I know it has been a long time since you put this video up. But could you please explain to me how you get
b = - tau / sqrt(5)
Because I am trying to work through it myself and I keep getting
b = tau / sqrt(5) [Notice the positive tau]
I must be going wrong somewhere but I don't know where.
Thanks
ViciousSheep 1 year ago
where did u get
a= # / sqr( 5) ?
heladobon 1 year ago
@heladobon
Okay: So we have: a + b = 1 and a*phi + b*tau = 1. Multiply the first equation through by tau and leave the second alone.
a*tau + b*tau = tau
a* phi + b*tau = 1
Subtract to get: a(phi - tau) = 1-tau.
But phi-tau = sqrt(5) and 1-tau = phi (check this!) so we have: a*sqrt(5) = phi giving a = phi/sqrt(5).
Does this help? [Writing math in an e-mail format horrible!!]
DrJamesTanton 1 year ago
@DrJamesTanton
thanks a lot man =D
I know it has been a long time since you put this video up. But could you please explain to me how you get
b = - tau / sqrt(5)
Because I am trying to work through it myself and I keep getting
b = tau / sqrt(5) [Notice the positive tau]
I must be going wrong somewhere but I don't know where.
Thanks
ViciousSheep 1 year ago
where did u get
a= # / sqr( 5) ?
heladobon 1 year ago
@heladobon
Okay: So we have: a + b = 1 and a*phi + b*tau = 1. Multiply the first equation through by tau and leave the second alone.
a*tau + b*tau = tau
a* phi + b*tau = 1
Subtract to get: a(phi - tau) = 1-tau.
But phi-tau = sqrt(5) and 1-tau = phi (check this!) so we have: a*sqrt(5) = phi giving a = phi/sqrt(5).
Does this help? [Writing math in an e-mail format horrible!!]
DrJamesTanton 1 year ago
@DrJamesTanton
thanks a lot man =D
heladobon 1 year ago