Added: 3 years ago
From: khanacademy
Views: 46,453
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  • can you just go and write a book pleas!! i have never seen anyone explaining things so good as you do,...

  • Gracias.

  • "Let me make it bigger so we can explore it a little bit"

    THATS WHAT SHEE SAID!! LOL!!

  • 10 kelvin. jesus christ. You sir are dead anywhere in that room.

  • Thank you so much... Only 2 days are left in my exam, so it was a big help.

    Thanks again for making it a bit easier for me to tackle these monsters 8)

  • This video is hot! ;)

  • Sal, have my children please.

  • 10K = 10 degrees above absolute zero...that is like...nothing will survive...colder than space...

  • Khan, keep on the great work! You are saving our lives here! Thanks :D

  • A 10K *heat* source? That's a pretty cold room if that counts as heat...

  • its calc 1d or calc 4 ! omg

  • You flew me inside the vector filed... I love you...

  • HI - at 6:27, when you take the derivative of the outside function, why don't you pick up an extra minus sign? I understand that the -2x is the partial derivative of the inside function, but the outside function is still e raised to the minus something - which should give you MINUS e to the minus something. OR is the minus sign somehow wrapped up in the function and "hidden" so that doesn't happen?

  • @jsm666

    d( e^f(x))/dx = df/dx * e^f

  • @motleyfoolmania *slaps forehead* Stupid me.

  • it's alike gravity

  • awesome

  • Salman Khan is Chuck Norris' teacher.

  • You need to be hired by Texas Christian University

  • Comment removed

  • A rather unrelated question:

    It is intuitive that the rate of increase of temperature increases as you get closer to the source but I somehow just can't get my head round the proof of this. I did y=10^(-x) where x=r^2 and plotted dy/dx, but when x decreases to zero , dy/dx DECREASES, can someone explain this to me!!!!!!F***ing irritating...

  • awesome! this helps me visualize gradients soooo much . thanks!

  • u r awesome !!hope i can pay back to you !!!!

  • I guess if you get further and further away from a 10 kelvin "heat" source you get hotter and hotter

  • @dalcde LOL, its still gonna be a 10 K heat source and going away from it will be like going in a space with even lesser temp say 8, 7, 5 and so on. The equation is still valid.

  • @najafnajafali The temperature of space is about 2 to 3 kelviin.

  • Comment removed

  • hey sal

    What graphing software do u use to graph the gradients?

    You're videos are amazing BTW!!

    Thanks for evreything!!

  • @arvv92 in one of his later videos he drags the app far enough into the window that i could see the programs name. its called javaview. google magic! :D

  • The multiplying by a unit vector is just a standard adopted to ensure that the calculated value of the gradient (the magnitude) is always consistent; at least, this is what I learned from my professor.

  • @AnaticulaeIratae14

    My apologies, I confused the unit vectors i, j, and k with the unit vector used in calculating the directional derivative in my first comment. The actual purpose of the unit vectors i, j, and k is to simply give the vector direction in n dimensions.

  • just out of curiosity, what is the point of multplying by the unit vector? isn't it just one?

  • @fprecoiil the unit vector has a length of one in a spacific direction, for example i is 1 in x and 0 in y and z. When you multiply the unit vectors at a given point it will increase the values a i, j and k. With gradients you are looking for a set of vectors within the vector space. The resulting vectors have directional components and intensity of these vectors which is defined by how long the vectors are.

  • does anybody know the name of the graphing tool?

  • you are truely amazing

  • oh my god! i have such a hunger for knowledge because of you sal!

  • what program are you using for your plotting? i have matlab but i'm thinking that's maple or something

  • Right now I'm taking college algebra, but I got bored of it and decided to move on to calculus because of these vids, and a couple others, I can do partial derivatives and such, It'll take a few reviews of these gradient and curl vids to get it down but yep :] thanks man you are awesome!

  • if there is a god, u are godsend....thanks a lot man, i just might pass my calc 3.

  • wait what? this is Calc 3? I thought it was the beginning or middle of Calc 2. I wouldn't know I'm not even in Calc 1!!! I just started taking notes and that voice, that soothing, cool voice dragged me into a hunger for knowledge.

  • @gobberpooper yeah thats cal 3

  • @captaindisguise; da khor kuass dy

  • great video I was confused about the gradient before I started and you explained EXACTLY what it was!!! you didn't go through some theory that I would have no comprehension of whatsoever you instead was down to earth and understandable! I will be watching more of your videos to help me through my calculus 3 class i am taking now,

    God Bless!!

  • yeh we have just been learning bout this in physics at first it makes you want to beat your head in with a calculator but after ten mins of reading the books you really get the the whole concept.

  • This is great, I keep watching video after video and I just can't stop, it is all said and explained in such a way that it gets kind of addictive. Probably many more people would like maths if they learned it that way!

  • Could you please explain why

    "The gradient of a scalar function can be written as the sum of a constant vector and the gradient of a periodic function."

    I would appreciate it if you make a VDO of that!

  • it was really great , thanks alot , and god bless you

  • that looks like Maple, which was developed at MIT (?). Sal might know.

  • i believe Maple as developed in waterloo, ontario in canada

  • Thank you.

  • Awesome software. What do you use?

  • Sal uses JavaView for graph and MS Paint as a blackboard.

  • k thnx :) I'm also guessing he's using a pen as a mouse, a tablet.

  • Comment removed

  • This was so cool. Thnx :)

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