why would you post this video? Anyone who took PHY I knows this (or in your case PHY 2130/2131 at WSU). You are a "pre-mathematics" major according to university records.
This isn't presented in PHY 2130. I believe that is an Algebra-based physics course. This isn't presented in PHY 2170, the Calculus based physics course either. Special relativity isn't typically introduced in any detail until modern physics. The Lorentz transformations aren't typically shown in the hyperbolic trigonometric format in that course either.
shit dude - you do much better math and weights than me!!!
Ive forgotten most of my physics degree but I seem to remember Lorentz Transformations in Riemannian geometry as a lead in to general relativity ...or not.
You demonstrate strength and intelligence are not mutually exclusive!
Thanks for the reply. I understand the derivations once you define sinh/cosh = v/c, and I understand the trig stuff. What I'm just wondering is why sinh / cosh is defined to be v / c.
The Lorentz transformations are really just hyperbolic rotations. They have properties commensurate with regular Euclidean rotations.
One invariance of Lorentz transformations is:
x^2-c^2t^2=x'^2-c^2t'^2. Hyperbolic trig has the identity that cosh^2-sinh^2=1 (as opposed to cos^2+sin^2=1)
The invariance of x^2-c^2t^2 follows from that identity. The key is that time and space are given the same units, with t replaced by ct. There is then a relation called "rapidity" that is defined by
How do you know that tanh = sinh/cosh = v/c? Is this just some property of 3D motion?
I understand from some googling that it arises from rapidity I guess, but I'm not up to speed on relativity (no pun intended, hah...). Is there a physical interpretation?
Ur that guy that benches a 2 plates and u can do geometry. Boss
lightbulbs95 5 months ago
Algebra for morons. I want some visualisation of the invariance of hyperbolae
TheNatureOfMonkey 6 months ago
I like it , good
xxjhones 7 months ago
wait how is this hyperbolic geometry? you are just using hyperbolic trig functions. You never even mention the hyperbolic plane.
DarthPickley 8 months ago
nice vid (well explained)
berserker098 1 year ago
can u calc how much ballhair my scrotum got ?
thank you , baawweee sheeevvvffaaa
murtadha12345678910 2 years ago
I'm going to make a video about that. Thanks!
matmania1 2 years ago
what planet are you from ?ARE YOU SUPERMAN ?
thedoors360 2 years ago
still homenbrewing that tren? Megadosing idoit.
justinklucko 2 years ago
Someone's bitter.
Derek78787878 2 years ago
why would you post this video? Anyone who took PHY I knows this (or in your case PHY 2130/2131 at WSU). You are a "pre-mathematics" major according to university records.
justinklucko 2 years ago
What about the people that haven't taken "PHY?"
This isn't presented in PHY 2130. I believe that is an Algebra-based physics course. This isn't presented in PHY 2170, the Calculus based physics course either. Special relativity isn't typically introduced in any detail until modern physics. The Lorentz transformations aren't typically shown in the hyperbolic trigonometric format in that course either.
troponinnutrition 2 years ago
You just cemented your place as my idol for all things besides med school.
jonnosferatu 2 years ago
Good luck in med school if you're going that route. I have a huge respect for what doctors go through to get that MD!
troponinnutrition 2 years ago
shit dude - you do much better math and weights than me!!!
Ive forgotten most of my physics degree but I seem to remember Lorentz Transformations in Riemannian geometry as a lead in to general relativity ...or not.
You demonstrate strength and intelligence are not mutually exclusive!
xmlisnotaprotocol 2 years ago
Thanks for the reply. I understand the derivations once you define sinh/cosh = v/c, and I understand the trig stuff. What I'm just wondering is why sinh / cosh is defined to be v / c.
Schwarzalbenheimen 2 years ago
The Lorentz transformations are really just hyperbolic rotations. They have properties commensurate with regular Euclidean rotations.
One invariance of Lorentz transformations is:
x^2-c^2t^2=x'^2-c^2t'^2. Hyperbolic trig has the identity that cosh^2-sinh^2=1 (as opposed to cos^2+sin^2=1)
The invariance of x^2-c^2t^2 follows from that identity. The key is that time and space are given the same units, with t replaced by ct. There is then a relation called "rapidity" that is defined by
troponinnutrition 2 years ago
hyperbolic angle = arctanh(v/c), or with rapidity as r,
v = c tanh(r/c)
troponinnutrition 2 years ago
How do you know that tanh = sinh/cosh = v/c? Is this just some property of 3D motion?
I understand from some googling that it arises from rapidity I guess, but I'm not up to speed on relativity (no pun intended, hah...). Is there a physical interpretation?
Schwarzalbenheimen 2 years ago
why are there so many weightliftig videos in related vids?
Muvlonion 2 years ago
Because he's freakishly strong, too.
Ever seen the movie TWINS, starring Arnold Schwarznegger and Danny Devito?
This guy is the Arnold character.
bio2020 2 years ago
That squat was too high.
Ooops, wrong video.
84cm84 3 years ago 8
haha!
troponinnutrition 3 years ago
this may be the best comment i've ever seen on youtube... well done sir.... well done.
rolls324 2 years ago
you're too awesome man
ZyphonZest 3 years ago
You are an ideal human being. Marry me?
Melatinini 3 years ago
Well you have deffinately blown the big meathead with no brains stigma out of the water lol. Good Job!!
Gabe7g 3 years ago 6
oh yeah....i get it....lol
RyanLVMetal88 3 years ago
i see a log there!!!
bigtonutz 3 years ago
and e to the zero= 1 hehe
bigtonutz 3 years ago
Physics II material
DonnieDarko727 3 years ago