math in mean girls

[TrayDay101]

Don't let the haters stop u from doing your thang !! Lol

[BleedingLlama]

1) Lindsay Lohan is so hot here.

2) 2:58 SOMETIMES the product of two negative INTEGERS is a positive? You mean always and any two terms, asshole.

3) 3:38 almost all the marks on a test is given for working. In fact, the Jun 2010 exam only offered 10% for correct answers in my exam board (UK, but still.)

4) 6:19 this isn't really the hardest algebra I've ever seen. I have no complaints here.

5) 6:47 147 is also correct.

6) If you know anything about limits, this requires no working out.

[storm610]

CON HALL.

[summerluverr]

if the limit did not exist in a math problem, my teacher would just say "the answer to number 5 is mean girls"

[eternalnight100]

@summerluverr best comment ever!

[Shazgi]

That wasn't exactly a hard question for a maths championship

[gmlmangwar]

OMFG She was so hot in this fucking movie.

[iluvthatmusic]

GET SOME~~~~~~~~~

[wookieproductions]

WASSUP

[xS0L1DSH0Tx]

This might be the dumbest thing I've ever seen.

Everyone needs to go on Wolfram Alpha and plug this problem in and figure out that it actually is -1. Poorly made movie.

[MrMbogza]

how the hell did she get "the limit is negative one" ?

[TheNightsMoon]

Oh wow, I'm such a nerd, I actually knew what they were talking about....

[Mergahuszarok]

@TheNightsMoon Why is that makes you a nerd? It makes you matematicaly educated.

[gigijbijbj]

@Mergahuszarok well fucking said

[rabbitcfh]

thang

[su627]

LOL can't use L'hopital twice for this one just realized xD

[su627]

OMG thats my school!!! It's university of Toronto LOL xD and the limit is 1.....she had to use L'hopitals rule twice hehe

[chris110012]

@su627

Haha Con Hall!!!

[LeonLovesIt]

love this!

[shelbsterrox]

at 7:14 you can totally see camera men XD

[KoushOWNs]

how the hell did she know that crazy ass limit doesnt approach 0?!

[andr00123]

@KoushOWNs lol its so easy, and she's probably wrong. If you were to use l'hoptals rule you could likely find the limit instead of saying its undefined.

all you need to look at is the bottom. If the bottom is zero, you know you can't divide by zero. (x is approaching zero so replace all the "x"'s with 0 on the denominator)

[andr00123]

@KoushOWNs oh ya btw, just did L'hopitals rule and it doesn't work because by the time I reached the second derivative, I couldn't use it because L'hopitals only works under the condition of 0/0 or infinity / infinity

[mylinhle801]

I hate limits @@

[tiptopluongo]

LOL I love how I never understood it until I took calculus last year and I'm like "I know what that means now!"

[Autonova]

we'd like to get jackets.

[holaperu1000]

It's Con Hall!!!

[aevelynl95]

On Oct. 3 he asked me what day it was.

[rowergirl2011]

im watching this on october 3rd :O

[Scooperson6988]

This movie is supposed to be about calc, but they dont talk about derivatives, the most basic part of calc, or integrals. The farthest they got was limits, and they were cake...

[layser49]

OMG That Con hall in the final math battle :D

[Selenafreak67]

Lmao at 8:38

[OneDayHenry]

girls are super mean all right. Lol, check out my vids !!!

[tehsummit]

I'm using this to review for AP Calc.

[JaceyNaii]

great turn out this year

[cessnacitationx1]

i kid you not in my math class once my teacher mentioned limits and literally half the class went "the limit does not exist!"

[whiteelf75]

i came back to this problem since i learned calc and its actually really easy

[ambyleeful]

press 7:54 then 8:56 lol

[puffballs839]

How are these people so smart?

[YaraSoWhat]

Thumbs up if you're watching this in 2011 :D

[RvStacks1]

I LIES NO DO

[ayatollahrocknrolla]

...we pick the girl too

[Cosidelight]

damn africaa hahahaahah

[angeldeoro18]

sucks 

[Flound3r]

I almost can't handle how many people are saying Hospital instead of Hopital lol.

[Nickuncle]

I can't believe a human can do that in their head! Were doing limits now and I can't imagine solving limits in my head while imagining women! Gah! Movies!

[MaverickBearage]

lindsey lohan doing calculus hahaha

[purpleogtwi]

just noticed that tina fey is the teacher lol

[h0wud0in2]

hahah I like how she solved it. The great realisation was that it doesnt approach anything. How d she get that did she plot the function in her fuckin mind??

anyway L'Hospital JUST ONCE and you get zero denom and finite numerator. end of story

[revilo314]

1) Double differentiate both numerator and denominator with respect to x (applying l'Hopital's rule

2) -1/2/2

3) ????

4) Profit

[Darko1393]

GET SUUMMM, GET SUUUUUUUUMMMM!!!

[urimv]

I get 1/2 as the limit. First, the denominator is just sin^2. As the limit is of form 0/0, use L'Hospital's rule. The numerator becomes 1/(x - 1) - cosx. The denominator will become 2(sinx)(cosx) which equals sin(2x). Again the limit is of form 0/0 so use L'Hospital's rule again.

The numerator is now (x - 1)^(-2) + sinx. The denominator becomes 2cosx.

plug zero into the equation. numerator = (0 - 1)^(-2) +sin(0) = 1 + 0 = 1

denominator = 2cos(2*0) = 2 * 1 = 2

Therefore the limit is 1/2

[revilo314]

@urimv

-1/2

you forgot to apply the chain rule to the first term. :p

[GabiN64]

Ah yes highschool

[jamerikan5689]

ew math is gross. however i appreciate those who are good at it. rock on you guys who dont totally suck ass at math.

[maximalideal]

I am. I originally put together these clips for a class of mine, a math appreciation type class, as a sort of introduction, to start the semester thinking a little more broadly and realistically about how math fits into our lives than is typical. Also as a little bit of an antidote to the usual pop math fare.

[neogeo328]

If you don't mind me asking, are you a teacher?

If so, wow. lol. I think it would be pretty cool to have a teacher to get us to watch Mean Girls and then discuss or talk about it, not that math wasn't already cool in high school.

[watusernameshudiuse]

she's right. ln(x-1) moves the function so that x can not approach 0, therefore the limit does not exist at x approaches 0

[h0lyshitters]

THEY WANT JACKETS

[h0wud0in2]

oh common!! how could anybody solve the first 2 problems in something like 5 seconds??

[EvangelineBeatrice]

LOLLL

[jaytothelu]

That's a tall ass asian

[SnookTX2010]

What's the name of the beat at 9:08 ? I've heard it in another movie.

[theredheadchannel]

That asian kid's name is so close to Tupac

[gleekfuzz]

7:57 That killed me!!! ' Oh crap i lost! "

[maximalideal]

@LilMarkymark L'Hopital's rule is only applicable when the limit of the derivatives exists at that point. That the limit you get when doing L'Hopital's doesn't exist does not mean that the original limit does not exist. It only implies that you can't use L'Hopital's rule to try to find the limit. See Wikipedia's entry on the rule, where they use the example f(x) = x + sin(x) and consider when x -> infinity. The limit of f(x) exists, but if you use L'Hopital, you get a non-existent limit.

[PortCactus]

@maximalideal Is it wrong that i think this comment is the only comment in all of Youtube that is relevant in ANY way?! :D

[sam5248]

@maximalideal Not quite right. If the limit via l'hopitals exists OR the limit by l'hopitals approaches infinity then you can use it. If the limit does not exist for any other reason when you have used l'hopitals then l'hopitals is an invalid method. Also, to confuse you further look at this example: lim x to infinity of f/g where f(x) = e^-2x(cosx + 2sinx) and g(x) = e^-x(cosx + sinx) . f'/g' has limit 0 but this limit actually does not exist! I avoid l'hopitals where i can .... it is risky!

[sam5248]

@maximalideal This problem is quite easy WITHOUT l'hopitals ... it is ~ [landaus symbol] to -1 / [2sin(x)] as x-->0 and this limit clearly doesn't exist.

[sam5248]

My correction it is ~ -2/sinx as x-->0

[pigglywink]

lmao at Kevin G at 8:38

[happyhappydancer12]

fuck every girls lives, the guy who plays aaron is gay.

[RebaWillGraceFan]

P!nk song!! lol

[twilightgirl6271]

I just realized that on the card Kevin Gnapoor gave to Cady, it says "Bad-Ass M.C." on the right xD

[hotdarx]

heey October 3rd is MY birthday! lol :D

[fianlfantasyx2lover]

it's raining.......yeah

[CarlyxCrash]

is there suppose to be camera men at 7:14???!!!!!!

[pkap9041]

@CarlyxCrash those aren't cameras, those guys are carrying the podiums

[xxVeronica92xx]

HEY 5:33 is filmed at my school ! University of Toronto COOL!

haha i looove this movieee

[MissIyer]

@xxVeronica92xx

Did you know The Naked Mile was filmed at Con Hall?

And the army scene from The Incredible Hulk was at King's College Circle. =)

[rebskie1]

The music at 3:05 is in Willy Wonka and the Chocolate Factory...

[DorvellTStewart]

"Grool!"

Nice catchphrase there!

[livi1226]

HAHAHAHA! indian boy is so funny!! lolzz! and the gurl wit deh uniform is so ugly!! YUCK! make over

[Deeperella]

haha check out kevin's card. math enthusiast and badass mc!

[Uhthenuh]

Holy crap! When Kady is walking into spring fling and you see the shot from the from her arm arent in her jacket but when they show her from the back she is!

[Mithrawnuruodo]

The limit is "negative infiniti"... Use Taylor series !

[DevilDude16]

@ comments below: thank you for turning this clip into a math lesson!

[SimplyRisque]

Lindsay used to be so beautiful. Now she looks haggard. Let this be an example of what drugs and alcohol will do to you.

[Michael326]

@SimplyRisque

A bit ironic how her limits didn't exist. 

[ronniemonnie]

We were learning limits today, and all I could think about was this movie LOL

[tehsummit]

@ronniemonnie Same!

[915jefflee]

HAHAHA OMG! I know the place where they shot the mathlete competition scene! It's Con Hall!! :O lol I actually have lectures in there! So, I've sat in that place before.. feels weird to see it in a movie actually

[TheDreamer201]

@915jefflee yeah that's con hall right by sf,

<3 uoft

[atims05]

is this for some school project lol? yeah we always quote the limit does not exist in math class.

[123abigal]

the limit doesnt exist.. cause they will never be equal to each other... i love calculus AP

[ifuseekamy]

I fucking hate math.. I could barely pass PRE ALGEBRA.

[MishMishgangsta]

@ifuseekamy thank you!one person who doesnt say its easy!

[SweetStuffDiamond]

im sorry but when kevin talks ´cool´ its like akward ya no i have no affense to the kids he rocks but like its kinda akward

[KathRou27]

I hate calculus.

[Guard0985]

Hahaha.

She wiped her hand on her trousers @ 8:36

[sweetluv322]

@Guard0985 ahaha, out of all the times i've watched this movie, i never noticed that she wiped her hands after shaking hands with the other girl.

that was pretty funny, haha.

[TheAwesomenated]

it's raining...yep

[ClythiaMystica]

lol this is my favorite movie XD! its raining.. yeah..

[Tim92G]

This is how to solve the limit:

If you evaluate this it is indeterminate, at 0/0. However, if you use L'Hospital's Rule, it simplifies to the form of -2/0, or negative infiniti. From the derivative it tells us that the value of the numerator infinitely approaches 2, while the denominator approaches 0.

-1.9999999999/ .00000000001 = f(x) > - 1,000,000 < f(a)

The simplified form is -1-cosx/x2cosxsinx which does not exist as it approaches negative infiniti

[Sungoddess18]

4:22 Wicked quote! Probably just coincidence, but I was pleased.

[barkleysound]

if i ever win a math competition...i gonna rip my shirt

[Joschmo939]

LOL! HOW YOU LIKE ME NOW!? *RIPS SHIRT* YOU LIKE THAT?! YEAH GET SOME! GET SOME! XD

[ianonavy17]

I love how every comment is about the math contest and the part where Lohan says that the limit does not exist.

[MegaShiny]

The limit does not exist!

[d0msp3ll]

Mean Girls inspired me to take AP Calculus in 11th grade.

Best decision ever. :D

[Girlyy011]

"How you like me now uh ,you liek that get some ,get some" lolsx!

[subway987]

hmm apparently a 58% is a D??

[yankees032778]

I remember when I first learned limits, I thought of this movie

[frapevip]

@yankees032778 me too! haha

[kimberleexx3]

THE LIMIT DOES NOT EXIST.

[MGameSwim]

8:56 asian guy gets his screen time LOL!

"what?" hahahaah

[sophieSPAZZTARD]

@MGameSwim i actually thought this when i first seen this film :')

[RorySeizeTheDay]

@MGameSwim  lol. But at the start, he also says.."I hear her hair is insured for ten thousand dollars".

[jackchrisevans]

@MGameSwim but theres also the bit when he says that regina's hair is insured for $10,000

[my89tube]

I used to think it was some crazy hard shit when i first saw this movie. Then i took Calc and it was so simple.

On a sidenote, look at how much of a suckulent red head linsday lohan is in this movie. Now she's pretty fucked up.

[Krinks86]

its undefined, right?

[kingsterbomb]

THE LIMIT DOES NOT EXIST!!!

[lynxiness]

"if the limit doesn't approach anything"

lol it isn't that it approaches nothing, it's that it appraoches different things from both sides. someone who wasn't even paying attention to limits in class wolud never be able to solve that

[JaceyNaii]

8:40 best bit of the film

[redbathtubs]

wow, they must have gone a long way to get to that mathletes competition because that building is convocation hall found on the University of Toronto campus in Toronto, Canada. I was just there for my bio class this morning lol.

[RiseToNothing]

HAHA lindsay lohan and smart in the same movie.wow

[SparkyFlary]

so uh the answer in infinite from one side and negative infinite from the other side after a Lhopitals rule and you get limit does not exist. dang she did it quick though for someone who didnt know what she was doing

[coolboyaznkid]

6:04 STILL MAKING ME LAUGH LIKE CRAZY

[emmmmih]

Soo you got pretty involved with the meaning of a PG13 chick flick...good video though

[HK6]

5:38 LOL

[amparobarrio]

she was soo lucky with that math problm,, the explanation she thinks of is NOT how you solve limis,, hehe

luvvv the movie though

[SubImpactt]

lol the limit of that equation is negative one

[maximalideal]

you have to take the limit from both sides.

[mariuschhh]

@maximalideal it's still -1

[LilMarkymark17]

@maximalideal actually you don't even have to worry about taking the limit from both sides. Use L'Hospital's rule, multiply the top and bottom of the resulting limit by (x-1), you have 1-sin x on the top, which equals 1, and the bottom equals 0, which does not exist therefore the limit does not exist.

[maximalideal]

@LilMarkymark17 L'Hopital's rule is only applicable when the limit of the derivatives exists at that point. That the limit you get when doing L'Hopital's doesn't exist does not mean that the original limit does not exist. It only implies that you can't use L'Hopital's rule to try to find the limit. See Wikipedia's entry on the rule, where they use the example f(x) = x + sin(x) and consider when x -> infinity. The limit of f(x) exists, but if you use L'Hopital, you get a non-existent limit.

[lookche]

sub in x=0 to find your limit. ends up being (loge(1)-sin0)/(1-1^2), which ends up being (0-0)/0, and as you're dividing by zero the limit does not exist!

[scholzie]

@lookche You can't say the limit doesn't exist just because (0-0)/0 is undefined. 0/0 is an indeterminate form and you need to use L'Hospital's rule to determine whether the numerator or denominator reaches 0 first, or neither. For example, (e^x-1-x)/x^2 is also 0/0 as x->0, but the limit is actually 1/2.

[lookche]

@scholzie well as x->0 from small, negative values of x, x approaches infinity. and as x->0 from small, positive values of x, x approaches negative infinity. there is clear asymptotic behavior at x = 0. it's easy to ascertain that there is no limit in this equation due to its normal behavior.

[lookche]

@scholzie @scholzie graphing the equation also gives the answer.

[tong135799]

@SubImpactt The limit of that equation as it approaches x from the left is -1. However, the limit does not exist as x approaches 0 from the right. For the limit to exist, the side limits must be equal. They are not so therefore the limit does not exist for function f as x approaches 0

[h0wud0in2]

@SubImpactt no itso not.. L Hospital and you get (-1/x -cosx) / (1+2cosx sinx) and x->0 so denominator one numerator goes to infinity

[rudekult]

@SubImpactt So lindsey is correct, here's why

start with the easy part:

ln(1-0) = ln(1) = 0

now the denominator:

1-cos^2 x = sin^2 x

so that leaves us with:

lim x->0 (-sin x) / (sin^2 x) =

lim x->0 (-1) / sin x

sin(x) behaves like "x" (linear function) around the 0, which means that for a very small x it's either a very small positive number or a very small negative number. however what that means is that the inverse of that function (=1/x) is either positive infinity or negative infinity.

[MonkeyOctober]

Kevin is a badass

[Mooktopia]

8:38 best scene ever

[Beatmyguest001]

I love that mathlete Kevin.

He's actually really cute.

XD

[tarynlau]

thanks! i was actually looking for most of these scenes! LOL!

[inkassso]

Nice xD

What's the name of the Soundtrack at 9:05?