Integration Trick

[nickrohn93]

thanks.

[MultiKnull]

Why my brain not understand anything? :(

[Pretoriafly]

Meanwhile, I'm in love with this music. <3

[atreyyu1]

Sadly arcsin(sin(x)) is not equal to x. Fail!

[supermiedos]

@atreyyu1 i'm curious, why not? I always tought it was :/. Is it because of the restricted values?

[atreyyu1]

@supermiedos Yes, by the standard definition of arcsin, arcsin(sin(x))=x is true only for [-pi/2;pi/2].

[Marcuzzorox]

@atreyyu1 for restricted values it is!

[d4rk4ng3lk]

this is wrong!!!!!!!!!!!!!!!!



[n7darren]

Wow thats something so simple yet I would never have thought of applying it for integration..

[ace0415]

WOW never thought of that. I thought that "pi/2 - x" trick was only useful back in the pre calc days

[intellectable]

This is false.

The "WOLF" gets a far more complex answer!

( wolframalpha(dot)com )

How does:

arcsin( sin( (pi/2 - x) ) ) goto --> (pi/2 - x) ?

How does sin(x) "cancel out" with arcsin(x) ?

What "Ultra Violet Voo du" are you doing to get this "Rigor-less" answer?

Note: this is way good professors spell out the Arcsin() Fn.

[icanhasurvideos]

@intellectable

think of arcsin(u) as the angle whose sine is u. If u is sin(x), then arcsin(u) is the angle whose sine is sin(x), which is, of course, x. That's how the expression appears to"cancel out."

[intellectable]

@icanhasurvideos

Ahh, inverses. Thanks for correcting me.

i.imgur.com/396M1(dot)jpg

[sjsawyer]

mind = blown

[ra339801]

fag!



[chungzheng]

can any one pls explain why cosx equals sin(π over 2  minus x ) ?

[Riflehound]

@chungzheng

it's pretty much shifting the graph of a sinx graph to make it a cosx graph because the graphs of a cosx and sinx look the same except on is shifted over pi/2 units

[intellectable]

@chungzheng Cos is just a phase shifted (by 90 degrees or pi/2) version of sin.

[Heytrini5]

what's up with the sad music?

[urdream8]

please I need an urgent help

did any one know how to integrate EXP[ x^4 + x ] 

I need it in my programm pleaaaaaaaaaaaassssssssssse help

[CarefreeSince1905]

@urdream8 substitute u=x^4 + x so that dx = du/4x^3 + 1 and the integral = [EXP(x^4 + x)]/[4x^3 + 1]

[PeterROwen]

This takes me back 50 years. Wonderful? You bet! Keep up the good work.

[pollardrho06]

@PeterROwen Thanks a lot. Keep watching.

[Yu2Kal]

This really great, I don't usually use trig identities much when integrating, or differentiating

[mrwalrus128]

then u fail at basic calculus

[WieldThyGuitar]

Hah, nice! lol

[pollardrho06]

@WieldThyGuitar Thanks a lot. Keep watching.

[pollardrho06]

@Yu2Kal Thanks a lot. Keep watching.

[JakeBartlam]

thanks for the help

[pollardrho06]

@JakeBartlam Thanks a lot. Keep watching.

[anhegh]

@pollardrho06 can you tell me where could i find the basic fomulae for integral calculus

[dmceye]

great ! i already forgot all this

[pollardrho06]

No problem. This is exactly why I post these videos. Math should live on forever... :-)

[1990sourav]

keep the good work up bro

[pollardrho06]

Thanks man.