I've a question about that: with a 7º inclination one loses a bit of the horizontal component of the generated thrust: sin(7º) = 0.12, which means 12% of loss. In that case, there is not "that" advantage, right? Or am I wrong?
@Carlosouza87 I was going to post a similar comment, 7 degrees down thrust means 7 degrees of lift which is wasteful as it pointlessly fights gravity. They did say the hull interaction was like 15-20% though so they get 3-7% net improvement.
@Carlosouza87 Good intuition but a little faulty reasoning. The horizontal component does not decrease by sin(7deg) = 12%, but rather we consider cos(7deg) = 99.3% compared with cos(0deg) = 100%. The loss is the difference, which is approximately 0.7% in the horizontal direction.
@thepet3r this is said regarding the vectors. For 100 N of force a 7 degree tilt produces 99,25 N horizontal (useful) component plus a 12,19 N vertical (fighting gravity) component. AS known, vectors do not sum as algebric values BUT assuming force is related to power by a power-two relation, then we could have 9.851 horizontal-149 vertical adding up to 10.000 and explaining a final 1,49% loss of usefull power.
thumbs up if you are a mechanical engineer...>:)
MrNaxiotis 1 month ago
awesome!!!!!!!!
jdmk20aek 5 months ago
GREAT INFO
shakthiarunk 8 months ago
GREAT INFO
shakthiarunk 8 months ago
Carlos - I was thinking the same thing and was about to make the same comment!
lax4321 1 year ago
ahhhhhhhhhhhhhhhhh big words
tugcrazy 1 year ago
LOL We have ZERO thruster to hull interaction people!! ZERO!!! That means that no thrull babies!!
kompressor124 1 year ago
I've a question about that: with a 7º inclination one loses a bit of the horizontal component of the generated thrust: sin(7º) = 0.12, which means 12% of loss. In that case, there is not "that" advantage, right? Or am I wrong?
Carlosouza87 2 years ago
@Carlosouza87 I was going to post a similar comment, 7 degrees down thrust means 7 degrees of lift which is wasteful as it pointlessly fights gravity. They did say the hull interaction was like 15-20% though so they get 3-7% net improvement.
nunayafb 10 months ago
@Carlosouza87 Good intuition but a little faulty reasoning. The horizontal component does not decrease by sin(7deg) = 12%, but rather we consider cos(7deg) = 99.3% compared with cos(0deg) = 100%. The loss is the difference, which is approximately 0.7% in the horizontal direction.
thepet3r 4 months ago
@thepet3r this is said regarding the vectors. For 100 N of force a 7 degree tilt produces 99,25 N horizontal (useful) component plus a 12,19 N vertical (fighting gravity) component. AS known, vectors do not sum as algebric values BUT assuming force is related to power by a power-two relation, then we could have 9.851 horizontal-149 vertical adding up to 10.000 and explaining a final 1,49% loss of usefull power.
thkokkonis 3 months ago
*snore* *drool*
Yusep27 2 years ago
This has been flagged as spam show
Brainwash Thruster ^^
landmannami 2 years ago
Comment removed
landmannami 2 years ago
My Brain Hurts!!
gillyfish79 3 years ago
Detailed Information!
Buxte2008 4 years ago
Great video! Very informative!
multimolti 4 years ago 4