Aw man, you didn't show the clever arithmetic showing how you get from the sigma notation to the definition of the derivative. That's okay though. I can kind of understand why. Youtube isn't really made for such in depth explanation. Actually I think you're more likely to find the proof in real analysis books than calculus books.
Here's the Fundamental Theorem of Calculus: "The rate at which area is covered with paint by a paint roller is proportional to the width of the paint roller."
I understand how to apply the fundamental theory of calculus however, I don't understand why. Why is the anti-derivative of a line the definite integral? I do not understand why plugging a value into the anti-derivative of a function will give you the area below the curve of the function between zero and that x value. Sigma notation, limits, rectangles, that whole deal makes perfect sense but the jump from the limit to an anti-derivative I do not understand how.
Yeah, I have the exact same question! I'm taking Calc 3 this spring, and I'm still trying to figure out exactly why the anti derivative of a function would give you the definite integral. I see it's been awhile since you posted this response, have you found an answer?
THANK YOU SO MUCH. I'm going into highschool in about a week, and this really helped.
sukinorules 6 months ago
wat .________.
dameowmixman 8 months ago
you're shit hahaha.
oHeyitsthatguy 8 months ago
Aw man, you didn't show the clever arithmetic showing how you get from the sigma notation to the definition of the derivative. That's okay though. I can kind of understand why. Youtube isn't really made for such in depth explanation. Actually I think you're more likely to find the proof in real analysis books than calculus books.
theboombody 1 year ago
Here's the Fundamental Theorem of Calculus: "The rate at which area is covered with paint by a paint roller is proportional to the width of the paint roller."
BauraKale 1 year ago
terrible
themanisheab180237ce 1 year ago
hey
this was great
plain and simple
thank you very much
frostwow 1 year ago
You should also show how to find the area inside a polar curve or under a surface, that would be exiting.
GR1o6180339887498948 2 years ago
wheres the proof
TowerCraft 2 years ago
The proof is found in any calculus book on the market. No reaon to put it up here.
Lutemann 2 years ago
I understand how to apply the fundamental theory of calculus however, I don't understand why. Why is the anti-derivative of a line the definite integral? I do not understand why plugging a value into the anti-derivative of a function will give you the area below the curve of the function between zero and that x value. Sigma notation, limits, rectangles, that whole deal makes perfect sense but the jump from the limit to an anti-derivative I do not understand how.
lateralus011 3 years ago
Yeah, I have the exact same question! I'm taking Calc 3 this spring, and I'm still trying to figure out exactly why the anti derivative of a function would give you the definite integral. I see it's been awhile since you posted this response, have you found an answer?
rls0263 3 years ago
it just makes so much sense!
b0bb0bs0n 3 years ago
great video!
if you don't mind me asking, what program did you use to create this video??
The4thbassguy 3 years ago
Camtasia Studio
Lutemann 3 years ago
would you make some cal2 videos? if you were teaching it i, and many other students i have spoken with, would definitely take your class
pssycrssy 3 years ago
you should prove the fundamental theorem of calculus in a subsequent video.
ryeguy24 3 years ago
That's done in all the calculus books. What I'm trying to do with these videos is to explain how things work in the simplist terms.
Lutemann 3 years ago
oh ok, i just got excited when seeing the title. Would be a good to see proof visually? in case you having nothing to do this weekend :)
Good video though.
ryeguy24 3 years ago
Yes.
Lutemann 3 years ago
I have a problem. I think I have worked it out but I would like confirmation. Any help would be greatly apreciated.
I have a function y = 220*e^(-3333.33*x)
I believe that the indefinite integral(anti-derivative) is -.066*e^(-3333.33*x)
This being so, the definite integral of the interval 0 to .0015 (this is an area I want to find) would be:
-.066*e^(-3333.33*.0015)
- (-.066*e^(-3333.33*0))
or .0004447 - (-.066)
which equals .06555(The area under the curve)
Thanks for any help
4Teddybears 3 years ago
In addition to the above, I would also like to know whether dividing the area by the interval gives the average of all values of y over that interval.
i.e. .06555/.0015 = 43.7. Is 43.7 the average value of y from x=0 to x=.0015?
4Teddybears 3 years ago
amazing description... you should be a professor or something :p haha
iceman0869 3 years ago
nice ;)
onewayx12 3 years ago
:) Awesome video's. Really helpful. Night before exam doing a bit of reviewing.. but you do them in 5 min each XD
oxyking 4 years ago