Research the refractory period + synapses and you will find out.
Plus if you think, the receptor, or any other means of starting an impulse, will be at one end of the neurone so the impulse is just going to travel along the axon, rather than going half way and jus turning back :P
-If you artificially stimulate an axon from the center, it WILL travel in both directions away from the artificial stimulation. It just depends on where the action potential propagates.
@avocadomilk recall that the membrane can only produce another action potential when it is at the resting portential. thus, during the refractory period right after the an action potential, the cell membrane cannot produce another action potential becuase it is hyperpolarized. so, a new action potential can only be triggered at the leading edge o the first polarized area.
Just a skipped detail for everybody: At the end of the REpolarization (in which the cell becomes negative again)the Na+ K+ pump restablishes the Na+ outside the membrane and the K+ inside the cell.
but i think the picture is backwards, he said its polarized hen potassium (K) ions are inside, bu the picture shows K on the outside. this is confusing.
but i think the picture is backwards, he said its polarized hen potassium (K) ions are inside, bu the picture shows K on the outside. this is confusing.
when its polarised, the inside of the cell is negative relative to the outside of the cell an dat this point there's a high conc. of K ions inside and a low conc.of k ions outside, k tends to move into the membrane against its electrochemical gradient--which maintains the resting potential
........ I didn't understand a WORD in that video!!
legofilmer2000 3 months ago
realy hlpfl...
dev009bitoo 8 months ago
straightforward~ thx
psipsychologytutor 1 year ago
Does anyone know how long it's takes for the Nerve to pump na+ out and suck k- in?
I'm guessing only a few mill-seconds but it's just so amazing I can't believe it
BaltoMovie 1 year ago
what stops the impulses from traveling backwards?
avocadomilk 1 year ago 2
Research the refractory period + synapses and you will find out.
Plus if you think, the receptor, or any other means of starting an impulse, will be at one end of the neurone so the impulse is just going to travel along the axon, rather than going half way and jus turning back :P
ryan110110110 1 year ago
@avocadomilk
-If you artificially stimulate an axon from the center, it WILL travel in both directions away from the artificial stimulation. It just depends on where the action potential propagates.
z1jj 1 year ago
@avocadomilk recall that the membrane can only produce another action potential when it is at the resting portential. thus, during the refractory period right after the an action potential, the cell membrane cannot produce another action potential becuase it is hyperpolarized. so, a new action potential can only be triggered at the leading edge o the first polarized area.
got it from my text book.
vestraya 3 weeks ago
Wow heaps good :D
thanks :D
Giddy1993 2 years ago
This video was helpfull :)
WanahLovesAli 3 years ago
Thank you for adding this! Most helpful video I've found
arkey82 3 years ago
wooow im naked right now! w
andrew567567 3 years ago 6
Just a skipped detail for everybody: At the end of the REpolarization (in which the cell becomes negative again)the Na+ K+ pump restablishes the Na+ outside the membrane and the K+ inside the cell.
107stafed107 3 years ago
That voice really sounds like HAL...
Cheesephone 3 years ago
b-bit piece of shit.
chisox4 3 years ago
but i think the picture is backwards, he said its polarized hen potassium (K) ions are inside, bu the picture shows K on the outside. this is confusing.
kezdodik1 3 years ago
its showing in what direction the ions are moving, not the highest concentration
koomdogga 3 years ago
but i think the picture is backwards, he said its polarized hen potassium (K) ions are inside, bu the picture shows K on the outside. this is confusing.
kezdodik1 3 years ago
yes you r right!
paulmascarne 3 years ago
when its polarised, the inside of the cell is negative relative to the outside of the cell an dat this point there's a high conc. of K ions inside and a low conc.of k ions outside, k tends to move into the membrane against its electrochemical gradient--which maintains the resting potential
kriSSy1989ja 3 years ago
that's still the inside of the cell...outside the cell Na+ exists.
cyphi1 3 years ago
Interesting, yet brief.
marijazza 3 years ago
yaa its nice but not very nice
najyown 4 years ago
nice
krazyMaz 4 years ago
good work done. tanx for the videos
tsgopinath 4 years ago
does anyone have a calculator that looks similar?
tonyballa07 4 years ago