I'm reviewing this before my test on friday for calculus and I can honestly say you are so much better than my current teacher. She just goes way to fast without explaining things whereas in this video you take it step by step and explain each process. Keep up the vids!
Thanks! I have a test this morning and was trying to figure out how to do this and couldn't find out how to do it from my textbook. You explained everything.
Very helpful! the only example I could find with different bases and different coefficients for the x-terms in the exponents, which had been confusing me before.
Erm can i ask u a question ? .. After taking log n moving the power down .. cant u bring both log3 and log5 to a side n solve it ? I think its a faster way ..
I could have. In fact I could have taken the logs to any base on both sides. I chose Log (base 10). I would definitely use LN on both sides if the equation contained "e".
I could have, in fact I could have used any log, such as "log base 7". However there is no reason why I should not use log base 10, I usually only use natural logs when I am dealing with an equation containing "e".
The problem comes with the right hand side because there just is no way to simplify log(a + b) or, in your case, log (6^x + 2). I solved this by graphing y1 = 7^x and y2 = 6^x + 2. Their intersection point is x = 1.250838 and y = 11.404618. so the answer is approximately x = 1.250838. This agrees with Wolfram Alpha as well.
@ecswimmer06 Ha Ha:) I have been looking all over the internet to solve a problem just like that! It seems there is no way in this world to do it algebraically:)
I haven't worked with logarithms too much, but that seems like a very complicated way to solve the original problem. I sure hope my ACT doesn't have a log problem that tough!! :)
Thanks, my math book sucks at explaining things and when I searched the net I couldn't find examples as complex as this one to base my execution on. 5 stars.
I checked this out because as I understand, this kind of math is integral to computer science which fascinates me. Not surprising, I STILL find complex math Frustratingly detached from any real world application, Which saps my interest. I don't know HOW* I graduated. I still respect it though. and it's elegance.
thank you so much!! :D
DudeMr94 1 day ago
this makes sense to me now. thank you so much :)
heatherawrrable 1 week ago
my teacher didn't teach us shit, fuckin filipinos
hzeppelin23 1 week ago
THANK YOU, taught me better in 4 minutes then my teacher did in 50
FAILmasterFTW 2 weeks ago
Thank you! :D
8NylJ 2 weeks ago
omg thank you, that helped me so much!!
cheesecakencookies 1 month ago
I'm reviewing this before my test on friday for calculus and I can honestly say you are so much better than my current teacher. She just goes way to fast without explaining things whereas in this video you take it step by step and explain each process. Keep up the vids!
megacoolkid94 2 months ago
Thank you!
Escuderofiel1 2 months ago
Thank you so much for posting this. I was so lost on my homework before I watched this!
jennessy408 2 months ago
Major help ... many thanks. I had to find the exact solution for 2^(x-1) = 3^x ... now I know how to solve exactly! thanks
nyarbeinghi 2 months ago
GOOD STUFF!!
noodow715 3 months ago
Thano you !!!!
EpicJam1 3 months ago
Thank you!!
m0012 5 months ago
Thank you.
baseballstar93 8 months ago
AHHH!!! thank yous!!!geometry totally ruined my algebraic mojo >.< need review
aaypea 8 months ago
thank you very much sir
rafael1877 8 months ago
have a question? could i also express this given example on the video like
(x-5)ln(3)=(6x+2)ln(5) ....like using ln instead log??? or whats the difference?? =D
miguelitomania 9 months ago
thanks so much i totally get it now! (: you teach better than my math teacher. xD
missrockbandhero 9 months ago
helped so much!!!!
justforaccess09 9 months ago
Thanks! I have a test this morning and was trying to figure out how to do this and couldn't find out how to do it from my textbook. You explained everything.
esca8652 10 months ago
Very helpful! the only example I could find with different bases and different coefficients for the x-terms in the exponents, which had been confusing me before.
LacrymosaRequiem27 10 months ago
holy shit i love you
budradis1 10 months ago
Thanks :)!
mirjettaaa 1 year ago
THANK YOU!
midnightpanda 1 year ago
Thanks so much!
aprilen 1 year ago
There is a MUCH MUCH MUCH more quicker way of doing this.....
x-5 = 6x+2 Log3^5
1. Find Base of Log3^5 then mult base of Log3^5 by 6x+2
2. Add like terms
3. Solve.
MUCH QUICKER.... Only 3 steps insead of 10
012Miike 1 year ago
Comment removed
012Miike 1 year ago
this was mucho helpful, i pray i pass my exam
sexyoreo6692 1 year ago
Thanks, it's wonderful that people post this type of video. I wasn't paying attention to my professor the day she taught this. :P
YT4Tori 1 year ago
THANK YOU
DancinWithJB 1 year ago
uhhh... i dont know anything about Math
HorusFlint 1 year ago
very helpful
razmoket2233 1 year ago
why didnt you solve the equation LOL. i always enter it into my calculator wrong. i get everything but the calculator part. FML
maxim2266 1 year ago
Thanks a lot.
bukyogunleye 1 year ago
Thank you so much for this Clear step by step explanation.
cloud453 1 year ago
Thanks! :D
gtg4651 1 year ago
thanks, i was stuck lol
1073601 1 year ago
thanks, i was stuck lol
1073601 1 year ago
Thanks for the helpful guide.
ZakaqerE 1 year ago
This was sooooooo helpful! Thanks soo much!
coupado 2 years ago
You are a math god , thank you so much!
spyfinder 2 years ago
Erm can i ask u a question ? .. After taking log n moving the power down .. cant u bring both log3 and log5 to a side n solve it ? I think its a faster way ..
sh4d0wsl4y3r 2 years ago
Thank you for this great explaination, It really helped me understand exponential equations with diff bases
xSigzenx 2 years ago
why u didnt us LN?
khayle05 2 years ago
I could have. In fact I could have taken the logs to any base on both sides. I chose Log (base 10). I would definitely use LN on both sides if the equation contained "e".
minkusbc 2 years ago 3
Thanks big help
Azamat102 2 years ago
This answer is the BOMB!! awesome,concise.. exactly what I needed.
Thank you.. vless you!!
arlete144 2 years ago
you are really cool!!!
juryYELL18 2 years ago
i suck at calculus, and this is 1 of the best explanations i've ever gotten
87Jjj 2 years ago
wow, thanks a lot! This helped me out so much.
knorton9492 2 years ago
Dude you should have used natural log
Sp3nc3daman 2 years ago
I could have, in fact I could have used any log, such as "log base 7". However there is no reason why I should not use log base 10, I usually only use natural logs when I am dealing with an equation containing "e".
minkusbc 2 years ago 2
You have no idea how much this helped me. Thank you so much, God bless you.
xolillypad 2 years ago
THANK YOU!
ssssarzzz 2 years ago
i love you! know I get it!
ClubEXPRESS 2 years ago
I really need help... I may be just not thinking straight, but I just can't solve:
7^x = 6^x + 2
ecswimmer06 2 years ago
The problem comes with the right hand side because there just is no way to simplify log(a + b) or, in your case, log (6^x + 2). I solved this by graphing y1 = 7^x and y2 = 6^x + 2. Their intersection point is x = 1.250838 and y = 11.404618. so the answer is approximately x = 1.250838. This agrees with Wolfram Alpha as well.
minkusbc 2 years ago
@minkusbc can you help me solve this problem please???
I have to solve the exponential equation then express the solution in terms of natural logarithms
4^x-2=222
please help me out!!!
sucio1985 3 months ago
@sucio1985 Assuming you mean 4^(x-2)=222, take natural log of both sides.
ln(4^(x-2))=ln(222) Now, by the power rule for logarithms, the exponent can be brought in front.
(x-2)*ln(4)=ln(222) Now its just algebra
(x-2)=ln(222)/ln(4)
x=ln(222)/ln(4)+2
mcmanhandles 3 weeks ago
@ecswimmer06 Ha Ha:) I have been looking all over the internet to solve a problem just like that! It seems there is no way in this world to do it algebraically:)
mcmanhandles 3 weeks ago
Good stuff sir, now i'm not stuck anymore.
chkaus1 2 years ago 2
solid explanation
hephronss 2 years ago
oh..ur gud!!tnx..
xoxotrish17 2 years ago
I solved and got something like -2.3 I have no idea if this is right, as I didn't know what to do with the negative in -log3. Anybody know?
captaineothan 2 years ago
The easiest way to check yourself is to go back and plug in your answer.
You said x = -2.3. That results in something like 1/3040 = 1/176948160.
My answer was x = -1.01. That results in something like 1/737 = 1/635
weatherman1994 2 years ago
I haven't worked with logarithms too much, but that seems like a very complicated way to solve the original problem. I sure hope my ACT doesn't have a log problem that tough!! :)
captaineothan 2 years ago
this stuff is trippy.... umm, what do you mean exact ? this stuff sounds like a religion, the math rules.
evilcrabsitchalways 2 years ago
Decimals aren't exact numbers. The common log of anything (besides powers of ten) is irrational (making decimals estimates).
weatherman1994 2 years ago
thx
edgao5555 2 years ago
Wow!!
you did in 4 minutes, what my teacher couldn't do in two and half hours
thanks man!
Bless you and your Sharpie!!!
Winst0nOBoogie 3 years ago
YOU ROCK!!!
pafijohn 3 years ago
Thanks so much! Great explanation. The answer turns out to be about -1.018, I think
mtrc6 3 years ago
THANK YOU SO MUCH!!!
swcnut 3 years ago
tnx a looootttt
Wnaysha 3 years ago
You explained that better than my math teacher! Thank you so much! You are awesome :)
NAJ626 3 years ago
thank you so much! you rule!
zippynmandar 3 years ago
Thanks for helping us out!
blacksugar25 3 years ago
You just saved my GPA!! Forever grateful:)
NICOLIOUS 3 years ago
Thank you, you are an EXCELLENT teacher!! i love the arrows and highlight. it helps SOO much! stella
speranforever 3 years ago
Thank you!!!...
Saludos desde Argentina
torneronela 3 years ago
You sound like John McCain lol ty for the help
KhaiserVillhem 3 years ago
You really explain clearly... good work.
ssoko 3 years ago
thankyou!!!!
ochibii 3 years ago
Thanks, my math book sucks at explaining things and when I searched the net I couldn't find examples as complex as this one to base my execution on. 5 stars.
ReflectionEternal2 3 years ago
thank you sir!
Philipergrits 3 years ago
Excellence Video and Explanation. I'm Impressed.Thank You
b3f4school 3 years ago
Thank you, that was very helpful
JohnLetton 3 years ago
good work!
primmanet 3 years ago
Thank you for this video!! My math teacher is so stupid and this really really helped!
amberlynnbg 4 years ago
THANKS for the explanation!!!
IcyToben 4 years ago
Thanks goodness for logs. Nice video!
sjsawyer 4 years ago
thanks bud
simplefix2323 4 years ago
woooow your a 1000times better than my last math teacher
123nameless123 4 years ago
you are so much better than a lot of teachers.. conglatulations :)
psy123 4 years ago
Oh yea
Philipergrits 3 years ago
I checked this out because as I understand, this kind of math is integral to computer science which fascinates me. Not surprising, I STILL find complex math Frustratingly detached from any real world application, Which saps my interest. I don't know HOW* I graduated. I still respect it though. and it's elegance.
foreverseethe 4 years ago
dude u teach better those idiots at school!!!
hiredagent 4 years ago
ES UTIL
redmmmmmnn 4 years ago
great stuff
sidiqmk 5 years ago
This is great, I can youtube and study math at the same time!
rosalannes 5 years ago
I think stuff like that is extremely interesting. I seriousely do.
Krizzz56 5 years ago
awesome
mrjiggyfly122 5 years ago