Thank you for noticing the typo. I annotated the correction. It could start at zero but n would need to be adjusted to n + 1. You are correct, but (-1) would also need to be to the power of n+1. If you find the other videos, please let me know.
@ 0:10 Doesn't the power series representation of ln(x) need to start at n=1, either that or be rewritten as ∑(n=0,∞) ((-1)^n*(x-1)^(n+1))/(n+1)? As it is now when n=0 you'll have 1/0 as the first term. I think you have it written this way in two other videos as well.
Thank you for noticing the typo. I annotated the correction. It could start at zero but n would need to be adjusted to n + 1. You are correct, but (-1) would also need to be to the power of n+1. If you find the other videos, please let me know.
bullcleo1 9 months ago
@bullcleo1 Just noticed, the previous video "26. Taylor and Maclaurin Series" also has this chart right at the very end of it.
jasonjkeller79 8 months ago
@ 0:10 Doesn't the power series representation of ln(x) need to start at n=1, either that or be rewritten as ∑(n=0,∞) ((-1)^n*(x-1)^(n+1))/(n+1)? As it is now when n=0 you'll have 1/0 as the first term. I think you have it written this way in two other videos as well.
jasonjkeller79 9 months ago
No biggie, but when you wrote out the series @3:44 you forgot the + sign between the 2x and 4x^2/2! terms.
jasonjkeller79 9 months ago
Comment removed
jasonjkeller79 9 months ago