Steady I Really Like This Video How the range of a projectile is affected by launch angle (all trajectories have the same initial speed). For other physics animations like this one
To me this is incorrect. I was doing research for my science project on projectile angles using the same angles. I used a PVC pipe paintball launcher. I did 3 shots for each angle and I found that 30 degrees shot at least 40 ft farther than the 45 degree shots. I pumped each shot 35 psi and got for 30 degrees 107 ft, 118 ft, 116 ft. For 45 degrees I got 39 ft, 38 ft, and 40 ft. I have proven you all wrong. All the websites say 45 degrees is farthest. I cant explain my data though. Help?
@kickbutthentication Saying, "I have proven you all wrong" makes no one want to help you. Your data is skewed. 45 degrees should not have 1/3 of the distance of 30 degrees. Your machine sucks I'd say.
where Rx is range of x, u is initial resultant speed, theta is angle wrt horizontal, g is gravitational constant with is 9.81. Therefore range of projectile projected at angles of 15 and 75 are the same as sin30=sin150. Same for angles 30 and 60 where sin60=sin120.
Steady I Really Like This Video How the range of a projectile is affected by launch angle (all trajectories have the same initial speed). For other physics animations like this one
Mjhond 1 month ago
you can watch a program on my channel that also do projectile motion ideally. its a Windows program that you can download from softpedia
jensons88 4 months ago
huh!...interesting
BLTwithCHEESE 8 months ago
To me this is incorrect. I was doing research for my science project on projectile angles using the same angles. I used a PVC pipe paintball launcher. I did 3 shots for each angle and I found that 30 degrees shot at least 40 ft farther than the 45 degree shots. I pumped each shot 35 psi and got for 30 degrees 107 ft, 118 ft, 116 ft. For 45 degrees I got 39 ft, 38 ft, and 40 ft. I have proven you all wrong. All the websites say 45 degrees is farthest. I cant explain my data though. Help?
kickbutthentication 1 year ago
@kickbutthentication Saying, "I have proven you all wrong" makes no one want to help you. Your data is skewed. 45 degrees should not have 1/3 of the distance of 30 degrees. Your machine sucks I'd say.
Alahandrino 10 months ago
Q apology Oie program I can develop something similar to estho is for a physics project
vIcEntOtTy 1 year ago
Rx = (u^2 sin2theta)/g
where Rx is range of x, u is initial resultant speed, theta is angle wrt horizontal, g is gravitational constant with is 9.81. Therefore range of projectile projected at angles of 15 and 75 are the same as sin30=sin150. Same for angles 30 and 60 where sin60=sin120.
Silverix 3 years ago
Is this an ideal situation without any air resistance?
med1367 3 years ago 6
Yes, it is.
PelletierPhysics 3 years ago 4