Molecular Orbitals & Hybridization

[45ballplayer]

jay fucking shore....

[MrConBar]

thank you so much for this!

[MelodieeeL]

Thanks!

Now I will ace my Grade 12 Chemistry Test!

[vf1764]

@MelodieeeL

Ah you are already doing molecular orbitals in gr.12? That's excellent! We only did up to redox reactions, etc.

[MelodieeeL]

@vf1764 Yes! My chemistry teacher wants to prepare his students are university.

[bigu236]

this video helped!

[minhsakura281]

GOOD JOB !!!

[Cannondale900]

This video taught me what my UOP professor failed to.

[konanuk]

smily face at 8:49 :)

[1koshy]

too complicated man! LOL

[aakasho9z]

gr8 thnks......

[aakasho9z]

gr8

[Blacklizzy007]

Can you tell me the hybridization of CH3CN, I know the C-H with zigma bonds is sp3-s but I cant figure out the N-C with sigma and triple bond, as well as the c-c sigma bond

[moijn0002]

great!

[s200960170]

Amazing demonstration. 

[Seraphim137]

omg this is so helpful ty.

[cwells202]

woah...i may actually have a chance at passing this final now! badabing badaboom.

[O0oSorousho0O]

Omg thank you! My prof wasn't making this clear for me, and i read my textbook still no dice. but this helped out.

[Frozenleafz]

lol @ trendavi, i so agree wid u man... great work sca0190 u really helped me out!

[ejvaughan1]

Wheres the "love" button? I finally get it- wohoo!

[kebabsallad]

Damn, this tool is powerful, more than VSEPR imo !

[trendavi]

Fuckin Eh took me 2 years to get this shit. Teachers need to utilize illustrations like this in class more often! I could read it 12 times in my book and not understand it this well!

[anaonlinenow]

it is amazing

thank u so much

[mokdadmm]

I give this 5 star!!!!

[addagio9]

What a great visual explanation ! Thank you

[aswamy123]

Very good explanation. Why is Boron stable without a Octet ?

[pandixon]

@aswamy123

Boron has the the following configuration:

1s2 2s2 2p1. It has 3 electrons in the 2 orbital that undergo sp2 hybridization to allow 3 bonds. The reason it does not need an octet is because the 2s2 electrons are excited to the 2p level. With 6 electrons, the 2p orbital is completely filled, with the 2s orbital empty. This arrangement is favored over 2s2 2p4.

This is also the same reason that Berylium can be satisfied with a 2s2 orbital and not a full octet.

[aswamy123]

Very good explanation. Why is Boron stable without a Octet ?

[Jalangaloze]

@aswamy123 it's just an exception to the octet rule. it's just the way it is.

[nilayrulez]

thank u sir...u covered in everything......simply amazing...!!!

[Lavabug]

Excellent explanation for hybridization, but no molecular orbitals?

[Ghuntu1]

You did not explain molecular orbitals?

[Ghuntu1]

@ 1:42 , I thought that one of the electrons in the 2s orbital gets excited and gets into the the 2p orbital and then they hybridize.

[vleipnik]

simply amazing, very very well illustrated, thank you!

[nbableful]

Thank you very much, you covered everything in 10 minutes. Woo!!!!

[crayonstik]

VIDEO IS FRIGGIN GOOD (Y)

[paintingpink101]

THANKS SO MUCH!

[Timmay123456789]

8:50

looks like phosphorus is smiling =)

[lotusenzyme]

Good clarific

[HotRock2010]

?????still dont understand im thick

[hilibruuge]

great video. this really confused me for a long time. thx 4 posting

[Molie5726]

this is so helpful! thank you

[hcw58]

great video!!! i finally understand hybridization..!!

[nasefoll]

thx

[mmustaca1]

you rock man i got it! sat II here i come

[ghermanalina]

merci beaucoup!

[Southar]

Wtf? Beryllium and Chlorine is a ionic bond....

[calitats321]

nope

[BlueLamp614]

yo, nice post...but this video definitely belongs to McGraw-Hill Publishing as part of their "Chemistry by Julia Burdge" online ARIS System. I'd be careful about copyright infringement.

[halleluja37]

wow this is wonderful, thanks

[coocoocarol]

Wow, this is the best hybridization I've seen. Thanks to it I understand the concept now!

[CosmosFan1]

Hybridization depends on the geometry of the molecule. Linear is sp, Trigonal is sp2, Tetrahedral is sp3, Trigonal Bipyramidal is sp3d, and octahedral is sp3d2. Since PCl5 is trigonal bipyramidal so it forms an sp3d orbital. But PH3 is tetrahedral (lone-pairs make it so), so it is sp3. And I guess the BH3 takes the place of the lone-pair of PH3 is the second part of your question, so PH3 still maintains a tetrahedral geometry and therefore maintains an sp3 orbital.

[JaredsJamboree]

This was perfectly slow and concise. Great work.

[jaysaresteron]

thank you so much

[dzhitler]

but why they hybrid

[boundtogetdown]

science rules!!!

[kaykentucky]

chemistry needs more imagination then i thought! 0.0

[Tokay1420]

I have an exam in a half hour and this concept has just clicked for me thanks to this video.

[cmanalo89]

How'd you do on your exam?

Any tips?

I have my final this Thursday.

[Tokay1420]

did alright, 86%

thoroughly understanding orbital diagrams should help you a lot. paramagnetic vs. diamagnetic should be on your test, bond order, and molecular & electronic geometry will most likely be a big deal.

you are in a different class, so maybe not. but all of that is entirely related.

[cmanalo89]

thanks.

I just had my exam 5 minutes ago.

The para- and dia- was on the last exam.

The exam had electron configuration for O2 and filling the 2s-2p mix/non mix orbitals.

And molecular structures.