Lec 20 | MIT 18.01 Single Variable Calculus, Fall 2007

[melisantika]

I am very happy to see the vidoe Lecture 20: Second fundamental theorem from you, hopefully the others also are happy for You

[Onepissite]

I am very happy to see the vidoe Lecture 20: Second fundamental theorem after you give this

[Ondelendo]

I Love The Video Second fundamental theorem It Can Increase My Knowledge

[bebeheuy]

Steady I Really Like This Video Lecture 20: Second fundamental theorem

[willamricard]

Nice Video Second fundamental theorem That You Share , So Very Nice Thanks You

[imegatrone]

I Really Like The Video From Your Second fundamental theorem

[anakmudajaman]

after i watched this video, my insight is very open because the video Second fundamental theorem is very good to give information

[agapitoflores001]

I usually sleep in my calculus class, but in this video, I was fully awake.

[just003]

20:08 for ftc 2, if anyone is here for it :>

[ahmednadeem91]

@childkiller1500 obviously no professor at MIT lacks knowledge, but it looks like he's not "in" the whole lecture. he's just on another level than the students. Being a good teacher, one needs to be on the same level as the students. Btw i'm doing masters in mathematics so don't think im an inexperienced student

[ahmednadeem91]

looks like he has memorized the whole lecture instead of letting it come naturally

[valadyr2]

When he writes the proof of the second fundamental theorem, wouldn't the curve be y=f(t) instead of y=f(x)?

[bloomingdedalus]

Thank you MIT for providing high-quality academic content for free. You are a testament to the human value of the uninhibited spread of knowledge!

[bmwills8993]

@bloomingdedalus except for the $50,000+ cost of attendance

[bloomingdedalus]

@bmwills8993 Well, yeah, all the calculus in the world won't save you if you can't get credentialed. But, they're a research university, research is expensive. Nevertheless - they don't HAVE to put videos up for us impoverished community college students to watch - so it's appreciated.

[StillnessinMotion]

@bmwills8993 Yes but nobody actually pays that (unless both their parents are doctors...)

[lelyn1234]

This lecture seems to sprawl. On the other hand, at minute 36 he blew my mind. "If two functions have the same derivative, then they differ by a constant. That is all of Calculus." Damn. That means that given two identical rates of change, it is only a quantity that is different between them. Nice.

[DraSifisGr]

well thats true.... whats the wrong thing with that?

[michalchik]

At at 31:40 shouldn't that area be G(x) - G(a)?

[anakore2]

@michalchik yes but because you differenciate that and G(a) is always a constant then its derivative is G'(x)

[michalchik]

At 9:50 that should read a <= x <= b not a<x<b

[ACEofBULLYING]

not really