage of 100V. Total resistance is 33 1/3 ohms, and you will find that each resistor has 1amp through it; now open R2 and recalculate. Notice, R-total increased to 50 ohms, but current flow through R1 & R3 are still 1amp. What happens is the resistance total changes. Hope this helps.
Here's my question. Given that voltage remains constant across a parallel circuit from - to +, if r2 went out, then would r1 and r3 (assuming all lightbulbs) shine brighter because there is now more current passing through them than there would be if they had to share with r2?
Good question. Due to the total resistance increasing if R2 opens, R1 and R3 will not shine brighter. Try this. Work through the circuit with the three resistors equaling 100 ohms each and a total voltage of 100V. Total resistance is 33 1/3 ohms, and you will find that each resistor has 1amp through it; now open R2 and recalculate. Notice, R-total increased to 50 ohms, but current flow through R1 & R3 are still 1amp. What happens is the resistance total changes. Hope this helps.
Eeris
eefritz 3 weeks ago
Here's my question. Given that voltage remains constant across a parallel circuit from - to +, if r2 went out, then would r1 and r3 (assuming all lightbulbs) shine brighter because there is now more current passing through them than there would be if they had to share with r2?
Carsongamer23 3 weeks ago
Thank you for making this helpful video!!
Polle from Eritrea [ part of east africa]
pollerobiik 4 months ago
@pollerobiik Wonderful! I am happy that these vids are so helpful!
eefritz 2 months ago
thanks mam youre a great teacher
MrBertech 5 months ago