@chavia2132 you are right about the math .412x8.314x298 = 1020.76. My apologies on that and thank you for pointing it out. When I went back to see where I made the mistake I found that I used the wrong temp in the formula. Note that 16 oC is 289 K, which is correct, but when I wrote it into the formula I put 298 K which is incorrect. If you use the real numbers .412x8.314x289 you do get 980.93 Kpa. Thanks again for bringing this to my attention and let me know if you find any other mistakes!
@siffles93 Similar to the question above, R depends on your units. In the example I'm doing I use L and Kpa for volume and pressure. Since L and m3 are metric units and are related by a factor of 1000 (1000L = 1 m3) you can use the same R value (8.314....) but switch L to m3 if you also switch kPa to just Pa (since they differ by a factor of 1000 as well). All of this to say there are many units you can use for the variables in the ideal gas law you just need to make sure your R matches.
@lomz15 Thanks! The R you are using works when your pressure is in atmospheres. My example will find pressure in kilopascals. The math is all the same, just input your R and the answer you'll get for the pressure will be in atmospheres.
R = 0.0821
Gutsyndicate 2 weeks ago
sorry cant like a how to video that does multiplication wrong .412*8.314 * 298 = 1020.759664
chavia2132 11 months ago
@chavia2132 you are right about the math .412x8.314x298 = 1020.76. My apologies on that and thank you for pointing it out. When I went back to see where I made the mistake I found that I used the wrong temp in the formula. Note that 16 oC is 289 K, which is correct, but when I wrote it into the formula I put 298 K which is incorrect. If you use the real numbers .412x8.314x289 you do get 980.93 Kpa. Thanks again for bringing this to my attention and let me know if you find any other mistakes!
AndrewTeacherNSCC 11 months ago
isn't volume meant to be in m3? Great video though!
siffles93 1 year ago
@siffles93 Similar to the question above, R depends on your units. In the example I'm doing I use L and Kpa for volume and pressure. Since L and m3 are metric units and are related by a factor of 1000 (1000L = 1 m3) you can use the same R value (8.314....) but switch L to m3 if you also switch kPa to just Pa (since they differ by a factor of 1000 as well). All of this to say there are many units you can use for the variables in the ideal gas law you just need to make sure your R matches.
AndrewTeacherNSCC 1 year ago
that was helpful.. i just notices with "R"we always calculate it as 0.0821.. might have to check with my teacher.. thanks for this :D
lomz15 1 year ago
@lomz15 Thanks! The R you are using works when your pressure is in atmospheres. My example will find pressure in kilopascals. The math is all the same, just input your R and the answer you'll get for the pressure will be in atmospheres.
AndrewTeacherNSCC 1 year ago