I've seen this one before. They way they do it is by switching the beakers when they're out of shot at 0:36. Nice trick though. It's amazing what they can do with magic these days.
It is indeed permanganate and not manganate. The manganese in permanganate is in the +7 oxidation state, and thus is purple. The manganese in manganate would be in the +6 oxidation state, and would look green. Here, we are using permanganate.
Technically, yes. It's an oxidising agent, and is used for bleaching. What I'm assuming it would do to your hair is bleach the hair itself while dying it the henna colour, which would not be oxidised by the barium peroxide. Either way, pretty much anything that you use to change your hair's colour or bounce is damaging to it. It's not really such a big deal, though, since hair is dead, and you're not modifying the living root.
I've seen this one before. They way they do it is by switching the beakers when they're out of shot at 0:36. Nice trick though. It's amazing what they can do with magic these days.
MrAlistairSpalding 1 year ago
hey whats that man, i read on chemistry that it was potassium manganate, but yo wrote permanganate
EhtYlno 1 year ago
@EhtYlno
It is indeed permanganate and not manganate. The manganese in permanganate is in the +7 oxidation state, and thus is purple. The manganese in manganate would be in the +6 oxidation state, and would look green. Here, we are using permanganate.
ummacles 1 year ago
is barium peroxide damaging to the hair, my henna contains this chemical
toy1022 2 years ago
@toy1022
Technically, yes. It's an oxidising agent, and is used for bleaching. What I'm assuming it would do to your hair is bleach the hair itself while dying it the henna colour, which would not be oxidised by the barium peroxide. Either way, pretty much anything that you use to change your hair's colour or bounce is damaging to it. It's not really such a big deal, though, since hair is dead, and you're not modifying the living root.
ummacles 1 year ago
i) H2SO4 + Ba(O2) --> H2O2 + BaSO4 (white pp)
Fe° + H2SO4 + H2O2 --> Fe(II) (greenish) + SO4(-II) + 2H2O
ii) H2SO4 + Ba(O2) --> H2O2 + BaSO4 (white pp)
2KMnO4 (intense violet) + 3H2SO4 + 5H2O2 --> 5O2 (gas) + 2MnSO4 (virtually colourless) + K2SO4 (colourless) + 8H2O
Isn't it?
soyunclonyque 2 years ago
awesome =)
OrganicWebhead 2 years ago