weigh 2:2. Now weigh any 2 of them with another 2. If they are the same, take one of the balls from the other 2, weigh it with one of the normal balls. If it is the desired answer, it is either lighter or heavier. If not, then the other ball is it. Voila!
1. take 1 ball on each side. If they’re not the same, then shift one with another. If these are the same, the one you shifted out is lighter/heavier. If they’re not the same, the one that wasn’t shifted out is lighter/heavier
If the balls were equal at the first time, take another two and do as before
If the balls were equal, then shift one ball with one of the last balls. If they now are equal, then the last one is lighter/heavier. If they’re not the same, the ball you just put is the one
And here's a question for you - You have 10 chocolate making machines, each one making chocolates that weigh exactly 50 grammes. One of the machines got broken and makes chocolates that weigh only 49 grammes. Using an electronic scale, measure ONLY ONCE to find which one is broken! Beat that, geniuses of this world! :)
The solution - Put 3 balls each side, then see which side is lighter. Pick the balls from lighter side and take one ball each side. If one side is lighter, then thats the ball. If they're equal, then the other ball is lighter!
you wiegh 2 at a time and use that 3 times........ first time if 2 balls are the same you move on to the next 2...... if those are the same..... you scale the last 2 and you got a winner.....
@bananen12 Not what I mean, let me rephrase. How do you tell if the heavier ball of the two is heavier than the other five, or if the lighter of the two is lighter than all five? It's not possible, considering you can't weigh the balls anymore.
the problem that I keep seeing in the solutions is that people assume that the ball is heavier when it could be heavier or lighter. the only way to figure it out is to know one of the normal ones. if you know that then you can solve the puzzle.
3 balls each side, one side will be lighter, take that 3 balls, weight 2 of them, if they're balanced, the other ball is the light one, if one is lighter, then it's the light one.
1. You put on each side 2 balls -If both sides are equal, you know the Lighter or heavier ball has to be one of 2 which are left. You grab one, weight it With one of the normals. If the side of the Side of the normal goes up, you have a Heavier ball, else lighter.
2. Second case: You put 2 on each side and 1 goes up. You switch the one with the 2 Left balls. If its now equal, one of the 2 Balls we
Not sure about the series title for this one... This is better for revealing mental retardation through failure than uncovering genius through success.
1 put two balls on one side and two on the other if on side is heavier than compare the two balls that u have on that side (one vs one) and you r done in two uses of the scale.
If the 1 st test ( 4 balls) comes out with equal Sides than definetly the heavy ball is among the other two that u haven t tested yet and again proceed into compairing this two left ball and you r done two steps no need for the 3rd one.
@khaver1981 Your response assumes that the different ball will always be heavier. The vid says one ball is either lighter OR heavier. Figure out what ball is different and is it lighter or heavier.
For this to be an actual challenge, there should be 12 balls. and your task is to do the same thing. I spent two days scratching my head before solving it.. quite tricky
these are not puzzles. these are common sense... all of your videos are common sense. Calling them complicated just makes people feel smart for knowing what my 5 year old niece should.
its not possible, its trail and error.. We find solutions that ain't there sometimes because we are convinced there has to be one. Realising it is not possible is hard because the mind wants an answer.
Place 3 balls on each side. The side with the lighter ball will raise up. Remove one ball from each side till the scale is level and you will find the lightest ball. Pen and paper not needed.
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surely its simple they are all the same bar one so just do them in pairs and only the lighter/heavier one will show a difference, or perhaps im under thinking it
(1) Put 2 balls on each side. If one side is heavier, (2) remove 1 ball from each side, if the same, (2) test a ball of same mass with a ball of unknown mass. If one ball is heavier, (3) weigh that ball with a ball of known mass.
If it is one of the other 2 balls, (2) test one ball with a ball of known mass, if the same, (3) test the other with a ball of known mass.
Another solution is putting all 6 balls in [ 3 on each side] one side will of course be lighter or heavier, remove a ball from both sides if they balance compare the ball from the heavier side to the lighter side and you will know which disrupts the equilibrium
I've seen something harder. It's exactly the same, but the only thing is there are 12 balls and you are still, only allowed to use the balance scale 3 times.
There are many solutions on google for this 12 balls too. I'm not kidding. 6 balls is too easy and even with 12 balls, it is still solvable.
Guys, everyone's saying "take off the lighter one, that's it" No, dipshits. It's lighter OR heavier - you don't know that. It can't be done in two steps.
1. weigh the balls 3 on each side, then take the balls from the lighter side of the scale
2. take an extra ball (from the previous heavier side) and split the 3 balls (from the lighter side) in 2 like 2 and 1 + 1 (extra ball), then weigh it again
3. again, take the lighter side and weigh those balls, one on each side of the scale and voila
Easy Put two on each side When one side is lighter get another ball on the lighter side and if its still the same then the other ball is to light and that is a the answer
1.weigh it with three on each side which ever side is lighter than take those three balls and discard the other three.
2. weigh 2 of those three if they are equal than the one you left out is the light one if they are un even than the one that the scale shows is lighter than that is the light one
..if they are even you know that the set you just pulled off the scales have the mystery ball . if the scale moves you know that the mystery ball is still on there. Now by taking note the round before you will know whether or not the set on the table or the one on the scales had a lighter or heavier ball...so you weigh which ever set was out individually ( 1 on each side of the scales) and you then know which ball is the different one and also whether it is heavier or lighter than the rest )
have to see which ball wins and then you have your ball and the answer.
Now if back at stage 1 you put 2 sets of 2 balls on the scales and they were not even...you will know that the 2 balls on the table that weren't measured are 2 regular balls. You have to now take note of what happened to the first 4 balls you measured which set was heavier or lighter. Now leave 1 set of balls on the scales as is and remove the other set and replace it with the set on the table
The answer is to weigh any 4 balls ( 2 each side) then if the scales are even the mystery balls is one of the 2 balls not on the scales . In which case you leave the 1 set of 2 balls on the scale as is and put the new set on ...you’ll now know if the mystery ball is lighter or heavier by the fact it outweighs or doesn't outweigh the previous 2...you now take that new set and weigh them individually knowing that the ball you are looking for is lighter or heavier you just
The solution is actualy taking 4 balls (2 on each side), 2 things could happen:
If they are balanced, then put the other 2 balls and compare, then get the heavier and compare with some of the first two balls, if it's heavier, then that ball would be the different(and heavier) else the other ball was the lighter, else, if in the first step some side was heavier, take those 2 balls and compare, if they are equal, then the lighter ball is in the other 2 balls (you just need to compare them)
@planetofthescums That's not even a solution, first you dont know if the scale is large enough to fit the 6 balls without touching each other, second, that's not right, the height they get does not depend of their weight.
@planetofthescums Have you ever studied any physics? did you know that the speed of an objet falling only depends on how they move through the fluid they are in? and, as the balls are suposed to be of the same shape and size, they will move the same way.
@bigbig1604 Ok. The rate of a falling object only depends on its mass. What about the energy the scale imparts on said objects creating accelerations relative to their mass?
@planetofthescums rate of a falling objet does NOT depend on its mass, and, the scale impart energy according to it's mass, yes, but the acceleretion they get its the same, because the scale is suposed to be rigid, thus every objet leaves the scale with the same speed.
@bigbig1604 Sorry. I was up late when I typed that. I meant to say fall is independent of mass, like you said.
I suspect you are right that they leave the balance at the same speed. I was thinking about it and the more energy goes to the larger ball(s) but they reach the same height.
My other solution was also wrong, so 0 for 2 today.
The only further ponderance is if you actually made impact with the balls, all at the same time with the same object, then you would get different velocities.
1.put 2 balls on each side and let the 2 remaining off if the scale moves to one side u know that the heavy one is one that side if the scale doesn't move u know that the heavy on are the 2 remaining ones u didn't weight
2. take the 2 balls that that are heavyer (or the ones u didn't weight if the scale didn't move) and weight them the and u know it in 2 times :)
Step 4. With one turn left it needs to be determined which ball in the group is the different one. To do this divide the balls individually 1 thru 3. Measure ball 1 against ball 2. If they are balanced then its ball 3 that is the different one. If they are not balanced,use the density determined from step 3 to isolate the different ball.
Step 3. If group A, and group B are not balanced it has to be determined which group contains the different ball, and wether its heavier or lighter. To do this measure group A against group C. If balanced, then the ball is in group B. If unbalanced then the ball is in group A. The density of the ball can also be determined as the two balanced groups will be equally light, or equally heavy, with the density of the ball being the opposite of whichever result that may be.
Step 2b. If ball 1 and 2 are not balanced, determine which ball is different by measuring ball 1 against ball 3. If balanced, ball 2 is the different ball and its density can be determined by comparing it to ball 1. If not balanced, it is deduced that ball 1 is different. To get it's density, compare it against ball 3.
Step 1. Divide the balls into three groups of three and label them group A, group B, and group C.
Step 2. Weigh group A against group B. If group A is balanced with group B then the different ball is in group C. If this is the case move on to Step 2a. If however group A, and group B are not balanced, move on to Step 3.
Step 2a. Mark each ball in group C 1 thru 3. Measure ball 1 against ball 2. If 1 and 2 are balanced, then ball 3 is the different one. Compare the densities to determine wether ball 3 is heavier or lighter.
if 1,2 = 3,4 then 5,6> 1,2 then 5>6 5 is the odd one out, because we know from 1,2 being less the 5,6 that the odd one is heavier. so the only thing left is to way the last two of the odd pair, comparing the results if it being heavier or lighter then the other two well let you know odd is ighter heavier or lighter. confusing i know.
LOL.. dude.. this is stupid... If you can use the scale 3 times WTF? This is a nobrainer. Take two and scale them. Put them aside. If the two were identical continue. Scale the next two, if their identical as well, take one and scale it with one of the other two. If the next scaling is identical again, the lighter/heavier ball is the one remaining, unless you got different results the first or second time, meaning you would of had to carry on the same steps LOL
@Archm4ge I'm seriosly trying to not insult you right now... but are you stupid? you know from the first 2 scales or the first and last scale wich of the balls are the ordinary ones. Then you just have to find the one that doesnt have the same weight. What the hell is so hard to understand?
@WeAreChuckNorris i'm also seriously trying not to insult u... but your method has a flaw. U can use 3 turns to find out which ball is different, but u need 4 turns to find out whether the different ball is heavier or lighter.
@WeAreChuckNorris in case u are still wondering, lets say A vs B = balanced, C vs D = balanced, E vs C = balanced, with 3 turns used up, can u tell me if F is heavier or lighter?
@Archm4ge oh you have to tell if its lighter or heavier? A bit tricky I admit my fail, was not paying atention.
AB vs CD = balanced take A vs E = balanced and A vs F = unbalanced. Thats one way if you're lucky.
If AB vs CD = unbalanced remember which is heavier (ex AB heavier ) then A vs C = balanced A vs D = if balanced B is heavier , if A is heavier, D is the lighter one.
If ... A vs C = unbalanced (ex A is heavier ) take A vs D if balanced C is lighter, if A is different than D its the one.
a) If they are equal, the last one of the three is the odd one out
b) If they are not equal, test the third ball of those against one of the balls on the scale. If they are different, the ball that was on a scale all three times is the odd one. If they are the same, the one you took off for the final step (The one that was in the first two and not the third) is the ball
1) Take two balls out of the 6 and put the first one on one side and the second on the other.
2) if the they both weigh the same take the same two balls and put them together on one side of the scale.
3) out of the 4 remaining balls take two out and place both on the other side of the scale. If the scale titls take one ball from each side of the scale and if it is equal the ball you took out was the heavy one and if it rises or sinks the ball that remained was the lighter or heavier one.
Since the highest rated solution is wrong (because it disregards the possibility of a lighter ball):
1. test two against two. - If they're equal, test both remaining balls against a normal ball.
2. So the odd one is one of these four. Test both balls of the light pairs against each other. - they're equal? test a random one of the heavy pair against a normal ball * equal? the remaining ball is heavier. * unequal? tested ball is heavier. - they're unequal? The light ball is lighter.
@Theelepeltjel Of all the solutions that I read in the comments, yours is the only one that works. Even the top rated solution was incorrect(requiring too many weighings). They were on the right path though. What got most people was the lighter or heavier part of the problem. Good explanation.
YOu need to explain that you can put more than one ball in each side of the scale at a time.... the pic makes it look like you can only put one ball in at a time....
There has to be more to this puzzle, doesn't there? The answer is really simple: put a separate ball on each side of the scale each of the three times (6 balls total-3 trials) and whichever one falls is the heavier one.
You really don't need a scale at all. You have to lift them to the scale some how. You will have an idea if one is lighter or heavier than the rest as you are lifting them to the scale.....
@missdesignerdiva Not if the difference is minor. Bear in mind that despite what you may believe, your right-arm muscle mass isn't equal to that of your left arm, or very unlikely so. Thus one might feel lighter/heavier if you lift them at the same time with different arms, and if you don't lift them at the same time picking them up with one arm, you can't notice the slight difference in weight.
@TeachMeProperDancin Yes, I thought about that after I posted. But I went onto something else and forgot to remove the comment. LOL! Thanks Teach... I agree.
1:30secs. And @WaTuPMeTuBe21 , you're wrong, since we don't know if the ball is lighter or heavier. Solution: We have balls 1-6 1.Put 1&2 on one side, 3&4 on other. 2. Are they equal weight? YES - then go to A1. NO - go to B. A1.Put 1 on one side, 6 on the other. A2. Are they equal weight? YES - it's number 5. NO - It's number 6. B. Go over the same process with 1-3 (if equal, compare 1-2, if not, compare 1-4). In both cases, if equal, it's the only ball left, if not, it's the ball on the scale.
@renzling u'll see the diffrence but u wont be able to identify which is different and if it is heavier or lighter unless ur first or second guess is correct.
@reztreborn It can't be further from truth, since we don't know if the one ball is heavier or lighter. So when you put three balls on one side and three on the other one, the only thing you did, is that you wasted one turn (even in that case you can identify the ball with the chance lowered to 33.33%).
Assume A is odd. A B C 1 2 3 Weight 2 vs 2 [doesn't matter which as there are outcomes] 1) AB != 12; or 2) BC = 12 Result 2: If equal A vs 3. AC != 12 OR BC = 13 proves A as odd. Result 1: Swap 2. A1 != B2 [Weight same as before] vs B1 != A2 [Weight Swapped] Case 1, A is culprit as Weight distribution did not change. Case 2, A or 1 is culprit as weight swapped when they did. Isolate one of them. BC != A2 Proves A B1 = 23 also Proves A DONE.
I think you can pick them up to put them on the scale. Just not to measure their weight. They'd feel the same anyway, maybe only a tiny difference you wouldn't be able to notice. Just saying..
I've solved a similar puzzle from my school book that asks the exact same thing but with 12 coins instead of 8 snooker balls. It's still one odd coin that can heavier or lighter, solvable in 3 turns. Good luck on solving this one ^^,
1. Put d 2 balls on 1 side and the other 2 on the other side. f they r equal proceed to no 2.
2. Put d remaining 2 balls on d scale. Put them seperately. We will now have d lighter or d heavier. But Still we don't know if it is lighter or heavier.
3. Pick 1 from d heavier or lighter 1. But it doesn't matter which one you have chosen. If you pick d heavier one. Put it on one side of d scale then get a ball from d other 4 balls that you have used earlier. If d heavier is still heavier then we have d answer for HEAVIER. If d heavier is equal to d one that we use then d LIGHTER one is d one that we left on d step no 2.
1. Put d 2 balls on one side and the other 2 on the other side. If They are not equal then again it doesn't matter if you choose the lighter one or the heavier one. But I will just choose the (2 balls)heavier.
2. Put the (2 Balls)heavier on one side then the remaining 2 on the other side. If it is equal then we should scale the lighter one seperately on the step no. 1. Then we will get the LIGHTER ONE and this will be the LAST STEP. If the (2 Balls)heavier is still heavier then we will just scale it again.
3. Scale again the (2 Balls) Seperately. Here we should get which one is heavier.
I Hope This Will Help You.
And I'm sorry if my grammar is wrong because I just know simple English.
but heavier than the other that means that the ball from the lighter side is the lighter ball... if it is heavier than both of the balls it means that ball is heavier
no matter the outcome of your original measurement you can figure out which ball is out of place AND if it is lighter or heavier in two additional moves
1) take the 2 balls on the left, and two balls and the 2 balls on the right - if they are the same weight then you simply compare each of the remaining balls against any of the original 4 balls, one will be heavier or lighter
- if one side is heavier or lighter take one ball from the heavier side and measure it against the two balls from the lighter side... if those are all of equal weight it is the other ball from the heavier side, if it's equal to one of the balls from
Alas I don't know which is heavier or lighter. People solved this with 2 comparisons, but heres my solution
Name balls, a,b,c,d,e,f. Compare ab and cd. If ab=cd then ef is the weighted ball (w.b), compare a with e. If a =e then the answer is f, else the answer is e.
If ab =/= cd then remove a and c. If b=d then ac is the w.b, compare a with b. If a=b then the answer is c, else the answer is a.
If b =/= d then bd is the w.b, compare b with a. If b=a then d is the w.b, else b is the answer.
I find it amusing that everyone has a solution on HOW to find the ball but not whether its heavier or lighter. Though there's probably an issue with the problem definition.
@WaTuPMeTuBe21 not that easy. you've sepparated 3 balls (and one of them is allegedly heavier than all the other 5).
BUT on the the video it says that the ball may be LIGHTER or HEAVIER. what if the ball weights indead less than it was supposed to, and you've chosen the wrong 3 balls?
Because if this is the case, the 3 balls that you've sepparated all weigh the same. And then you can't draw any conclusion
U r wrong bro the puzzel says one of them could be heavier or lighter u do not know its heavy or light so the
heavier side could be normal and instead other side was lighter
here is answer:
u pick 4 balls put them on each side contains 2 balls if both side was balanced we know that the other 2 balls has different weights otherwise we know the other ball(heavier or lighter) is in this 4 balls_this is 1st move
in second case(hold first theory) we grab one ball of each side and...
test their weight if there was equal we know that other 2 of them are different otherwise we know we got the different one this is our second move
and the 3rd move is (now we got 2 balls that one is heavier or lighter than other) we just pick a random of two balls and test it with other 4 balls the point of this move is we understand which balls is different and is it heavier or lighter(as we know the other 4 r equal and if the 3rd move result was equal the other ball is differen
@WaTuPMeTuBe21 you'd only be able to use the scale 1 more time after step 2, how would you know the second set of three balls is heavier than the first set of three balls. He said you have to use the scales not hold them in your hand to see which is lighter, that's cheating!
@Zinx10 Well he said you have to use the scales 3 times. I don't think you're allowed to pick up the balls with your hand, after all, he said they all look and feel the same.
In order to use the scale, you must pick up the balls for the scale is off the ground, so are you basically saying don't touch them? Also if they look and feel the same, why wouldn't you be able to pick them up?
@nn44n4 He has the correct solution. In step two, when you set aside the heavier side, you know that if the defective ball is in that side it is too heavy, and if it's in the side you're about to test, it's too light.
What if the differently weighted ball was lighter? you don't know whether the ball is lighter or heavier, therefor you can not assume that the heavier side of the scale has the differently weighted ball because the lighter side could very well have it too.... im sorry but you are wrong....
@WaTuPMeTuBe21 knw u r upset of replies, jst tellin u the sol.
Divide in 3 groups A, B, C of 2 balls each.
Case 1: W1 -> A=B implies C has false ball. W2-> Definitely A=/=C (as C has false ball). W3-> the two balls of C. False ball = heavier or lighter depend on W2.
Case 2: W1 -> A=/=B ; W2 -> A=C implies B has false ball. W3-> two balls of B and false ball dependin on W1.
Case 3: W1-> A=/=B ; W2 -> A=/= C implies A has False Ball. W3 -> two balls of A and false ball depending on any W1,W2.
@WaTuPMeTuBe21 You don't know if the different ball is heavier or lighter. You will have to use your third turn weighing the other set of three, using the technique you mentioned.
@WaTuPMeTuBe21 No. The third turn would be used to tell whether it is heavier or lighter (since you don't address that in your answer). Also, just because 2 are different weight doesn't make the heavier one different since the different one could also be lighter.
@WaTuPMeTuBe21 nice solution, except for the obvious error of "what if the ball that was different if actually lighter?" then you are using the wrong set all together.
@WaTuPMeTuBe21 xDxD LOL you're a moron. One is lighter or heavier. Thats not the way to solve it. Bwahahha.... What you're saying is take the heavier set aside and scale 2 of them? What if one of the balls is lighter and its in the other set? LMAO I cant belive 10 people thumbed you up.. Im starting to lose hope in humanity xDXDXD
If you cant solve this one right away you're verry dumb
firewrkhooligan 3 days ago in playlist Meer video's van Woyano
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7Slayde 3 days ago
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7Slayde 3 days ago
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7Slayde 3 days ago
weigh 2:2. Now weigh any 2 of them with another 2. If they are the same, take one of the balls from the other 2, weigh it with one of the normal balls. If it is the desired answer, it is either lighter or heavier. If not, then the other ball is it. Voila!
Sanitoeter666 5 days ago in playlist Weitere Videos von Woyano
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Sanitoeter666 5 days ago in playlist Weitere Videos von Woyano
6? You can do this for 12 balls with 3 tries :|
Akshaylive 1 week ago
@Akshaylive No you can't.
bigbig1604 4 days ago
1. take 1 ball on each side. If they’re not the same, then shift one with another. If these are the same, the one you shifted out is lighter/heavier. If they’re not the same, the one that wasn’t shifted out is lighter/heavier
If the balls were equal at the first time, take another two and do as before
If the balls were equal, then shift one ball with one of the last balls. If they now are equal, then the last one is lighter/heavier. If they’re not the same, the ball you just put is the one
einargregersen 1 week ago
@einargregersen but you have to say if it is lighter OR heavier.
Getnill 1 week ago in playlist More videos from Woyano
And here's a question for you - You have 10 chocolate making machines, each one making chocolates that weigh exactly 50 grammes. One of the machines got broken and makes chocolates that weigh only 49 grammes. Using an electronic scale, measure ONLY ONCE to find which one is broken! Beat that, geniuses of this world! :)
Fullmetal21000 3 weeks ago
@Fullmetal21000 you just put different quantities of chocolates of each machine
borysco 1 week ago
The solution - Put 3 balls each side, then see which side is lighter. Pick the balls from lighter side and take one ball each side. If one side is lighter, then thats the ball. If they're equal, then the other ball is lighter!
Fullmetal21000 3 weeks ago
@Fullmetal21000
wrong mate
fullysickmick01 2 weeks ago
you wiegh 2 at a time and use that 3 times........ first time if 2 balls are the same you move on to the next 2...... if those are the same..... you scale the last 2 and you got a winner.....
bananen12 3 weeks ago
@bananen12 But which of the last two is the lighter or heavier one?
benJAMMIN745 3 weeks ago in playlist More videos from Woyano
@benJAMMIN745 you scale the last 2 and wich ever tips the scale is obviously the lighter or hevier one. im not good at explaining things. sry
bananen12 3 weeks ago
@bananen12 Not what I mean, let me rephrase. How do you tell if the heavier ball of the two is heavier than the other five, or if the lighter of the two is lighter than all five? It's not possible, considering you can't weigh the balls anymore.
benJAMMIN745 3 weeks ago
@benJAMMIN745 yea i understand you now :P but yea i figured out another way :P
bananen12 3 weeks ago
This has been flagged as spam show
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paradiseinfinity 3 weeks ago
the problem that I keep seeing in the solutions is that people assume that the ball is heavier when it could be heavier or lighter. the only way to figure it out is to know one of the normal ones. if you know that then you can solve the puzzle.
sean31sldier 4 weeks ago
I can do this with 9 balls and 2 times
ScaffaBoy18 1 month ago
3 balls each side, one side will be lighter, take that 3 balls, weight 2 of them, if they're balanced, the other ball is the light one, if one is lighter, then it's the light one.
dandyboykb 1 month ago
woyano took me to a blender website WTF?
GamerLel2001 1 month ago
Dam my comment got cut.. Too lazy to write again
akepolat59 1 month ago
Ok..got it(hope right) in 5 mins without paper:
1. You put on each side 2 balls -If both sides are equal, you know the Lighter or heavier ball has to be one of 2 which are left. You grab one, weight it With one of the normals. If the side of the Side of the normal goes up, you have a Heavier ball, else lighter.
2. Second case: You put 2 on each side and 1 goes up. You switch the one with the 2 Left balls. If its now equal, one of the 2 Balls we
akepolat59 1 month ago
@akepolat59
That doesnt work mate
fullysickmick01 2 weeks ago
Not sure about the series title for this one... This is better for revealing mental retardation through failure than uncovering genius through success.
PrinceOfPerelandra 1 month ago
1 put two balls on one side and two on the other if on side is heavier than compare the two balls that u have on that side (one vs one) and you r done in two uses of the scale.
If the 1 st test ( 4 balls) comes out with equal Sides than definetly the heavy ball is among the other two that u haven t tested yet and again proceed into compairing this two left ball and you r done two steps no need for the 3rd one.
khaver1981 1 month ago
@khaver1981 Your response assumes that the different ball will always be heavier. The vid says one ball is either lighter OR heavier. Figure out what ball is different and is it lighter or heavier.
gregrbenson 1 month ago
eaaaassy and yh this was on professor layton i love the prof laytons gettin the newest 1 spectres call 4 christmas =D
elekid147 1 month ago in playlist More videos from Woyano
For this to be an actual challenge, there should be 12 balls. and your task is to do the same thing. I spent two days scratching my head before solving it.. quite tricky
joshiijoshii 1 month ago
This puzzle was on Layton
roadcrosser 1 month ago
1:02 Meeeeoooowww..... :3
nakdemenMUSE 2 months ago
these are not puzzles. these are common sense... all of your videos are common sense. Calling them complicated just makes people feel smart for knowing what my 5 year old niece should.
zxenen 2 months ago
it's really easy.. you can solve it by using the scale only twice.
Mianzz 2 months ago
Comment removed
BastaBat666 2 months ago in playlist More videos from Woyano
its not possible, its trail and error.. We find solutions that ain't there sometimes because we are convinced there has to be one. Realising it is not possible is hard because the mind wants an answer.
GuitarJK1988 3 months ago
Place 3 balls on each side. The side with the lighter ball will raise up. Remove one ball from each side till the scale is level and you will find the lightest ball. Pen and paper not needed.
teslaminded1 3 months ago
whats a snooker?
darnpotato 3 months ago
can do it.
pokemon5678ification 4 months ago
@pokemon5678ification SPOILER. (made @ reverse text generator) .modnar ta llab lamron a tsniaga eno hgiew niaga ,elacs eht no si ti ton fi llab ddo eht evah uoy secnalab elacs eht fI
.owt rehtona evomer uoy elacs eht ecnalab ton did sllab owt tsrif eht gnivomer fI
.rehto eht si llab ddo eht wonk uoy emas eht shgiew ti fI .tceles ton did uoy llab a htiw gnola kcab eno ecalP .llab ddo eht detceles evah uoy
secnalab elacs eht fI .edis hcae morf eno evomer ,edis hcae no sllab 3 ecalP
planetofthescums 3 months ago
surely its simple they are all the same bar one so just do them in pairs and only the lighter/heavier one will show a difference, or perhaps im under thinking it
thickmott123 4 months ago
(1) Put 2 balls on each side. If one side is heavier, (2) remove 1 ball from each side, if the same, (2) test a ball of same mass with a ball of unknown mass. If one ball is heavier, (3) weigh that ball with a ball of known mass.
If it is one of the other 2 balls, (2) test one ball with a ball of known mass, if the same, (3) test the other with a ball of known mass.
PaladinswordSaurfang 4 months ago
@PaladinswordSaurfang like that.
pokemon5678ification 3 months ago
Another solution is putting all 6 balls in [ 3 on each side] one side will of course be lighter or heavier, remove a ball from both sides if they balance compare the ball from the heavier side to the lighter side and you will know which disrupts the equilibrium
t3hownzer 4 months ago
@t3hownzer it doesn't work. e.g.
(1) 3 balls on each side, one heavier.
(2) 2 balls on both sides, one heavier
(3) 1 ball on both sides, one heavier, but which one?? ...your method requires 4 tests
PaladinswordSaurfang 4 months ago
I've seen something harder. It's exactly the same, but the only thing is there are 12 balls and you are still, only allowed to use the balance scale 3 times.
There are many solutions on google for this 12 balls too. I'm not kidding. 6 balls is too easy and even with 12 balls, it is still solvable.
L3irus 4 months ago
Some people are just fucking stupid.
Guys, everyone's saying "take off the lighter one, that's it" No, dipshits. It's lighter OR heavier - you don't know that. It can't be done in two steps.
namerlis 4 months ago
this can done with 2 step dude
bitoyak 4 months ago
You could spend hours trying to get it orrr..... GET A LIFE who cares????
DesertEagle2222 5 months ago
It's funny how many people who don't understand the statement of the puzzle try anyway and put their answer...
boumbh 5 months ago
Why the heck do you need a scale to see which is the lightest?
Loboblancoazul 5 months ago
just 6 ??? I solved the one with 12 using scale 3 times.
shivandrag0n 5 months ago
1. weigh the balls 3 on each side, then take the balls from the lighter side of the scale
2. take an extra ball (from the previous heavier side) and split the 3 balls (from the lighter side) in 2 like 2 and 1 + 1 (extra ball), then weigh it again
3. again, take the lighter side and weigh those balls, one on each side of the scale and voila
CRIMAFUYT 6 months ago
Easy Put two on each side When one side is lighter get another ball on the lighter side and if its still the same then the other ball is to light and that is a the answer
THE 10 YEAR OLD HAS SPOKEN!
HBzTV 6 months ago
I CAN DO IT WITH 2 WEIGHINGS!!!!!!
1.weigh it with three on each side which ever side is lighter than take those three balls and discard the other three.
2. weigh 2 of those three if they are equal than the one you left out is the light one if they are un even than the one that the scale shows is lighter than that is the light one
cweida111 6 months ago
number the balls 1to 6.
1. weigh 1 and 2. if one of lighter, then you have found. if not, they're the same.
2. move on and weigh 3 and 4. if one is lighter, you found it. if not, they're the same.
3. move one nd weigh 5 and 6. if you have found the lighter by now, it will have to be one of either 5 or 6.
seanncali 6 months ago
took me one attempt a.k.a 20 seconds
LozyJC 6 months ago
Figured it out in about 5 minutes. I did it differently than the other guy.
ClusiveC 6 months ago
That's easy
chudoyudo17 6 months ago 11
..if they are even you know that the set you just pulled off the scales have the mystery ball . if the scale moves you know that the mystery ball is still on there. Now by taking note the round before you will know whether or not the set on the table or the one on the scales had a lighter or heavier ball...so you weigh which ever set was out individually ( 1 on each side of the scales) and you then know which ball is the different one and also whether it is heavier or lighter than the rest )
JJJWESTCOAST 7 months ago
have to see which ball wins and then you have your ball and the answer.
Now if back at stage 1 you put 2 sets of 2 balls on the scales and they were not even...you will know that the 2 balls on the table that weren't measured are 2 regular balls. You have to now take note of what happened to the first 4 balls you measured which set was heavier or lighter. Now leave 1 set of balls on the scales as is and remove the other set and replace it with the set on the table
JJJWESTCOAST 7 months ago
The answer is to weigh any 4 balls ( 2 each side) then if the scales are even the mystery balls is one of the 2 balls not on the scales . In which case you leave the 1 set of 2 balls on the scale as is and put the new set on ...you’ll now know if the mystery ball is lighter or heavier by the fact it outweighs or doesn't outweigh the previous 2...you now take that new set and weigh them individually knowing that the ball you are looking for is lighter or heavier you just
JJJWESTCOAST 7 months ago
I got the answer correct... :)
MrGowthambc 7 months ago
Can I borrow more one nomal ball?
DestructiveExpert 7 months ago
The solution is actualy taking 4 balls (2 on each side), 2 things could happen:
If they are balanced, then put the other 2 balls and compare, then get the heavier and compare with some of the first two balls, if it's heavier, then that ball would be the different(and heavier) else the other ball was the lighter, else, if in the first step some side was heavier, take those 2 balls and compare, if they are equal, then the lighter ball is in the other 2 balls (you just need to compare them)
bigbig1604 7 months ago 17
@bigbig1604 There are many solutions. I have one which uses the scale only once.
(made @ reverse text generator)
.rewol ro rehgih og rehtie lliw llab enO .tsif ruoy htiw yltfiws elacs eht fo dne rehto eht kcamS
.hcuot ton od yeht os ylluferac yrev ;elacs eht fo edis eno no rehtegot sllab xis lla ecalP
planetofthescums 3 months ago
@planetofthescums That's not even a solution, first you dont know if the scale is large enough to fit the 6 balls without touching each other, second, that's not right, the height they get does not depend of their weight.
bigbig1604 3 months ago
@bigbig1604 Why not?
planetofthescums 3 months ago
@planetofthescums Have you ever studied any physics? did you know that the speed of an objet falling only depends on how they move through the fluid they are in? and, as the balls are suposed to be of the same shape and size, they will move the same way.
bigbig1604 3 months ago
@bigbig1604 Ok. The rate of a falling object only depends on its mass. What about the energy the scale imparts on said objects creating accelerations relative to their mass?
planetofthescums 3 months ago
@planetofthescums rate of a falling objet does NOT depend on its mass, and, the scale impart energy according to it's mass, yes, but the acceleretion they get its the same, because the scale is suposed to be rigid, thus every objet leaves the scale with the same speed.
bigbig1604 3 months ago
@bigbig1604 Sorry. I was up late when I typed that. I meant to say fall is independent of mass, like you said.
I suspect you are right that they leave the balance at the same speed. I was thinking about it and the more energy goes to the larger ball(s) but they reach the same height.
My other solution was also wrong, so 0 for 2 today.
The only further ponderance is if you actually made impact with the balls, all at the same time with the same object, then you would get different velocities.
planetofthescums 3 months ago
@planetofthescums Well yes, that last one could work, but it is not very precise if the weights barely differ.
bigbig1604 3 months ago
@bigbig1604 I tried doing this with a couple of objects and you would need to go to great lengths to try and prove this works.
planetofthescums 3 months ago
@bigbig1604
Yea but the things i mate you dont know that the ball is heavier than all the others... 1 of them is lighter OR heavier
fullysickmick01 2 weeks ago
@fullysickmick01 I considered both cases in my solution if you read well.
bigbig1604 2 weeks ago
@bigbig1604 1 fo them is lighter OR heavier so u cant actually determine it that way
archiegeo 1 week ago
@archiegeo I don't understand, i considered both cases, that the ball can be either lighter or heavier.
bigbig1604 1 week ago
u can do it in 2 times
1.put 2 balls on each side and let the 2 remaining off if the scale moves to one side u know that the heavy one is one that side if the scale doesn't move u know that the heavy on are the 2 remaining ones u didn't weight
2. take the 2 balls that that are heavyer (or the ones u didn't weight if the scale didn't move) and weight them the and u know it in 2 times :)
jaguartje 7 months ago
u look like KIPKAY
MiteDyno 7 months ago
Step 4. With one turn left it needs to be determined which ball in the group is the different one. To do this divide the balls individually 1 thru 3. Measure ball 1 against ball 2. If they are balanced then its ball 3 that is the different one. If they are not balanced,use the density determined from step 3 to isolate the different ball.
PrimorisVir 7 months ago
Step 3. If group A, and group B are not balanced it has to be determined which group contains the different ball, and wether its heavier or lighter. To do this measure group A against group C. If balanced, then the ball is in group B. If unbalanced then the ball is in group A. The density of the ball can also be determined as the two balanced groups will be equally light, or equally heavy, with the density of the ball being the opposite of whichever result that may be.
PrimorisVir 7 months ago
Step 2b. If ball 1 and 2 are not balanced, determine which ball is different by measuring ball 1 against ball 3. If balanced, ball 2 is the different ball and its density can be determined by comparing it to ball 1. If not balanced, it is deduced that ball 1 is different. To get it's density, compare it against ball 3.
PrimorisVir 7 months ago
Step 1. Divide the balls into three groups of three and label them group A, group B, and group C.
Step 2. Weigh group A against group B. If group A is balanced with group B then the different ball is in group C. If this is the case move on to Step 2a. If however group A, and group B are not balanced, move on to Step 3.
PrimorisVir 7 months ago
Step 2a. Mark each ball in group C 1 thru 3. Measure ball 1 against ball 2. If 1 and 2 are balanced, then ball 3 is the different one. Compare the densities to determine wether ball 3 is heavier or lighter.
PrimorisVir 7 months ago
remember, u have the find out which ball is DIFFERENT, and whether it is HEAVIER or LIGHTER.
balls ABCDEF. weigh AB vs CD, if balanced, weigh E vs A and F vs A. (3 turns)
if AB vs CD is unbalanced (assume AB is heavier), weigh A vs B, if unbalanced (assume B is heavier), then answer is "Ball B is heavier" (2 turns)
if A vs B is balanced, weigh C vs D (assume C is heavier), then answer is "Ball D is lighter" (3 turns)
thumbs up if u agree
Archm4ge 7 months ago in playlist puzzle 1
@Archm4ge lol... didnt saw you allready posted the answer... *embaresed*
WeAreChuckNorris 7 months ago
if 1,2 = 3,4 then 5,6> 1,2 then 5>6 5 is the odd one out, because we know from 1,2 being less the 5,6 that the odd one is heavier. so the only thing left is to way the last two of the odd pair, comparing the results if it being heavier or lighter then the other two well let you know odd is ighter heavier or lighter. confusing i know.
kayladanyel08 7 months ago
Comment removed
kayladanyel08 7 months ago
Easy ask Chuck Norris
rickycottonrocks 7 months ago
LOL.. dude.. this is stupid... If you can use the scale 3 times WTF? This is a nobrainer. Take two and scale them. Put them aside. If the two were identical continue. Scale the next two, if their identical as well, take one and scale it with one of the other two. If the next scaling is identical again, the lighter/heavier ball is the one remaining, unless you got different results the first or second time, meaning you would of had to carry on the same steps LOL
WeAreChuckNorris 7 months ago
@WeAreChuckNorris but then u exhausted your turns to find out whether it is heavier or lighter
Archm4ge 7 months ago in playlist puzzle 1
@Archm4ge I'm seriosly trying to not insult you right now... but are you stupid? you know from the first 2 scales or the first and last scale wich of the balls are the ordinary ones. Then you just have to find the one that doesnt have the same weight. What the hell is so hard to understand?
WeAreChuckNorris 7 months ago
@WeAreChuckNorris i'm also seriously trying not to insult u... but your method has a flaw. U can use 3 turns to find out which ball is different, but u need 4 turns to find out whether the different ball is heavier or lighter.
Archm4ge 7 months ago in playlist puzzle 1
@WeAreChuckNorris in case u are still wondering, lets say A vs B = balanced, C vs D = balanced, E vs C = balanced, with 3 turns used up, can u tell me if F is heavier or lighter?
Archm4ge 7 months ago in playlist puzzle 1
@Archm4ge oh you have to tell if its lighter or heavier? A bit tricky I admit my fail, was not paying atention.
AB vs CD = balanced take A vs E = balanced and A vs F = unbalanced. Thats one way if you're lucky.
If AB vs CD = unbalanced remember which is heavier (ex AB heavier ) then A vs C = balanced A vs D = if balanced B is heavier , if A is heavier, D is the lighter one.
If ... A vs C = unbalanced (ex A is heavier ) take A vs D if balanced C is lighter, if A is different than D its the one.
WeAreChuckNorris 7 months ago
im not gonna try
zombiekilla1911 8 months ago
To add to WaTuPMeTube21's solution, after step 3:
a) If they are equal, the last one of the three is the odd one out
b) If they are not equal, test the third ball of those against one of the balls on the scale. If they are different, the ball that was on a scale all three times is the odd one. If they are the same, the one you took off for the final step (The one that was in the first two and not the third) is the ball
BaXeD22 8 months ago
1) Take two balls out of the 6 and put the first one on one side and the second on the other.
2) if the they both weigh the same take the same two balls and put them together on one side of the scale.
3) out of the 4 remaining balls take two out and place both on the other side of the scale. If the scale titls take one ball from each side of the scale and if it is equal the ball you took out was the heavy one and if it rises or sinks the ball that remained was the lighter or heavier one.
Twwistad 8 months ago
Since the highest rated solution is wrong (because it disregards the possibility of a lighter ball):
1. test two against two. - If they're equal, test both remaining balls against a normal ball.
2. So the odd one is one of these four. Test both balls of the light pairs against each other. - they're equal? test a random one of the heavy pair against a normal ball * equal? the remaining ball is heavier. * unequal? tested ball is heavier. - they're unequal? The light ball is lighter.
Theelepeltjel 8 months ago
@Theelepeltjel Of all the solutions that I read in the comments, yours is the only one that works. Even the top rated solution was incorrect(requiring too many weighings). They were on the right path though. What got most people was the lighter or heavier part of the problem. Good explanation.
merryass 1 month ago
@merryass Yeah, it's pretty funny how half of the comments bitch about this problem being too easy and the other half give false solutions :)
Theelepeltjel 1 month ago
YOu need to explain that you can put more than one ball in each side of the scale at a time.... the pic makes it look like you can only put one ball in at a time....
jerichomutant 8 months ago
too easy
vlejdd 8 months ago
1 ) 3 balls on the left ...3 balls on the right
(one side will be heavier ..one side will be lighter)
2) remove one ball from the left....one ball from the right
(if the scale levels off ..you will have the answer in your hand)
if not..then
3) remove another ball from the left...another ball from the right
(if the scale levels off ..you will have the answer in your hand)
if not then the answer is sitting on the scale.
vmxten 9 months ago
I only like Female Snookers...
They dont have balls.
vmxten 9 months ago
There has to be more to this puzzle, doesn't there? The answer is really simple: put a separate ball on each side of the scale each of the three times (6 balls total-3 trials) and whichever one falls is the heavier one.
JohnnieNaked 9 months ago
Lol. That took me about 10 seconds. . . I thought I was wrong until I read WaTuPMeTuBe's solution.
ImTheBatchMan 9 months ago
@ImTheBatchMan watupmetube's solution was wrong though, so doesn't that mean your's is wrong too?
kradrol 8 months ago
You really don't need a scale at all. You have to lift them to the scale some how. You will have an idea if one is lighter or heavier than the rest as you are lifting them to the scale.....
missdesignerdiva 9 months ago
@missdesignerdiva Not if the difference is minor. Bear in mind that despite what you may believe, your right-arm muscle mass isn't equal to that of your left arm, or very unlikely so. Thus one might feel lighter/heavier if you lift them at the same time with different arms, and if you don't lift them at the same time picking them up with one arm, you can't notice the slight difference in weight.
TeachMeProperDancin 9 months ago
@TeachMeProperDancin Yes, I thought about that after I posted. But I went onto something else and forgot to remove the comment. LOL! Thanks Teach... I agree.
missdesignerdiva 9 months ago
orlopcz 9 months ago
Good puzzle i solved it
Mrlaydown0 9 months ago
You can do this same puzzle with 12 balls and the same number of weighing opportunities!
It is substantially more complicated, though.
1337SuperNewb 9 months ago
Comment removed
autmnleaf 9 months ago
dont know if this has been posted before but this is kinda stupid.
just take the first two balls, then the second two, then the third two balls.
if one of them is lighter or heavier you see it anyway
renzling 9 months ago
@renzling u'll see the diffrence but u wont be able to identify which is different and if it is heavier or lighter unless ur first or second guess is correct.
Cuma9 9 months ago
@Cuma9 uups. i overheard that i also have to find out if its heavier or lighter
so i guess im not a genius ;)
renzling 9 months ago
If one more fucking person replys to my comment im gonna blow up youtube, ITS WRONG!!! I KNOW ITS FUCKING WRONGE LEAVE ME ALONE!!!!
WaTuPMeTuBe21 9 months ago
@WaTuPMeTuBe21 Dude ur answer is wrong
jo892734 9 months ago
@jo892734 Nope. I think it's correct. Explain please
reztreborn 9 months ago
@reztreborn It can't be further from truth, since we don't know if the one ball is heavier or lighter. So when you put three balls on one side and three on the other one, the only thing you did, is that you wasted one turn (even in that case you can identify the ball with the chance lowered to 33.33%).
orlopcz 9 months ago
wtf people stop thumb's up my comment, i messed up when i was wrighting the commet, ITS WRONG
WaTuPMeTuBe21 9 months ago
Hukeyohi 9 months ago
Its too easy. Got it in likt 2 secs..sorry for the word limit:(
YakaProduction 11 months ago
1. Group in 2 [ab] [cd] [ef]
2. Measure [ab] vs [cd]
3. if[ab] = [cd] Then goto 4 else goto 6
4. remove [cd] and place [ef]
5. surely [ab] != [EF], you know AB is good, so if EF is weighter, the defective ball is weighter or else it is lighter.
6. if [ab] != [cd],
replace [cd] with [ef],
YakaProduction 11 months ago
if[ab] == [ef], we know that the deffective ball is in [CD]
and we know that if [ab] was heavier that [cd] then the deffective
ball is lighter
if[ab] != [ef]
we know that the defective ball is in [ab] and we know
that [cd] = [ef]
so if [ef] is heavier than [ab] deffective ball is lighter or else it it heavier
YakaProduction 11 months ago
I think you can pick them up to put them on the scale. Just not to measure their weight. They'd feel the same anyway, maybe only a tiny difference you wouldn't be able to notice. Just saying..
tristan9812 11 months ago
You can put 2-2 and leave the other two on the floor.....then it will be very easy to solve it
jharitos 11 months ago
I've solved a similar puzzle from my school book that asks the exact same thing but with 12 coins instead of 8 snooker balls. It's still one odd coin that can heavier or lighter, solvable in 3 turns. Good luck on solving this one ^^,
imusthegreat 1 year ago
This Is The First Situation
1. Put d 2 balls on 1 side and the other 2 on the other side. f they r equal proceed to no 2.
2. Put d remaining 2 balls on d scale. Put them seperately. We will now have d lighter or d heavier. But Still we don't know if it is lighter or heavier.
mcmxxxiii0023 1 year ago
3. Pick 1 from d heavier or lighter 1. But it doesn't matter which one you have chosen. If you pick d heavier one. Put it on one side of d scale then get a ball from d other 4 balls that you have used earlier. If d heavier is still heavier then we have d answer for HEAVIER. If d heavier is equal to d one that we use then d LIGHTER one is d one that we left on d step no 2.
mcmxxxiii0023 1 year ago
This Is The Second Situation
1. Put d 2 balls on one side and the other 2 on the other side. If They are not equal then again it doesn't matter if you choose the lighter one or the heavier one. But I will just choose the (2 balls)heavier.
mcmxxxiii0023 1 year ago
2. Put the (2 Balls)heavier on one side then the remaining 2 on the other side. If it is equal then we should scale the lighter one seperately on the step no. 1. Then we will get the LIGHTER ONE and this will be the LAST STEP. If the (2 Balls)heavier is still heavier then we will just scale it again.
3. Scale again the (2 Balls) Seperately. Here we should get which one is heavier.
I Hope This Will Help You.
And I'm sorry if my grammar is wrong because I just know simple English.
mcmxxxiii0023 1 year ago
Comment removed
mcmxxxiii0023 1 year ago
Comment removed
mcmxxxiii0023 1 year ago
wheiner.com?
zodiac19931993 1 year ago
yay...i figured it out :p
SleepyHaw 1 year ago
but heavier than the other that means that the ball from the lighter side is the lighter ball... if it is heavier than both of the balls it means that ball is heavier
no matter the outcome of your original measurement you can figure out which ball is out of place AND if it is lighter or heavier in two additional moves
watwoodthefonzdo 1 year ago
The real solution
1) take the 2 balls on the left, and two balls and the 2 balls on the right - if they are the same weight then you simply compare each of the remaining balls against any of the original 4 balls, one will be heavier or lighter
- if one side is heavier or lighter take one ball from the heavier side and measure it against the two balls from the lighter side... if those are all of equal weight it is the other ball from the heavier side, if it's equal to one of the balls from
watwoodthefonzdo 1 year ago
Alas I don't know which is heavier or lighter. People solved this with 2 comparisons, but heres my solution
Name balls, a,b,c,d,e,f. Compare ab and cd. If ab=cd then ef is the weighted ball (w.b), compare a with e. If a =e then the answer is f, else the answer is e.
If ab =/= cd then remove a and c. If b=d then ac is the w.b, compare a with b. If a=b then the answer is c, else the answer is a.
If b =/= d then bd is the w.b, compare b with a. If b=a then d is the w.b, else b is the answer.
Saruukhai 1 year ago
I find it amusing that everyone has a solution on HOW to find the ball but not whether its heavier or lighter. Though there's probably an issue with the problem definition.
Saruukhai 1 year ago
Oops lol never mind.
WaTuPMeTuBe21 1 year ago
----------------Solution Thumbs up so people can see it ---------------
1. Put three of them on one side, and the other three on the other side.
2. Which ever side is heavier Take those three ball and set the to the side,
You now have 2 turns left,
3. Take the three heavier set and take two of the three and put them on the scale
if one is heavier then thats the different one, if their the same then its the one that you never put on the scale.
All solved with still one turn to use the scale :D
WaTuPMeTuBe21 1 year ago 17
@WaTuPMeTuBe21 not that easy. you've sepparated 3 balls (and one of them is allegedly heavier than all the other 5).
BUT on the the video it says that the ball may be LIGHTER or HEAVIER. what if the ball weights indead less than it was supposed to, and you've chosen the wrong 3 balls?
Because if this is the case, the 3 balls that you've sepparated all weigh the same. And then you can't draw any conclusion
sacana123456789 1 year ago
@sacana123456789 Thats why i said "oops nvm" in my other comment, however my way can work if you get lucky :D
WaTuPMeTuBe21 1 year ago
@WaTuPMeTuBe21 well yeah, but then how can it be solved? :O
sacana123456789 1 year ago
@WaTuPMeTuBe21 thats not the whole solution cause the odd ball is either heavier or lighter
hamidul93 1 year ago
@WaTuPMeTuBe21
Doesn't work; he said it could be lighter OR heavier, your solution only works if it is heavier.
MW9000cows 1 year ago
@WaTuPMeTuBe21 And if the one you're looking for is lighter than the rest, you've failed.
articuno1508 1 year ago
@WaTuPMeTuBe21
U r wrong bro the puzzel says one of them could be heavier or lighter u do not know its heavy or light so the
heavier side could be normal and instead other side was lighter
here is answer:
u pick 4 balls put them on each side contains 2 balls if both side was balanced we know that the other 2 balls has different weights otherwise we know the other ball(heavier or lighter) is in this 4 balls_this is 1st move
in second case(hold first theory) we grab one ball of each side and...
shimolishimo 1 year ago
@WaTuPMeTuBe21
test their weight if there was equal we know that other 2 of them are different otherwise we know we got the different one this is our second move
and the 3rd move is (now we got 2 balls that one is heavier or lighter than other) we just pick a random of two balls and test it with other 4 balls the point of this move is we understand which balls is different and is it heavier or lighter(as we know the other 4 r equal and if the 3rd move result was equal the other ball is differen
shimolishimo 1 year ago
@WaTuPMeTuBe21 and if it is a ligther ball?
josenimo 11 months ago
@WaTuPMeTuBe21 you'd only be able to use the scale 1 more time after step 2, how would you know the second set of three balls is heavier than the first set of three balls. He said you have to use the scales not hold them in your hand to see which is lighter, that's cheating!
tristan9812 11 months ago
@tristan9812
Uhh...are you trying to be a troll?
Zinx10 11 months ago
Comment removed
tristan9812 11 months ago
@Zinx10 Well he said you have to use the scales 3 times. I don't think you're allowed to pick up the balls with your hand, after all, he said they all look and feel the same.
tristan9812 11 months ago
@tristan9812
In order to use the scale, you must pick up the balls for the scale is off the ground, so are you basically saying don't touch them? Also if they look and feel the same, why wouldn't you be able to pick them up?
Zinx10 11 months ago
@WaTuPMeTuBe21 one of the balls can be lighter or heavier.in your method it will only work if it is heavier than the rest
nn44n4 11 months ago
@nn44n4 He has the correct solution. In step two, when you set aside the heavier side, you know that if the defective ball is in that side it is too heavy, and if it's in the side you're about to test, it's too light.
noobicus2 11 months ago
@WaTuPMeTuBe21
What if the differently weighted ball was lighter? you don't know whether the ball is lighter or heavier, therefor you can not assume that the heavier side of the scale has the differently weighted ball because the lighter side could very well have it too.... im sorry but you are wrong....
TheSteezyG 11 months ago 3
@WaTuPMeTuBe21 What if the ball was supposed to be light?
baggedyman 10 months ago 19
@WaTuPMeTuBe21 what it the weird ball was light and not heavy then this wouldnt work
thegreyknight364 9 months ago
@WaTuPMeTuBe21 that doesnt tell you which if its heavier or lighter and ur method involves some luck.
The Answer:
1:Place 2 balls in each side
2:If balls r = replace those with the remaining 2 balls to get a difference
3:replace 1 ball with another and the weight either evens out or stays the same showing u what ball is different and if its lighter or heavier
(2:If balls arnt = then remove one from each side
3:if = then replace with 2 balls u just removed/if not = then replace 1 side w/ a ball)
Cuma9 9 months ago
@WaTuPMeTuBe21 knw u r upset of replies, jst tellin u the sol.
Divide in 3 groups A, B, C of 2 balls each.
Case 1: W1 -> A=B implies C has false ball. W2-> Definitely A=/=C (as C has false ball). W3-> the two balls of C. False ball = heavier or lighter depend on W2.
Case 2: W1 -> A=/=B ; W2 -> A=C implies B has false ball. W3-> two balls of B and false ball dependin on W1.
Case 3: W1-> A=/=B ; W2 -> A=/= C implies A has False Ball. W3 -> two balls of A and false ball depending on any W1,W2.
autmnleaf 9 months ago
@WaTuPMeTuBe21 You don't know if the different ball is heavier or lighter. You will have to use your third turn weighing the other set of three, using the technique you mentioned.
plexnoid 8 months ago
@WaTuPMeTuBe21 No. The third turn would be used to tell whether it is heavier or lighter (since you don't address that in your answer). Also, just because 2 are different weight doesn't make the heavier one different since the different one could also be lighter.
twilightknight123 8 months ago
@WaTuPMeTuBe21 nice solution, except for the obvious error of "what if the ball that was different if actually lighter?" then you are using the wrong set all together.
kradrol 8 months ago
@WaTuPMeTuBe21 but it says the ball could be heavier or lighter, so yours doesnt work if its lighter
Evanisawesome54321 8 months ago
@WaTuPMeTuBe21 xDxD LOL you're a moron. One is lighter or heavier. Thats not the way to solve it. Bwahahha.... What you're saying is take the heavier set aside and scale 2 of them? What if one of the balls is lighter and its in the other set? LMAO I cant belive 10 people thumbed you up.. Im starting to lose hope in humanity xDXDXD
WeAreChuckNorris 7 months ago
@WaTuPMeTuBe21 one can be lighter as well...
YewTo0b 7 months ago
@WaTuPMeTuBe21 what if the ball was actualy lighter so u measureed the wrong ones?
NastyMutation 7 months ago