Now it's 2012.... What the deal today... Does anyone on youtube have one of these that work>? Seem there are many ways to wire a motor to run but what about the main goal of over-unity?
My dear rivizal you i have written sometimes because i have tried to do what you do with the 2 motors bambas i echo without results with an engine of 1hp and one half cv but we have no information of connection we modify the 1/2hp with magnets the rotor working to 127vca with 3400rpm but i do not have the power to hook the that of 1hp that advises us greetings atte jose pge kings mexico
un pregunta si me puede ayudar como conecta usted los capacitares para bajar el consumo quiero hacerlo en 2 motores de trabajo 1 de 1/2 hp que consume 7 amperios y el otro que es de 1hp que consume 13 amperios bajarlos ha un 70 o 80% seria posible me podría ayudar gracias atte jose guadape reyes mi correo es ilumina33@hotmail.com saludos
un pregunta si me puede ayudar como conecta usted los capacitares para bajar el consumo quiero hacerlo en 2 motores de trabajo 1 de 1/2 hp que consume 7 amperios y el otro que es de 1hp que consume 13 amperios bajarlos ha un 70 o 80% seria posible me podría ayudar gracias
can somone please tell me how to connect the caps in to the generator. I have 1.5kw 3phase motor and a 5hp briggs and i want to build a generator out of it. The output can be in 3 or 1 phase it doesnt matter. THANKS sorry for bad english :(
You can do anything you like, you will not be able to get out more power than you put in, it is, impossible and against the laws of physics. Remember, it is no good multiplying current by volts and thinking that this gives you watts as it does not, as you are not taking PF into account. This means that you could have say 100V and 10 amps, but this does not mean that you have 1000W as you might not have the 100v at the same time as the 10 amps, they will occur at different parts of the AC cycle.
don't let anyone tell you find it yourself I know overunity is a realty keep exp. and be carefull those high voltage moters can be julting esptly 400+v. you just hit a right combo of moters.
Maximum output from an alternator being driven by a 1300w motor would be around 850w assuming the motor is not being pushed of sync by the load being applied.
any virtual or apparent power has miliseconds of potential as the load overcomes the inertia and drags the system down.
It is not possible to get more power out of a system than is put.
Hi all, what Rev ius doig is creating VARS or circulating current, what we need to do is transform it into usable WATTS. ATM it is reactive power, so cannot be series loaded, as falls out of resonance. The RV way to extract this into usable watts is profiled on the RV document on the panacea university site. Thanks Rev, you are getting there!
Dear Revizal For AC signals Power = V x I x Cos(Phi) So you need to present the Cos(Phi) of the system. P = V x I is for DC!! Please try to use Wattmeter! Thanks.
what do you mean by circulating current? how is the ammeter connected when measuring the alt. side? If the alternator is not connected to a load how can you measure current?
This current flows at exiter capacitor on alternator side. The current virtually circulate at that capacitor without the load. I could connect a load to at this capacitor to get real power output.
i beleive in what you state but i also beleive in proof of concept being exactly that.... PROOF!
usable power would be best shown with loop and excess power running either a light or another motor.preferable another motor so you can guage different anomalies.
love what you doing here. i have been thinking about it since i was 5 yrs old... cheers
@revizal Sorry but I think you are wrong, that power output you have is reactive power, not active, that´s not real power, is only current circulating without delivering any work.
Now it's 2012.... What the deal today... Does anyone on youtube have one of these that work>? Seem there are many ways to wire a motor to run but what about the main goal of over-unity?
JAUFOwitness 1 month ago
1:39 fast forward so you wont get bored
LUCKY4908 9 months ago
My dear rivizal you i have written sometimes because i have tried to do what you do with the 2 motors bambas i echo without results with an engine of 1hp and one half cv but we have no information of connection we modify the 1/2hp with magnets the rotor working to 127vca with 3400rpm but i do not have the power to hook the that of 1hp that advises us greetings atte jose pge kings mexico
Babylon 9
regiomontano50 11 months ago
This has been flagged as spam show
un pregunta si me puede ayudar como conecta usted los capacitares para bajar el consumo quiero hacerlo en 2 motores de trabajo 1 de 1/2 hp que consume 7 amperios y el otro que es de 1hp que consume 13 amperios bajarlos ha un 70 o 80% seria posible me podría ayudar gracias atte jose guadape reyes mi correo es ilumina33@hotmail.com saludos
regiomontano50 1 year ago
un pregunta si me puede ayudar como conecta usted los capacitares para bajar el consumo quiero hacerlo en 2 motores de trabajo 1 de 1/2 hp que consume 7 amperios y el otro que es de 1hp que consume 13 amperios bajarlos ha un 70 o 80% seria posible me podría ayudar gracias
regiomontano50 1 year ago
What is meant by "Circulating" output?
TheTruthPusher 1 year ago
Wow.........Does that mean that you just can hook the one to another and run it as a Free Energi Device....?
I hope so....
GOOD LUCK, and please keep it up...:-)
Ebdan88 1 year ago
can somone please tell me how to connect the caps in to the generator. I have 1.5kw 3phase motor and a 5hp briggs and i want to build a generator out of it. The output can be in 3 or 1 phase it doesnt matter. THANKS sorry for bad english :(
basedrum1000 1 year ago
Did a cap blow up in your face yet
LottsaLasagna 1 year ago
You can do anything you like, you will not be able to get out more power than you put in, it is, impossible and against the laws of physics. Remember, it is no good multiplying current by volts and thinking that this gives you watts as it does not, as you are not taking PF into account. This means that you could have say 100V and 10 amps, but this does not mean that you have 1000W as you might not have the 100v at the same time as the 10 amps, they will occur at different parts of the AC cycle.
caerleon87 1 year ago 2
Your calculations are wrong. Your power output will be less than power input.
Violation of Physics is against the law.
kahvac 1 year ago 3
amazing
TheIronStark 1 year ago
i'm going to share some # 36vdc moterdriving a 48or60v motor makes output than input more high the rating higher the output
MrJetjoe 2 years ago
don't let anyone tell you find it yourself I know overunity is a realty keep exp. and be carefull those high voltage moters can be julting esptly 400+v. you just hit a right combo of moters.
MrJetjoe 2 years ago
...can you calculate us cos(PI)... ;)
jm41637 2 years ago
Hi
Maximum output from an alternator being driven by a 1300w motor would be around 850w assuming the motor is not being pushed of sync by the load being applied.
any virtual or apparent power has miliseconds of potential as the load overcomes the inertia and drags the system down.
It is not possible to get more power out of a system than is put.
Ecoenergy 2 years ago
The rotoverter concept begs to differ.
LoneOarman 2 years ago
50 Hz motor runs on 60 Hz home grid.
revizal 2 years ago
were are those motors from???
chone7 3 years ago
Hi all, what Rev ius doig is creating VARS or circulating current, what we need to do is transform it into usable WATTS. ATM it is reactive power, so cannot be series loaded, as falls out of resonance. The RV way to extract this into usable watts is profiled on the RV document on the panacea university site. Thanks Rev, you are getting there!
ashtweth 3 years ago
Thanks Ash. This above is the one that assumed PF = 1 (like DC). I hope i will able to use this apparent power to the real power with PF near to 1.
revizal 3 years ago
Dear Revizal For AC signals Power = V x I x Cos(Phi) So you need to present the Cos(Phi) of the system. P = V x I is for DC!! Please try to use Wattmeter! Thanks.
samedsoft 3 years ago 4
Measuring amps and volts is not sufficient to calculate your powers. The phase between volt and amps matters in this case.
robbiehobbie47 3 years ago 5
what do you mean by circulating current? how is the ammeter connected when measuring the alt. side? If the alternator is not connected to a load how can you measure current?
d3adp001 3 years ago
This current flows at exiter capacitor on alternator side. The current virtually circulate at that capacitor without the load. I could connect a load to at this capacitor to get real power output.
revizal 3 years ago
now that I would love to see. If you can show 6.1amps @ 400v worth of light bulbs running, well then you got me sold. But I am a hard sell.
d3adp001 3 years ago
i agree
i beleive in what you state but i also beleive in proof of concept being exactly that.... PROOF!
usable power would be best shown with loop and excess power running either a light or another motor.preferable another motor so you can guage different anomalies.
love what you doing here. i have been thinking about it since i was 5 yrs old... cheers
kissmyhho 3 years ago
@revizal Sorry but I think you are wrong, that power output you have is reactive power, not active, that´s not real power, is only current circulating without delivering any work.
martinexex 2 months ago
Are you allowed to sell electricity back to your power company?
jesslessthemess 3 years ago